EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
9th Edition
ISBN: 9781337517218
Author: SOBHAN
Publisher: VST
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Question
Chapter 15, Problem 15.18P
To determine
Find the maximum height of a slope.
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Students have asked these similar questions
Given an infinite slope with the following properties: γ = 17 kN/m3, H = 5 m, β = 34°, φ = 25° and c = 20 kPa.
a. Determine the normal stress.
b. Determine the shear stress.
c. Determine the factor of safety.
A 45 ° slope as shown in figure has
been excavated to a depth of 6 m in
a saturated clay having the following
properties:
C₁ = 50 kN/m² ₂ 0 = 0 and y = 19 kN/m²³
Determine the factor of safety.
[Take area of wedge
39 m²]
ok
3.4 m
f
2.65 m
6m
45°
90°
=
9m
Figure below gives details of an embankment to be made of cohesive soil with c, = 20 kPa. Unit
weight of soil is 19 kN/m³. For the trial circle shown, determine the factor of safety against failure.
The weight of the sliding sector is 329 kN acting at an eccentricity of 4.8 m from the centre of
rotation.
What would be the factor of safety if the shaded portion of the embankment were removed?
Assume no tension crack develops.
71°
R = 9 m
e = 4.8 m
3 m
1.5 m
1.1
3 m
VINIS
Chapter 15 Solutions
EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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- A cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following. a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?arrow_forwardA 30° slope has a height of 10 m as shown in the figure below. The soil in the slope has the following parameters c = 20 kPa, ϕ = 0°, γ = 18 kN/m . Calculate the factor of safety for the slip surface shown in the figure.arrow_forwardAn infinite slope of clay soil has a slope of 29 degrees. The soil has a specific gravity of 2.7 and a void ratio of 0.47. The soil has a depth of 5m over ledge rock measured vertically. Effective friction angle and soil cohesion are 14 degrees and 25kPa respectively. Assuming the ground water table is in the ground surface, determine the limiting depth of this soil, measured vertically over ledge rock. A 1.25m B 5.95m 3.67m D 6.88marrow_forward
- 4. A cut is to be made in a soil having γ = 18 kN/m3, c = 40 kPa, and φ = 15°. The cut slope makes an angle of 30°. a. If H = 6 m and θ = 15°, find the force that tend to cause sliding.b. Find the frictional force.c. Find the cohesive force.d. Find the factor of safety.e. For a factor of safety of 2.0, find the value of the critical angle along which the maximum developed cohesion occurs. f. Determine the depth of cut for a factor of safety of 2.0g. Determine the developed shear stress along the failure plane h. Determine the developed normal stress alongthe failure plane.arrow_forwardA 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay having strength parameters, c = 60 kN/m², p = 0, and y- 19 kN/m³. Determine the factor of safety for the trial failure surface shown in below figure using Swedish circle method. 8 m 40° 95⁰ R = 10.2 m 4m- W = 1050 kN THE Warrow_forward2. A cut slope is to be made as shown. The unit weight of soil is 18KN/cu.m and the angle of internal friction is 22°. The soil has cohesion of 30 Kpa. The cut slope makes an angle of 30° with the horizontal and the height is 12 m. If the failure plane is 15° from horizontal. Determine a. Frictional force along the failure plane b. Cohesive force along the failure plane Factor of safety against sliding B 24 m A trial failure plane 12 m 30 15° Carrow_forward
- A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.arrow_forwardA level site underlain by fully saturated clays is cut over a few days as shown in the figure below. The water table is located at the ground surface across the site. Determine the resisting moment in kN.m for the circular slip surface depicted in the Figure below shortly after excavation. Consider the soil wedge above the circular slip surface as a single free body, whose plane area is equal to 100 m2 and the centre of gravity of the soil wedge is given at Point C.arrow_forwardAn infinite slope of granular soil has a slope of 29 degrees. The soil has a dry unit weight of 18.02kN/m^3 and a saturated unit weight of 21.15kN/m^3. The soil has a depth of 5 meters over ledge rock measure vertically. Effective friction angle and soil cohesion are 14 degrees and 25 kPa, respectively. a) Compute the factor of safety considering no seepage. b) Compute the factor of safety considering full seepagearrow_forward
- A 10m deep slope of 40° is made in a saturated clay of unit weight 20kN/m3. The value of cohesion is given as 72 kN/m2 and the Taylor's stability coefficient is given as 0.18. Compute the factor of safety for the load.arrow_forwardFrom the figure shown the soil has a unit weight of 28.5 kN/m^3 and the undrained shear strength cu = 20 kN/m^2. The slope makes an angle 62 degrees with the horizontal. Assume a stability number m = 0.16761. Compute the stability factor. a. 6.78b. 6.7c. 5.99d. 5.012. Compute the maximum depth up to which the cut could be made. a. 5.18 mb. 4.97 mc. 4.20 md. 3.84 m3. Compute angle that the failure plane makes with the horizontal if BC is 9 m. a. 22.32 degreesb. 28.25 degreesc. 21.05 degreesd. 20.15 degreesarrow_forwardA cut slope of h= 7m was excavated in a saturated clay with a slope of angle beta = 45 degrees with the horizontal. The Previous explorations showed that a rock layer was located at a depth of 14 m. Given that, c = 60 kN/m² and unit weight = 17 kN / (m ^ 3) . Determine the factor of safety.arrow_forward
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