Chemistry: The Science in Context (Fifth Edition)
Chemistry: The Science in Context (Fifth Edition)
5th Edition
ISBN: 9780393614046
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster, Stacey Lowery Bretz, Geoffrey Davies
Publisher: W. W. Norton & Company
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Chapter 15, Problem 15.58QP

(a)

Interpretation Introduction

Interpretation: The pKb value of quinoline is given to be 9.15 . The pH of 0.0752M solution and hydroxide ion concentration of solution of quinoline is to be calculated.

Concept introduction: The pH is the term used for expressing the extent of H+ in the solution. The pKa and pKb values are more helpful to determine the nature of the substances. These both terms related to acidic and the basic nature of any compound.

To determine: The pH of 0.0752M solution of quinoline.

(a)

Expert Solution
Check Mark

Answer to Problem 15.58QP

Solution

The pH of quinoline is 8.86_ .

Explanation of Solution

Explanation

Given

The pKb value of quinoline is 9.15 .

The ionization of quinoline is shown by the equation,

Quinoline Quinoline (H+) + OH

The Kb of solution of quinoline is calculated by the formula,

Kb=10pKb (1)

Substitute the value of pKb in equation (1).

Kb=109.15=7.08×1010

The calculation of concentration of Quinoline (H+) and [OH] is shown by the ICE table.

QuinolineQuinoline(H+)[OH]Initial0.0752M00ChangexxxEquilbrium(0.0752x)Mxx

The equilibrium constant is calculated by the formula,

Kb=[Quinoline+]×[OH]Quinoline (2)

Substitute the values of equilibrium constant, concentration of ions and compound in equation (2).

7.08×1010M=(x)×(x)(0.0752M)xx20.0752M (3)

In equation (3), x is very small as compared to (0.0752M) . So, it is neglected.

x2=(7.08×1010M)×(0.0752M)x=5.32×1011=7.3×106M

Thus, the concentration of both ions [Quinoline+] and [OH] in the solution is

7.3×106M .

The pOH is calculated by the formula,

pOH=log[OH] (4)

Substitute the value of [OH] in equation (4).

pOH=log(7.3×106M)=5.14

The pH is calculated by using pOH shown as,

pH=14pOH=14-5.14=8.86_

Therefore, the pH of quinoline is 8.86_ .

(b)

Interpretation Introduction

To determine: The hydroxide ion concentration of given solution.

(b)

Expert Solution
Check Mark

Answer to Problem 15.58QP

Solution

The concentration of [OH] in the solution is 7.3×10-6M_ .

Explanation of Solution

Explanation

Given

The pKb value of quinoline is 9.15 .

The ionization of quinoline is shown by the equation,

Quinoline Quinoline (H+) + OH

The Kb of solution of quinoline is calculated by the formula,

Kb=10pKb (1)

Substitute the value of pKb in equation (1).

Kb=109.15=7.08×1010

The calculation of concentration of Quinoline (H+) and [OH] is shown by the ICE table.

QuinolineQuinoline(H+)[OH]Initial0.0752M00ChangexxxEquilbrium(0.0752x)Mxx

The equilibrium constant is calculated by the formula,

Kb=[Quinoline+]×[OH]Quinoline (2)

Substitute the values of equilibrium constant, concentration of ions and compound in equation (2).

7.08×1010M=(x)×(x)(0.0752M)xx20.0752M (3)

In equation (3), x is very small as compared to (0.0752M) . So, it is neglected.

x2=(7.08×1010M)×(0.0752M)x=5.32×1011=7.3×10-6M_

Thus, the concentration of both ions [Quinoline+] and [OH] in the solution is

7.3×10-6M_ .

Conclusion

  1. a) The pH of 0.0752M solution of quinoline is 8.86_ .
  2. b) The concentration of [OH] in the solution is 7.3×10-6M_ .

