Concept explainers
Derive the relation
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Vector Mechanics For Engineers
- 10. The angular momentum of a particle about point A in a reference frame is defined as r dot mv where r is the radius vector from point A to the particle position, m is the particle mass, and v is the particle velocity. True Falsearrow_forwardCollision at an Angle To apply conservation of linear momentum in an inelastic collision. Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at a speed 2v, while the second was traveling in a southeastern direction at an angle ϕ with respect to the east-west direction and at a speed v. After the collision, the two-car system travels in a northeastern direction at an angle θ with respect to the north-south direction and at a speed v final. Find v final, the speed of the joined cars after the collision. Express your answer in terms of v and ϕ.arrow_forwardCollision at an Angle To apply conservation of linear momentum in an inelastic collision. Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at a speed 2v, while the second was traveling in a southeastern direction at an angle ϕ with respect to the east-west direction and at a speed v. After the collision, the two-car system travels in a northeastern direction at an angle θ with respect to the north-south direction and at a speed v final. What is the angle θ (with respect to north) made by the velocity vector of the two cars after the collision? Express your answer in terms of ϕ. Your answer should contain an inverse trigonometric function.arrow_forward
- An object of mass m1 = 2.0 kg moving at 1.8 m/s collides with an object of mass m2 = 1.4 kg moving from the opposite direction with a speed of 1.5 m/s. After collision, m1 continues to go in the same direction with a speed of 0.3. What will be the speed of m2 after the collision? A 9.0 bullet traveling with a speed of 100 m/s gets embedded in a wooden block of mass 1 kg. The wooden block is hanging like a pendulum as shown in the figure below. To what height h will the wooden block rise, when it comes to a momentary stop. (Hint: do this as a two step problem, g = 9.8 m/s2).arrow_forwardThe spring constants are k1 = 140N / m, k2 = 240N / m and the unstretched lengths of the springs are 0.3 m. If the 6 kg ring is released from rest from point A, calculate its velocity when it reaches point B. According to the given datum line, the total potential energy (Ve) at point A is A = 1116.86 J and the total elastic potential energy (Ve) at point B is B = 370.8 J. Neglect the dimensions of the bracelet. (L1 = 0.90 m, L2 = 1.80 m, h1 = 1.20 m and h2 = 2.40 m)arrow_forwardA 100 kg vehicle initially travels clockwise in a circular path with a radius of 10 m at a speed of 5 m/s. If a counterclockwise couple moment of 100 Nm is applied for 10 s, and the vehicle continues to travel on a circular path at 5 m/s, then the circular path radius must drop to from 10 m to 8 m. True Falsearrow_forward
- Part A: What is the period of the spacecraft's orbit? T=___s Part B: Using conservation of angular momentum, find the ratio of the spacecraft's speed at perigee to its speed at apogee. (Vperigee)/(Vapogee)=___ Part C: Using conservation of energy, find the speed at perigee and the speed at apogee. Vperigee,Vapogee=___m/s Part D: It is necessary to have the spacecraft escape from the earth completely. If the spacecraft's rockets are fired at perigee, by how much would the speed have to be increased to achieve this? delta(perigee)=___m/s Part E: What if the rockets were fired at apogee? delta(apogee)=___m/s Part F: Which point in the orbit is more efficient to use and why?arrow_forwardA truck of mass 50 tonnes is moving at 85kmph. It collides with a second truck of mass 30 tonnes moving in the opposite direction at 60 kmph. After the collision the second truck has changed its speed to 2100 cm/s in the opposite direction as before the collision. Find: (i) the velocity of the first truck after the collision (ii) the coefficient of restitution. 1.The velocity of the first truck after the collision in (m/s) is 2.The Coefficient of Restitution isarrow_forwardTo use the principle of work and energy to determine characteristics of a system of particles, including final velocities and positions. The two blocks shown have masses of mA = 56 kg and mB = 74 kg . The coefficient of kinetic friction between block A and the inclined plane is μk = 0.15 . The angle of the inclined plane is given by θ = 40 ∘ . Neglect the weight of the rope and pulley. Determine the magnitude of the normal force acting on block A, NA If both blocks are released from rest, determine the velocity of block B when it has moved through a distance of s = 2.00 m. If both blocks are released from rest, determine how far block A has moved up the incline when the velocity of block B is (vB)2 = 6.25 m/s.arrow_forward
- A vehicle of mass 45 tonnes is moving at 85kmph. It collides with a second vehicle of mass 30 tonnes moving in the opposite direction at 50 kmph. After the collision the second vehicle has changed its speed to 2400 cm/s in the opposite direction as before the collision. Find: (i) the velocity of the first vehicle after the collision (ii) the coefficient of restitution. 1.The velocity of the first vehicle after the collision in (m/s) is 2.The Coefficient of Restitution isarrow_forwardThe 3 kg object A and the 5 kg object B undergo oblique impact as shown in Figure P5. The coefficient of restitution between the objects is 0.6. The magnitude of the velocity of A is 10 m/s, while the magnitude of the velocity of B is 5 m/s just before impact. The angle theta =36.9?. What is the magnitude of the velocity of each particle after impact?arrow_forwardA vehicle of mass 65 tonnes is moving at 85kmph. It collides with a second vehicle of mass 30 tonnes moving in the opposite direction at 40 kmph. After the collision the second vehicle has changed its speed to 2100 cm/s in the opposite direction as before the collision. Find: (i) the velocity of the first vehicle after the collision (ii) the coefficient of restitution.arrow_forward
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