Review. Why is the following situation impassible? You are in the high-speed package delivers’ business. Your competitor in the next building gains the right-of-way to build an evacuated tunnel just above the ground all the way around the Earth. By firing packages into this tunnel at just the right speed, your competitor is able to send the packages into orbit around the Earth in this tunnel so that they arrive on the exact opposite side of the Earth in a very short time interval. You come up with a competing idea. Figuring that the distance through the Earth is shorter than the distance around the Earth, you obtain permits to build an evacuated tunnel through the center of the Earth (Fig. P15.50). By simply dropping packages into this tunnel, they fall downward and arrive at the other end of your tunnel, which is in a building right next to the other end of your competitor’s tunnel. Because your packages arrive on the other side of the Earth in a shorter time interval, you win the competition and your business flourishes. Note: An object at a distance r from the center of the Earth is pulled toward the center of the Earth only by the mass within the sphere of radius r (the reddish region in Fig. P15.50). Assume the Earth has uniform density. Figure P15.50
Review. Why is the following situation impassible? You are in the high-speed package delivers’ business. Your competitor in the next building gains the right-of-way to build an evacuated tunnel just above the ground all the way around the Earth. By firing packages into this tunnel at just the right speed, your competitor is able to send the packages into orbit around the Earth in this tunnel so that they arrive on the exact opposite side of the Earth in a very short time interval. You come up with a competing idea. Figuring that the distance through the Earth is shorter than the distance around the Earth, you obtain permits to build an evacuated tunnel through the center of the Earth (Fig. P15.50). By simply dropping packages into this tunnel, they fall downward and arrive at the other end of your tunnel, which is in a building right next to the other end of your competitor’s tunnel. Because your packages arrive on the other side of the Earth in a shorter time interval, you win the competition and your business flourishes. Note: An object at a distance r from the center of the Earth is pulled toward the center of the Earth only by the mass within the sphere of radius r (the reddish region in Fig. P15.50). Assume the Earth has uniform density. Figure P15.50
Solution Summary: The author explains Kepler's third law, where the square of the orbital period of Earth is proportional to the cube of its radius. The time period for the competitor’s package to arrive at an arbitrary position
Review.Why is the following situation impassible? You are in the high-speed package delivers’ business. Your competitor in the next building gains the right-of-way to build an evacuated tunnel just above the ground all the way around the Earth. By firing packages into this tunnel at just the right speed, your competitor is able to send the packages into orbit around the Earth in this tunnel so that they arrive on the exact opposite side of the Earth in a very short time interval. You come up with a competing idea. Figuring that the distance through the Earth is shorter than the distance around the Earth, you obtain permits to build an evacuated tunnel through the center of the Earth (Fig. P15.50). By simply dropping packages into this tunnel, they fall downward and arrive at the other end of your tunnel, which is in a building right next to the other end of your competitor’s tunnel. Because your packages arrive on the other side of the Earth in a shorter time interval, you win the competition and your business flourishes. Note: An object at a distance r from the center of the Earth is pulled toward the center of the Earth only by the mass within the sphere of radius r (the reddish region in Fig. P15.50). Assume the Earth has uniform density.
One of your summer lunar space camp activities is to launch a 1130 kg rocket from the surface of the Moon. You are a serious
space camper and you launch a serious rocket: it reaches an altitude of 217 km. What gain AU in gravitational potential energy
does the launch accomplish? The mass and radius of the Moon are 7.36 × 1022 kg and 1740 km, respectively.
AU =
J
In this problem, you are going to explore three different ways to determine the gravitational constant G.
a) By observing that the centripetal acceleration of the Moon around the Earth is ac = 2.66 × 10-3 m/s2, what is the gravitatonal constant G, in cubic meters per kilogram per square second? Assume the Earth has a mass of ME = 5.96 × 1024 kg, and the mean distance between the centers of the Earth and Moon is rm = 3.81 × 108 m.
b) Measuring the centripetal acceleration of an orbiting object is rather difficult, so an alternative approach is to use the period of the orbiting object. Find an expression for the gravitational constant in terms of the distance between the gravitating objects rm, the mass of the larger body (the earth) ME, and the period of the orbiting body T.
c) The gravitational constant may also be calculated by analyzing the motion of an object, launched from the surface of the earth at an initial velocity of vi. Find an expression of the gravitational constant…
A satellite is traveling around a planet in a circular orbit with radius R. It moves in a constant speed of v = 1.1 × 104 m/s. The mass of the planet is M = 6.04 × 1024 kg. The mass of the satellite is m = 1.2 × 103 kg. First, find an expression for the gravitational potential energy PE in terms of G, M, m, and R.
a)Calculate the value of PE in joules.
b)Enter an expression for the total energy E of the satellite in terms of m and v.
c)Calculate the value of the total energy E in joules.
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