Concept explainers
A 2.500-g sample of a mixture of sodium carbonate and sodium chloride is dissolved in 25.00 mL of 0.798 M HCl. Some acid remains after the treatment of the sample.
- a Write the net ionic equation for the complete reaction of sodium carbonate with hydrochloric acid
- b If 28.7 mL of 0.108 M NaOH were required to titrate the excess hydrochloric acid, how many moles of sodium carbonate were present in the original sample?
- c What is the percent composition of the original sample?
(a)
Interpretation:
The explanations for the given set of statements have to be given.
Concept introduction:
The percent composition of the given original sample can be calculated by using the following formula.
Answer to Problem 15.100QP
The complete reaction is
Explanation of Solution
The complete reaction of sodium carbonate with hydrochloric acid is
(b)
Interpretation:
The explanations for the given set of statements have to be given.
Concept introduction:
The percent composition of the given original sample can be calculated by using the following formula.
Answer to Problem 15.100QP
The number of moles of sodium carbonate present in the original sample is
Explanation of Solution
First we can determine the total number of moles of
Now, let’s find the number of moles of
We come over that, the number of moles of
Hence, the number of moles of sodium carbonate present in the original sample is
(c)
Interpretation:
The explanations for the given set of statements have to be given.
Concept introduction:
The percent composition of the given original sample can be calculated by using the following formula.
Answer to Problem 15.100QP
The percent composition of
The percent composition of
Explanation of Solution
To determine the percent composition, first determine the mass of
Now, the percent
Hence, the percent composition of
Hence, the percent composition of
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Chapter 15 Solutions
OWLv2 with Student Solutions Manual eBook for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 4 terms (24 months)
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