Evaluating a Double
In Exercises 9–-16, evaluate the double integral
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Chapter 14 Solutions
Calculus: Early Transcendental Functions
- Use polar coordinates to set up and evaluate the double integral ∫R∫ f(x, y) dA. f(x, y) = arctan( y /x) R: x2 + y2 ≥ 1, x2 + y2 ≤ 4, 0 ≤ y ≤ xarrow_forwardM3. Subject :- Advance math The surface surrounding the region bounded by the x2 + y2 = 4 cylinder and the z = 0 and z = 3 planes is S, the normal directed outward. Accordingly, (x, y, z) = x i + y j + z k using the Divergens theorem to calculate the integral of F. n dSarrow_forward(a) Sketch the region of integration R in the xy - plane and sketch the region G in the uv - plane using the coordinate transformation x = 2u and y = 2u + 4v.arrow_forward
- 1a)Evaluate the double integral over the rectangular region R: ∫∫R 4xy^3 dA;R=(x,y) :−10≤ x ≤10,−8 ≤ y ≤ 8 b)Evaluate ∬R 1/ (x^2+y^2+1) dA where R is region in the first quadrant bounded byy=0, y=x and x^2+y^2=121arrow_forwardConsider the double integral ∫ ∫ D (x^2 + y^2 ) dA, where D is the triangular region with vertices (0, 0), (0, 1), and (1, 2). A. Describe D as a vertically simple region and express the double integral as an iterated integral. B. Describe D as a horizontally simple region and express the double integral as an iterated integral. C. Evaluate the iterated integral found either in part A or in part B.arrow_forwardEvaluate the given DOUBLE integral by changing to polar coordinates. The double integral is: sqrt (16-x2-y2) dA where R = (x, y) | x2 + y2 ≤ 16, x ≥ 0.arrow_forward
- Using Stokes’ Theorem to evaluate a surface integral Evaluate∫∫S (∇ x F) # n dS, where F = -y i + x j + z k, in the following cases.a. S is the part of the paraboloid z = 4 - x2 - 3y2 that lies within the paraboloid z = 3x2 + y2 (the blue surface as shown). Assume n pointsin the upward direction on S.b. S is the part of the paraboloid z = 3x2 + y2 that lies within the paraboloidz = 4 - x2 - 3y2, with n pointing in the upward direction on S.c. S is the surface in part (b), but n pointing in the downward direction on S.arrow_forwardEvaluate the line integral using Green's Theorem and check the answer by evaluating it directly. ∮C4 y2dx+6 x2dy∮C4 y2dx+6 x2dy, where CC is the square with vertices (0,0)(0,0), (3,0)(3,0), (3,3)(3,3), and (0,3)(0,3) oriented counterclockwise. ∮C4 y2dx+6 x2dy=arrow_forwardSet-up the iterated double integral in rectangular coordinates equalto the volume of the solid in the first octant bounded above by the paraboloid z = 1−x2-y2, below by the plane z =3/4, and on the sides by the planes y = x and y = 0.arrow_forward
- Evaluate the line integral using Green's Theorem and check the answer by evaluating it directly. ∮C 3 y2 dx+3 x2 dy, where CC is the square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), and (0,2)(0,2) oriented counterclockwise.arrow_forwardEvaluating a Surface Integral. Evaluate ∫∫ f(x, y, z)dS, where S f(x,y,z)=√(x2+y2+z2), S:x2+y2 =9, 0⩽x⩽3, 0⩽y⩽3, 0⩽z⩽9.arrow_forwardEvaluate the double integral integral integral_(D) e^(−y^2) dA, {R = (x, y) | 0 ≤ y ≤ 3 , 0 ≤ x ≤ y}arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
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