Concept explainers
(a)
Interpretation:
Quantity of heat required to heat
Concept Introduction:
To increase the temperature of a solid we need to supply heat energy. Specific heat plays crucial role in increase of temperature of a substance.
(b)
Interpretation:
How much heat energy will be required to melt
Concept Introduction:
Melting point is the temperature at which a solid starts melting to liquid and until all the solid is not melted temperature remains same.
(c)
Interpretation:
How much heat energy will be required to vaporize
Concept Introduction:
Boiling point is the temperature at which a liquid starts boiling to vapor and until all the liquid is not boiled off temperature remains same.
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EBK INTRODUCTORY CHEMISTRY
- The lattice energy of LiF is 1023 kJ/mol, and the Li—F distance is 200.8 pm. NaF crystallizes in the same structure as LiF but with a Na—F distance of 231 pm. Which of the following values most closely approximates the lattice energy of NaF: 510, 890, 1023, 1175, or 4090 kJ/mol? Explain your choice.arrow_forwardFrom the molar heats of formation in Appendix G, determine how much heat is required to evaporate one mole of water: H2O(l)H2O(g)arrow_forwardAt 20. C the vapor pressure of white phosphorus is 0.0254 mmHg; at 40. C it is 0.133 mmHg. Use the Clausius-Clapeyron equation to estimate the heat of sublimation (J/mol) of white phosphorus.arrow_forward
- Rank the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest boiling point, choose 2 next to the substance with the next highest boiling point, and so on. substance B C D chemical symbol, chemical formula or Lewis structure HI H H ** HICIO-C-H со Cao I I H H H II HICICIOIH I | | H H boiling point (Choose one) (Choose one) (Choose one) • (Choose one)arrow_forwardSH vaporization = 2300 J/g SH fusion of water = 300 J/g SH ice = 2.0 J/g K SH water = 4.0 J/g K SH steam = 2.0 J/g K What is the H in kilojoules (kJ)of 50 g water at 253 K becoming this matter at 253°C according to the specific heats above? a) -167 b) -115 c) -55 d) 55 e) 167arrow_forwardUse the following information on Na to determine the total amount of heat required to convert 150.0 g of solid Na at 48.0°C into gaseous Na at 883°C.Melting Point = 98.0°CBoiling Point = 883°C Molar Heat Capacities:C = 23.7 J/mol °CC =37.5 J/mol °CΔH = 2.64 kJ/molΔH = 97.9 kJ/mol Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a. 855 kJ b. 192 kJ c. 149 kJ d. 225 kJarrow_forward
- 1. An 800g aluminium block cools from 85°C to 30 °C. Calculate the heat capacity, C, of the aluminium block. 2. Construct an energy cycle diagram for potassium fluoride. 3. Determine the lattice energy of potassium fluoride. Enthalpy of atomization of potassium = +89.2kj/mol Enthalpy of atomization of fluorine = +79kj/mol 1st ionization energy of pottasium = +418kj/mol Electron affinity of fluorine = -328kj/mol Enthalpy of formation of potassium fluoride = -561.7kj/molarrow_forwardSubstance A has the following properties.mp at 1 atm:-20.°C ;bp at 1 atm:85°C ;H(fus)180. J/g ;H(vap):500. J/g ;c(solid):1.0 J/g°C ;c(liquid):2.5 J/g°C ;c(gas):0.5 J/g At 1 atm, a 25-g sample of A is heated from -40.°C to 100.°C ata constant rate of 450. J/min. (a) How many minutes does it take to heat the sample to its melting point? (b) How many minutes does it take to melt the sample? (c) Perform any other necessary calculations, and draw a curve of temperature vs. time for the en-tire heating processarrow_forwardCalculate the lattice energy of sodium fluoride; NaF in kJ/mol from the following data: lonization energy of Na: + 496 kJ/mol Electron affinity of F: - 328 kJ/mol Energy to vaporize Na: + 108 kJ/mol F2 bond energy: + 160 kJ/mol The energy of reaction: Na(s) + F2(g)- -> NaF(s); AH xn = -575 kJ a) - 851 b) -931 c) - 1011 d) + 931arrow_forward
- Consider the data in the table. Compound Melting point (°C) AH (kJ/mol) Boiling point (°C) AHap (kJ/mol) HF -83.11 4.577 19.54 25.18 HCI -114.3 1.991 -84.9 17.53 HBr -86.96 2.406 -67.0 19.27 HI -50.91 2.871 -35.38 21.16 Using the data in the table, calculate ASt and AS for HCI. AStn 12.53 J/(K mol) AS. = 93.12 J/(K mol) Determine the entropy change when 3.50 mol HCI(1) freezes at atmospheric pressure. AS = J/K TOOLSarrow_forwardhow much vaporization energy does 185.65g of FeO release according to 4FeO + O2 -> 2Fe2O3 FeO= 71.844 g/mol H vaporization = -560 kJ/molarrow_forwardcalculate the lattice energy of NaCl: Na(s)----> Na(g) = 109kj Cl2--->2Cl(g) = 243kj Na(g)----> Na+(g)+ e- = 496kJ Cl(g)+e------>Cl-(g) = -349kJ Na(s) + 1/2Cl2(g)----->NaCl(s) = -411kJarrow_forward
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