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Concept explainers
(a)
Interpretation: To determine the larger number from
Concept Introduction :
Scientific notation: It may be defined as the special way to write very small and very large number in easier way so that it will be easy to write and understand.
And standard form is normal way of writing the numbers.
(b)
Interpretation: To determine the larger number from
Concept Introduction :
Scientific notation: It may be defined as the special way to write very small and very large number in easier way so that it will be easy to write and understand.
And standard form is normal way of writing the numbers.
(c)
Interpretation: To determine the larger number from
Concept Introduction :
Scientific notation: It may be defined as the special way to write very small and very large number in easier way so that it will be easy to write and understand.
And standard form is normal way of writing the numbers.
(d)
Interpretation: To determine the larger number from
Concept Introduction :
Scientific notation: It may be defined as the special way to write very small and very large number in easier way so that it will be easy to write and understand.
And standard form is normal way of writing the numbers.
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Chapter 1 Solutions
EP BASIC CHEMISTRY-STANDALONE ACCESS
- A chemist mixes 34.9 g of diethyl ether with 52.1 g of 2-ethyltoluene and 9.03 g of butanoic acid. Calculate the percent by mass of each component of this solution. Be sure each of your answer entries has the correct number of significant digits. component mass percent diethyl ether 2-ethyltoluene 0% 0% butanoic acidarrow_forward4. A very sick diabetic patient needs to get 10g glucose, CHO̟ via an I.V. over the next hour. The concentration 612 of the glucose in the IV bag is 1.25M. What total volume of the glucose solution should the patient receive? Extra challenge: What rate should the IV drip be set at in mL/minute in order to give the patient the right dose in one hour?arrow_forwarda IMG_0299.heic Search What is the molarity of a solution that contains 639 g CuSO4 in 6.00 L of solution? PM In the 'Answer' box, express your numerical answer to 3 significant figures. Give the correct units in the 'units' box. AM Your Answer: AM AM Answer unitsarrow_forward
- = STATES OF MATTER Calculating mass percent composition A chemist mixes 81.4 g of benzene with 49.9 g of heptane and 10.0 g of 2-ethyltoluene. Calculate the percent by mass of each component of this solution. Round each of your answers to 3 significant digits. component benzene heptane 2-ethyltoluene mass percent % X 5arrow_forwardIA 8A Periodic Table of the Elements H Не 2A 3A 4A SA 6A 7A 1.008 4.003 3 5 6 8 9 10 Li Be F Ne 2 6.941 9.012 10.81 12.01 14.01 16.00 19.00 20.18 12 13 14 15 16 17 18 Na Mg Al Si Cl Ar 3B 4B 5B 6B 7B 8B IB 2B 22.99 24.31 26.98 28.09 30.97 32.07 35.45 39.95 19 20 21 22 23 24 25 26 27 Čo 28 29 30 31 32 33 34 35 36 K Са Sc Ti Cr Mn Fe Ni Cu Žn Ga Ge As Se Br Kr 39.10 40.08 44.96 47.87 50.94 52.00 54.94 55.85 58.93 58.69 63.55 65.41 69.72 72.64 74.92 78.96 79.90 83.80 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 Rb Sr Zr Nb Mo Tc Ru Rh Pd Ag | Cd 54 Xe In Sn Sb Te (98) 112.4 127.6 85.47 87.62 88.91 91.22 92.91 95.94 74 W 101.1 102.9 1064 107.9 114.8 1187 121.8 126.9 131.3 55 56 57 72 73 75 76 77 78 79 80 81 82 83 84 85 86 Cs Ва La Hf Ta Re Os Ir Pt Au Hg Pb Ро At Rn 132.9 137.3 1389 178.5 180.9 183.8 186.2 190.2 192.2 195.1 197.0 200.6 2044 207.2 209.0 (209) (210) (222) 87 88 89 104 105 106 107 108 109 110 II 112 113 114 115 116 117 118 Fr Ra |Ac Rf Db Sg Bh Hs Mt Ds Rg Cn Nh F1 Mc…arrow_forward1. If you start with 135 mg of acetone, what mass of NaBH4 in mg do you need? To account for some of the NaBH4 decomposing, you plan to use 1.3 equivalents of it. Again assuming 135 mg of acetone, what mass of NaBH4 in mg do you need?arrow_forward
- If the CaCl₂ was available not as a solid, but rather as a 0.40 molar solution, how many mL of that solution should be used if you desire to make 1.0 grams of MgCl₂? Do not include units in your answer. Make sure your answer has at least 3 significant digits.arrow_forwardTable 2: Faux data set to process oft Concentration of sodium hydroxide: 0.20M Trial 1 Trial 2 Trial 3 Volume vinegar (L) 10.00 mL 10.00 mL 10.00 mL Initial volume NaOH 0.0 mL 43.5mL 85.3mL Final volume NaOH 43.5 ml 85.3mL 127.3mL Volume NaOH used for titration (L) Mols base Mols acid Molarity acetic acid in vinegar Average molarity from three trials: M 24.6nL 48.30AL 18.76arrow_forwardA solution contains 500 mg of potassium acetate, 500 mg of potassium bicarbonate and 500 mg of potassium citrate per teaspoon. How many millimoles of potassium acetate, potassium bicarbonate and potassium citrate. are contained in a 25 ml vial? *Type in your answer in 2 decimal places. Do not forget the unit. Potassium acetate (MW-98 g/n) = Potassium bicarbonate (MW-100 g/n) = Potassium citrate (MW-306 g/n) =arrow_forward
- Muriatic acid is the commercial name for hydrochloric acid that can be purchased from hardware stores as a solution that is 37 % (w/w) HCI. What mass of this solution contains 7.5 g of HCI? Part 1 Your answer is correct. To begin this problem, one must find a way to relate the percentage by weight of HCI to grams of the solution. To do this, assume 37 g of HCI per 100 g of solution. eTextbook and Media Attempts: 1 of 15 used Part 2 Your answer is correct. Set up an equation to solve for grams of solution. 8 soln 8soln = SHCI 8HCI 8soln = (8HCI 8 solr 8roln = (8Hci) [(8som ) (8ncı)] Attempts: 1 of 15 used Part 3 Input the appropriate values to solve for the mass of a 37% (w/w) solution of HCI that contains 7,5 gof HCI? g solution Save for Later Attempts: 0 of 15 used Submit Answerarrow_forward3. While determining the volume during this experiment (Part II), if the total volume of the flask were incorrectly reported as 125 mL, how would this error affect the calculated molar mass of the unknown volatile liquid? Explain. MacBook Air 80 DII F3 F4 F5 F6 F7 F8 F9 F10 & * 4 5 6 7 8 R Y * 00arrow_forwardData obtained: Chips # of extractions Chips' weight (g) Fat weight (g) Regular 3 20.043 6.745 3 20.187 6.438 3 20.198 7.451 Low fat 3 19.456 3.982 3 20.072 4.547 3 20.192 4.589 Mass percent is a method of expressing the concentration of a substance in a mixture or element in a compound. It is calculated as the mass of the component divided by the total mass of the mixture and then multiplied by 100 to get the percent. The formula is: mass % of component= (mass of component / total mass) x 100% 1) Reproduce the following table, and use the data to determine the mass % of fat in the chips for each trial. 2) Show one example calculation. Chips Trial % by mass of fat Regular 1 2 3 Lowfat 1 2 3arrow_forward
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- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
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