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Chapter 15 Solutions

Chemistry: The Science in Context (Fifth Edition)

Ch. 15.5 - Prob. 11PECh. 15.5 - Prob. 12PECh. 15.6 - Prob. 13PECh. 15.6 - Prob. 14PECh. 15.7 - Prob. 15PECh. 15.8 - Prob. 16PECh. 15.8 - Prob. 17PECh. 15.8 - Prob. 18PECh. 15 - Prob. 15.1VPCh. 15 - Prob. 15.2VPCh. 15 - Prob. 15.3VPCh. 15 - Prob. 15.4VPCh. 15 - Prob. 15.5VPCh. 15 - Prob. 15.6VPCh. 15 - Prob. 15.7VPCh. 15 - Prob. 15.8VPCh. 15 - Prob. 15.9VPCh. 15 - Prob. 15.10VPCh. 15 - Prob. 15.11QPCh. 15 - Prob. 15.12QPCh. 15 - Prob. 15.13QPCh. 15 - Prob. 15.14QPCh. 15 - Prob. 15.15QPCh. 15 - Prob. 15.16QPCh. 15 - Prob. 15.17QPCh. 15 - Prob. 15.18QPCh. 15 - Prob. 15.19QPCh. 15 - Prob. 15.20QPCh. 15 - Prob. 15.21QPCh. 15 - Prob. 15.22QPCh. 15 - Prob. 15.23QPCh. 15 - Prob. 15.24QPCh. 15 - Prob. 15.25QPCh. 15 - Prob. 15.26QPCh. 15 - Prob. 15.27QPCh. 15 - Prob. 15.28QPCh. 15 - Prob. 15.29QPCh. 15 - Prob. 15.30QPCh. 15 - Prob. 15.31QPCh. 15 - Prob. 15.32QPCh. 15 - Prob. 15.33QPCh. 15 - Prob. 15.34QPCh. 15 - Prob. 15.35QPCh. 15 - Prob. 15.36QPCh. 15 - Prob. 15.37QPCh. 15 - Prob. 15.38QPCh. 15 - Prob. 15.39QPCh. 15 - Prob. 15.40QPCh. 15 - Prob. 15.41QPCh. 15 - Prob. 15.42QPCh. 15 - Prob. 15.43QPCh. 15 - Prob. 15.44QPCh. 15 - Prob. 15.45QPCh. 15 - Prob. 15.46QPCh. 15 - Prob. 15.47QPCh. 15 - Prob. 15.48QPCh. 15 - Prob. 15.49QPCh. 15 - Prob. 15.50QPCh. 15 - Prob. 15.51QPCh. 15 - Prob. 15.52QPCh. 15 - Prob. 15.53QPCh. 15 - Prob. 15.54QPCh. 15 - Prob. 15.55QPCh. 15 - Prob. 15.56QPCh. 15 - Prob. 15.57QPCh. 15 - Prob. 15.58QPCh. 15 - Prob. 15.59QPCh. 15 - Prob. 15.60QPCh. 15 - Prob. 15.61QPCh. 15 - Prob. 15.62QPCh. 15 - Prob. 15.63QPCh. 15 - Prob. 15.64QPCh. 15 - Prob. 15.65QPCh. 15 - Prob. 15.66QPCh. 15 - Prob. 15.67QPCh. 15 - Prob. 15.68QPCh. 15 - Prob. 15.69QPCh. 15 - Prob. 15.70QPCh. 15 - Prob. 15.71QPCh. 15 - Prob. 15.72QPCh. 15 - Prob. 15.73QPCh. 15 - Prob. 15.74QPCh. 15 - Prob. 15.75QPCh. 15 - Prob. 15.76QPCh. 15 - Prob. 15.77QPCh. 15 - Prob. 15.78QPCh. 15 - Prob. 15.79QPCh. 15 - Prob. 15.80QPCh. 15 - Prob. 15.81QPCh. 15 - Prob. 15.82QPCh. 15 - Prob. 15.83QPCh. 15 - Prob. 15.84QPCh. 15 - Prob. 15.85QPCh. 15 - Prob. 15.86QPCh. 15 - Prob. 15.87APCh. 15 - Prob. 15.88APCh. 15 - Prob. 15.89APCh. 15 - Prob. 15.90APCh. 15 - Prob. 15.91APCh. 15 - Prob. 15.92APCh. 15 - Prob. 15.93APCh. 15 - Prob. 15.94APCh. 15 - Prob. 15.95APCh. 15 - Prob. 15.96APCh. 15 - Prob. 15.97APCh. 15 - Prob. 15.98APCh. 15 - Prob. 15.99APCh. 15 - Prob. 15.100AP
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