   Chapter 14.2, Problem 42E ### Algebra and Trigonometry (MindTap ...

4th Edition
James Stewart + 2 others
ISBN: 9781305071742

#### Solutions

Chapter
Section ### Algebra and Trigonometry (MindTap ...

4th Edition
James Stewart + 2 others
ISBN: 9781305071742
Textbook Problem

# Bridge Hands What is the probability that a 13 -card bridge hand consists of all cards from the same suit?

To determine

To find:

The probability that a 13-card bridge hand consists of all cards from the same suit.

Explanation

Approach:

Bridge Hands: The cards held in a game of bridge.

Combinations: Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

Formula used:

Cnr=n!r!(nr)!...(1)

Here, n is the total number of items and r is the number of items being chosen at a time.

If E is the event in a sample space S, then the probability of E is

P(E)=n(E)n(S)...(2)

Calculation:

There are 52 cards in a deck. So,

n=52

So, in 13-card bridge hand, the number of possible outcomes is,

n(S)=C5213

Substitute 52 for n and 13 for r in equation(1).

C5213=52!13!(5213)!=52!13!39!

Now,

n(S)=52!13!39!

There are four suits and each suit has 13 cards.

If 13-card bridge hand consists of all cards from the same suit then the number of possible outcomes is,

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 