EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
9th Edition
ISBN: 8220103611718
Author: SOBHAN
Publisher: CENGAGE L
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Chapter 15, Problem 15.10P
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Sand is placed on a rock slope, as shown in Figure Q2.
(a) Show that sand will be stable (i.e., no sliding sliding) if
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Chapter 15 Solutions
EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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- A cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following. a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?arrow_forwardThe infinite sand slope shown in the figure is on theverge of sliding failure. The ground water tablecoincides with the ground surface. Unit weight of water % = 9.81kN/m² The value of the effective angle of internal friction (indegrees, up to one decimal place) of the sand is. 111 7sat = 21 kN/m²³arrow_forward120 KN 1.5 m 60 KN/m 60 KN/m 1.0 m A 3.0 m 3.0 m a. Determine the location of the maximum deflection using double integration. b. Determine the magnitude of the maximum deflection using double integration method using E = 200 x10^6 KPa and I = 1.440 x10^-5 m4arrow_forward
- 16.9 Use Taylor's method to determine the factor of safety of the slope shown in Figure P16.9. 1 Very stiff clay FIGURE P16.9 $ = 20 kPa 18 kN/m²arrow_forwardPlease answer (a)arrow_forward120 KN 50 KN/m 2.0 m 50 KN/m 2.0 m B A 4.0 m 4.0 m a. Determine the location of the maximum deflection using double integration. b. Determine the magnitude of the maximum deflection using double integration method using E = 200 x10^6 KPa and I = 1.440 x10^-5 m4arrow_forward
- A slope is shown in the figure below. If AC represents a trial failure plane, determine the factor of safety against sliding for the wedge ABC. Given: β= 570 , ϒ = 17.5 kN/m3 , φ’ = 13.50 , and c’ =27 kN/m2Please use the Culmann’s method B. Briefly Comment on how to analyze a slope and determine the factor of safety against overturning.arrow_forwardFor a railway track 7 m high embankment is required. The clay to be used for the embankment was found to have c = 20 kN/m2and unit weight = 19 kN/m3 Compute the critical maximum side slope angle for the embankment if a hard rocky stratum was found 3.5 m below the ground level. Assume ϕ for the clay equal to zero. The following values are given from Taylor's chart for depth factor D = 1.5 :arrow_forwardPlease solve with stepsarrow_forward
- 3. For the planar wedge shown below: 22 m Slip surface 39° 28° Calculate the factor of safety against plane failure assuming: p (degree) > (kN/m³) c (kPa) 55 2800 1850 c: cohesion of rock mass; y: unit weight of rock mass; p: friction angle of rock mass جیهان کاظیarrow_forwardThe figure below picturizes a rock slope containing a planar sliding surface and a vertical tension crack. The tension crack is partly-filled with water due to the water table intersecting the slope face where the sliding surface daylights on the face. The water pressures in the tension crack and on the sliding surface are approximated by the triangular force diagrams illustrated in the figure. The slope has been reinforced by a tensioned rock anchor. Assume that; A: the area of the sliding surface. TROT c: the cohesion of the sliding surface p: the internal friction angle of the sliding surface I yp: the dip of the sliding surface. YT: anchor installation angle from the horizon. hw: the height of water column in the tension crack. Yw: the unit weight of water W: the weight of the block V and U: the water forces acting in the tension crack, and on the sliding plane, respectively. So, by taking this geometrical, physical, and mechanical circumstances into the account, derive the…arrow_forwardA cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the stability factor?arrow_forward
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