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MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, 9th Edition, [Instant Access], 2 terms (12 months)
9th Edition
ISBN: 9781305971257
Author: Braja M. Das; Khaled Sobhan
Publisher: Cengage Learning US
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Chapter 15, Problem 15.3P
To determine
Find the factor of safety
Expert Solution & Answer
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Students have asked these similar questions
Question No. 16
A long slope is formed in a soil with shear strength
parameters: c' = 0 and d' = 34°. A firm stratum lies
below the slope and it is assumed that the water
table may occasionally rise to the surface, with
seepage taking place parallel to the slope. Use
Ysat = 18 kN/m³ and Yw = 10 kN/m³. The maximum
slope angle (in degrees) to ensure a factor of
safety of 1.5, assuming a potential failure surface
parallel to the slope, would be
Q.5 Figure 5 shows an infinite slope with H = 30 ft and the groundwater table coinciding with
the ground surface. If there is seepage through the soil, determine the factor of safety
against sliding along the plane AB. The soil properties are Gs = 2.7, e = 0.8, β = 16 ͦ,
Ø = 21 ͦ, and c’ = 1250 lb/ft2
.
Example 4.2
Along rectangular channel is 3m wide & carries water at the rate of 13m/sec. At a
certain point there is an approach change in the slope from 1:60 to 1:600 , determine:
a)whether the hyd. Jump will form?
Solution
Q = * R2/3 * S1/2 A
n
3y1
1
(3y,)(:
13
0.015
3+ 2y1
Y1 = 0.79 m
1
3y1
13 =
(3y2)G
3+2y2
0.015
Y2 = 1.82m
2
(13/3)
3
3
Ye =
= 1.24 m
9.81
Y1 < Yc
Chapter 15 Solutions
MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, 9th Edition, [Instant Access], 2 terms (12 months)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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Similar questions
- A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.arrow_forwardQue.5 A long natural slope in overconsolidated fissured clay of saturated unit weight 22kN/m³, is inclined at 14 degrees to the horizontal. The water table is at the surface and seepage is approximately parallel to the slope. A slip surface has developed on a plane parallel to the surface at a depth of 4m. Determine the factor of safety along the slip plane using the residual strenght parameter, o'r=20 degrees.arrow_forwardGEOTECHNICAL ENGINEERING Determine the height of a 1: 1 slope.Saturated clay Cu = 25 kn / m2Ysat = 18 kn / m3D = 1.2FS = 2.0arrow_forward
- Please calculate the critical factor of safety for the following slope configuration using the following m ethods: Using slope stability charts Layer 1 Clay c=35 kN/sq.m Friction Angle=0 Unit Weight-18 kN/cu.m Layer 2 Silty Sand c=5 kN/sq.m Friction Angle=35 deg Unit Weight=18 kN/cu.m Slope Height=10 m Slope Angle=30 Degrees Layer 1arrow_forwardThe factor of safety of an infinite soil slope shown in the figure having the properties c = 0, 0 = 35°, 16 kN/m3 and Ysat %3D = = 20 kN/m3 is Ydry approximately equal to 30° 8 m 10 marrow_forwardA trapezoidal channel discharges water at a rate of 45 m³/s. The wetted perimeter and area are 14 m and 18 m², respectively. If the Manning's n value is 0.015, which of the answers below would be the bed slope? O a. 0.5 m in 5 km O b. 0 с. 1 km in 1 km 0.5 m in 0.5 km O d. 1 min 1 marrow_forward
- 1. A trapezoidal channel with a 5-m bottom width and side slope m = 1.0 discharges 35 m3/s. The slope is 0.004 and is paved with smooth concrete (n = 0.012). a. What is the critical depth? b. What is the normal depth? c. Is it a mild slope, or steep?Hint: Compare critical depth with normal depth OR find the critical slope (??) and compare it with bed slope(?0) d. Is the depth increasing or decreasing upstream? Why would that be (e.g. a spillway, dam, etc.)?Hint: For the first part, use ????=?0−?1−??2 to show if the depth is decreasing/increasing (either by finding Fr and S, OR by simply using the values of ?, ?? and ?0 to figure out if the fraction is +/-). e. How would you conceptualize the flow – what regime (e.g., S1, S2, S3, M1, M2, M3 in Figure 10.20)? f. Determine the depth 3.3 m upstream from a section that has a measured depth of 1.69 m.Hint: If you are using MATLAB, solve the GVF differential equation (????=?0−?1−??2) and find flow depth y at location x = -3.3 m. If you are…arrow_forwardThe open channel shown in the following figure is constructed of smooth concrete. Water flows at 3.0 m2/s in uniform flow. What is the minimum slope? Use a reasonable value of the Manning's roughness coefficlent (i.e. for smooth concrete, use n= 0.013). Given that w = 3.3 m. W. concrete channel water 60 O a. 0.00011 O b.0.00106 Oc.0.00498 O d.0.00064 O e. 0.00204arrow_forwardProblem 6: A cut slope is to be made as shown in the figure with the respective shear strength parameters: 0 = 29° B = 50° $ = 10° Unit weight of soil is 16 kN/m3 %3D 3.0 m Failure plane Soil cohesion = 25 kPa Height of slope = 3 m %3D Determine the factor of safety against sliding.arrow_forward
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