Chapter 14.6, Problem 10TFS

To determine

The correct match of the statement, “The area of a rectangle is $568{\text{ ft}}^2$. The length is $26\text{ ft}$ greater than the width. Find the length and the width.” from the following options by translating it to an equation:

Option	Equation
A	$5x+25y=9.35,x+y=59$
B	$4^2+x^2=8^2$
C	$x\left(x+26\right)=568$
D	$8=x\cdot 24$
E	$\frac{75}{x}=\frac{105}{x+5}$
F	$\frac{75}{x}=\frac{105}{x+5}$
G	$2x+2\left(x+26\right)=568$
H	$x+3x+\left(x+3x-17\right)=180$
I	$x+3x+\left(3x-17\right)=180$
J	$0.05x+0.25y=9.35,x+y=59$
K	$8^2+8^2=x^2$
L	$x^2+{\left(x+26\right)}^2=568$
M	$x-5\%\cdot x=8568$
N	$\frac{1}{55}+\frac{1}{75}=\frac{1}{x}$
O	$x+5\%\cdot x=8568$