EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
9th Edition
ISBN: 8220103611718
Author: SOBHAN
Publisher: CENGAGE L
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Chapter 15, Problem 15.3P
To determine
Find the factor of safety
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Answer is 1.35
Please answer (a)
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Chapter 15 Solutions
EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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- Question No. 16 A long slope is formed in a soil with shear strength parameters: c' = 0 and d' = 34°. A firm stratum lies below the slope and it is assumed that the water table may occasionally rise to the surface, with seepage taking place parallel to the slope. Use Ysat = 18 kN/m³ and Yw = 10 kN/m³. The maximum slope angle (in degrees) to ensure a factor of safety of 1.5, assuming a potential failure surface parallel to the slope, would bearrow_forwardPlease answer 15.8arrow_forwardB 20 ft Y=110 Ib/ft O= 20° c= 400 Ib/ft? 25° 50 A This question has three parts. For the given slope conditions (ABC) and failure surface (AC) shown in the figure: 1) Calculate the factor of safety against sliding. 2) Calculate the factor of safety if c = 0. 3) Calculate the factor of safety if the groundwater level rises to point A.arrow_forward
- 6.b. A granular soil has ysat = 20KN/m³, o = 30°. A slope has to be made of this soil. If a factor of safety of 1.2 needed against slope failure, determine the safe angle of the slope, i. when the slope is dry or submerged without seepage ii. If seepage occurs parallel to the slope with water table at a depth of 1.5m, what is the factor of safety available on a slope parallel to the ground surface at a depth of 4m? Assume a slope angle of 28°. %3Darrow_forwardGive me right solution.arrow_forwardExample 4.2 Along rectangular channel is 3m wide & carries water at the rate of 13m/sec. At a certain point there is an approach change in the slope from 1:60 to 1:600 , determine: a)whether the hyd. Jump will form? Solution Q = * R2/3 * S1/2 A n 3y1 1 (3y,)(: 13 0.015 3+ 2y1 Y1 = 0.79 m 1 3y1 13 = (3y2)G 3+2y2 0.015 Y2 = 1.82m 2 (13/3) 3 3 Ye = = 1.24 m 9.81 Y1 < Ycarrow_forwardFigure 15.47 shows an infinite slope with H = 9.14 m and the groundwater table coinciding with the ground surface. If there is seepage through the soil, determine the factor of safety against sliding along the plane AB. The soil properties are Gs = 2.7, e = 0.8, β = 16°, ϕ′ = 21°, and c′ = 59.8 kN/m2.arrow_forwardNonearrow_forwardA 45° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties Cu= 50 kN/m², qu=0° and y = 19 kN/m³ Determine the factor of safety. [Take area of wedge = 39 m²]arrow_forwardA 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.arrow_forwardThanks for the solution.arrow_forwardPlease solve with stepsarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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