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MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, 9th Edition, [Instant Access], 2 terms (12 months)
9th Edition
ISBN: 9781305971257
Author: Braja M. Das; Khaled Sobhan
Publisher: Cengage Learning US
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Question
Chapter 15, Problem 15.30P
To determine
Find the factor of safety
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A slope is shown in the figure below. If AC represents a trial failure plane, determine the factor of safety against sliding for the wedge ABC. Given: β= 570 , ϒ = 17.5 kN/m3 , φ’ = 13.50 , and c’ =27 kN/m2Please use the Culmann’s method
B. Briefly Comment on how to analyze a slope and determine the factor of safety against overturning.
A 45° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties Cu= 50 kN/m², qu=0° and y = 19 kN/m³
Determine the factor of safety. [Take area of wedge = 39 m²]
Find slope at D in degrees using double integration method. Consider 250 mm x 400 mm (b x h) section and E = 120 GPa. Use a = 3.2 m, b = 19.1 kN/m, and c = 25.5 kN
Chapter 15 Solutions
MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, 9th Edition, [Instant Access], 2 terms (12 months)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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- Question No. 16 A long slope is formed in a soil with shear strength parameters: c' = 0 and d' = 34°. A firm stratum lies below the slope and it is assumed that the water table may occasionally rise to the surface, with seepage taking place parallel to the slope. Use Ysat = 18 kN/m³ and Yw = 10 kN/m³. The maximum slope angle (in degrees) to ensure a factor of safety of 1.5, assuming a potential failure surface parallel to the slope, would bearrow_forwardA cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following. a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?arrow_forwardThe factor of safety of an infinite soil slope shown in the figure having the properties c = 0, 0 = 35°, 16 kN/m3 and Ysat %3D = = 20 kN/m3 is Ydry approximately equal to 30° 8 m 10 marrow_forward
- Briefly explain the meaning of FS = 1.0 for sand followed by the infinite slope analysis.arrow_forwardA cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the stability factor?arrow_forwardA 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.arrow_forward
- Consider a slope given below with 10 slices, which has a circular failure surface. Each slice has 5 meters wide, and the weight of each slice was estimated on the basis of average height and a unit weight of soil ? = 16 kN/m3. The shear strength of the soil is assumed to be ? = 20 kPa and ? = 20°. The pertinent data for these ten slices is given in the table below. a) Determine the factor of safety using Janbu’s simplified method by assuming the initial ?? = ?. ?. b) Discuss how the factor of safety (stability of the Slope) will change due to the rainfall. You start to consider what environmental conditions will change first.arrow_forwardThis is a question from slope stability bishop method Please Note i am not asking for the entire problem to be completed, i am simply seeking guidance on how to calculate slice 1 entire row that is highlighted in red. example how did we derive the values of (W) in the table. formula ....W=ybz but im not getting the values see diagram attached Question A compacted earth fill is constructed on a soft, saturated clay (figure below). The fill was compacted to an average dry unit weight of 19 kN m3 ⁄ and water content of 15%. The shearing strength of the fill was determined by CU tests on samples compacted to representative field conditions. The shear strength parameters are ?? = 45 kPa, ??′ = 34°, and ???′ = 28°. The variation of undrained shear strength of the soft clay with depth as determined by simple shear tests is shown in the figure below, and the friction angle at the critical state is ???′ = 30°. The average water content of the soft clay is 40%. Compute the factor of safety…arrow_forwardCalculate the safety factor with the following conditions in a rock slope, likewise this slope requires a long-term static SF project equivalent to 2 based on the RCCDMX. b Zw B H a 02 A Rock mass properties: -Cohesion =3.3 T/m2 ; Internal friction angle: = -ymat = 3.8 T/m3; b=3m; B=6m; a=60° - 01=45° ; 0=72°; Zw=4m; Ax=12 m2 35° 01arrow_forward
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