Traffic And Highway Engineering
5th Edition
ISBN: 9781133605157
Author: Garber, Nicholas J., Hoel, Lester A.
Publisher: Cengage Learning,
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Question
Chapter 15, Problem 13P
To determine
(a)
The intersection angle.
To determine
(b)
The radius of the curve.
To determine
(c)
The length of tangent.
To determine
(d)
The external distance.
To determine
(e)
The middle ordinate.
To determine
(f)
The length of long chord.
To determine
(g)
The length of the curve.
To determine
(h)
The station of the PC.
To determine
(i)
The station of the PT.
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QUESTION 2
Two tangents AB and BC intersect at an angle of 24°0'0". A curve is formed from point A to C. A point on the curve, D, is found along the curve near A. Point D is located 21.03 m from point B, and has a
perpendicular distance of 2.79 m from line AB.
a. Calculate the radius of the simple curve connecting the two tangents and passing point D
Answer: R=
m
b. Calculate the length of the chord connecting PC and point D
Answer: C =
m
Note: Unit has been provided after the blank space. No need to indicate units on your answer.
Use sexagesimal units for angle measurements.
The length of the common tangent of a compound curve is equal to 68.62 m. The common tangent makes an angle of 12° and 18°, respectively to the tangents of the compound curve. If the length
of the tangent of the first curve is equal to 41.02 m, determine:
a. radius of the second curve
Answer: R₂=
b. radius of the first curve
Answer: R₁=
c. the stationing of PT if PC is at 20+042.20
Answer: Sta PT=
m
m
QUESTION 2
The tangent thru the PC has a direction due to North; and the tangent through the PT has a bearing of N 50° E. It has a radius of 200 m.
Stationing of PC is 12+060.
a. Compute the tangent distance of the curve.
Answer: T=
b. Compute the long chord of the curve.
Answer: Lc =
m
m
c. A line is drawn from the center of the curve (at the central angle) and intersects the curve at point B. This line, when extended, makes an
angle of 62° with the tangent thru PC. What is the stationing of point B?
Answer: Sta. B =
Note: Unit has been provided after the blank space. No need to indicate units on your answer.
Chapter 15 Solutions
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- The tangent thru the PC has a direction due to North; and the tangent through the PT has a bearing of N 50° E. It has a radius of 200 m. Stationing of PC is 12+060. % a. Compute the tangent distance of the curve. Answer: T= [tangent] m b. Compute the long chord of the curve. Answer: Lc = [Lchord] m c. A line is drawn from the center of the curve (at the central angle) and intersects the curve at point B. This line, when extended, makes an angle of 62° with the tangent thru PC. What is the stationing of point B? Answer: Sta. B = [StaB]arrow_forwardThe common tangent of a compound curve has a length of 70 m. This common tangent makes an angle of 14° and 20° to the tangents of the compound curve respectively. If T1 = 40 m, determine: a. The radius of the second curve. b. The radius of the first curve. c. The station of PT if PC is at 29+999.99 Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.arrow_forwardQUESTION 2 The long chord from the PC to the PT of a compound curve is 300 m. A common tangent, from point A to B, has an angle of 12° with AV and 15° with BV. If the common tangent is parallel to the long chord, determine: a. the radius of the first curve Answer: R₁= b. the radius of the second curve Answer: R₂= c. the stationing of PT if PC is 10+204.30 Answer: Sta PT= m m Note: Unit has been provided after the blank space. No need to indicate units on your answer.arrow_forward
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