Explanation Given: 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ] Concept Used: Basic properties of logarithmic function: ln a + ln b = ln a b ln a − ln b = ln a b n ln a = ln a n Where a > 0 , b > 0 and n is any real number Calculation: To express the quantity in single logarithm 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ] Use basic properties of logarithmic functions, as 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ] = ln ( x + 2 ) 3 / 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ] , using property n ln a = ln a n = ln ( x + 2 ) + 1 2 [ ln x (

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

1st Edition

ISBN: 9781305779037

Author: James Stewart, Troy Day

Publisher: Cengage Learning

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Question

Chapter 1.5, Problem 41E

To determine

To express the given quantity in single logarithm

13ln(x+2)3+12[lnx−ln( x 2+3x+2)2]

Expert Solution & Answer

Chapter 1 Solutions

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

Ch. 1.1 - Prob. 11E Ch. 1.1 - Prob. 12E Ch. 1.1 - Prob. 13E Ch. 1.1 - Prob. 14E Ch. 1.1 - Prob. 15E Ch. 1.1 - Prob. 16E Ch. 1.1 - Prob. 17E Ch. 1.1 - Prob. 18E Ch. 1.1 - Prob. 19E Ch. 1.1 - Prob. 20E Ch. 1.1 - Prob. 21E Ch. 1.1 - Prob. 22E Ch. 1.1 - Prob. 23E Ch. 1.1 - Prob. 24E Ch. 1.1 - Prob. 25E Ch. 1.1 - Prob. 26E Ch. 1.1 - Prob. 27E Ch. 1.1 - Prob. 28E Ch. 1.1 - Prob. 29E Ch. 1.1 - Prob. 30E Ch. 1.1 - Prob. 31E Ch. 1.1 - Prob. 32E Ch. 1.1 - Prob. 33E Ch. 1.1 - Prob. 34E Ch. 1.1 - Prob. 35E Ch. 1.1 - Prob. 36E Ch. 1.1 - Prob. 37E Ch. 1.1 - Prob. 38E Ch. 1.1 - Prob. 39E Ch. 1.1 - Prob. 40E Ch. 1.1 - Prob. 41E Ch. 1.1 - Prob. 42E Ch. 1.1 - Prob. 43E Ch. 1.1 - Prob. 44E Ch. 1.1 - Prob. 45E Ch. 1.1 - Prob. 46E Ch. 1.1 - Prob. 47E Ch. 1.1 - Prob. 48E Ch. 1.1 - Prob. 49E Ch. 1.1 - Prob. 50E Ch. 1.1 - Prob. 51E Ch. 1.1 - Prob. 52E Ch. 1.1 - Prob. 53E Ch. 1.1 - Prob. 54E Ch. 1.1 - Prob. 55E Ch. 1.1 - Prob. 56E Ch. 1.1 - Prob. 57E Ch. 1.1 - Prob. 58E Ch. 1.1 - Prob. 59E Ch. 1.1 - Prob. 60E Ch. 1.1 - 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Prob. 11E Ch. 1.3 - Prob. 12E Ch. 1.3 - Prob. 13E Ch. 1.3 - Prob. 14E Ch. 1.3 - Prob. 15E Ch. 1.3 - Prob. 16E Ch. 1.3 - Prob. 17E Ch. 1.3 - Prob. 18E Ch. 1.3 - Prob. 19E Ch. 1.3 - Prob. 20E Ch. 1.3 - Prob. 21E Ch. 1.3 - Prob. 22E Ch. 1.3 - Prob. 23E Ch. 1.3 - Prob. 24E Ch. 1.3 - Prob. 25E Ch. 1.3 - Prob. 26E Ch. 1.3 - Prob. 27E Ch. 1.3 - Prob. 28E Ch. 1.3 - Prob. 29E Ch. 1.3 - Prob. 30E Ch. 1.3 - Prob. 31E Ch. 1.3 - Prob. 32E Ch. 1.3 - Prob. 33E Ch. 1.3 - Prob. 34E Ch. 1.3 - Prob. 35E Ch. 1.3 - Prob. 36E Ch. 1.3 - Prob. 37E Ch. 1.3 - Prob. 38E Ch. 1.3 - Prob. 39E Ch. 1.3 - Prob. 40E Ch. 1.3 - Prob. 41E Ch. 1.3 - Prob. 42E Ch. 1.3 - Prob. 43E Ch. 1.3 - Prob. 44E Ch. 1.3 - Prob. 45E Ch. 1.3 - Prob. 46E Ch. 1.3 - Prob. 47E Ch. 1.3 - Prob. 48E Ch. 1.3 - Prob. 49E Ch. 1.3 - Prob. 50E Ch. 1.3 - Prob. 51E Ch. 1.3 - Prob. 52E Ch. 1.3 - Prob. 53E Ch. 1.3 - Prob. 54E Ch. 1.3 - Prob. 55E Ch. 1.3 - Prob. 56E Ch. 1.3 - Prob. 57E Ch. 1.3 - Prob. 58E Ch. 1.3 - Prob. 59E Ch. 1.3 - Prob. 1P Ch. 1.3 - Prob. 2P Ch. 1.3 - 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Prob. 63E Ch. 1.5 - Prob. 64E Ch. 1.5 - Prob. 65E Ch. 1.5 - Prob. 66E Ch. 1.5 - Prob. 67E Ch. 1.5 - Prob. 68E Ch. 1.5 - Prob. 69E Ch. 1.5 - Prob. 70E Ch. 1.5 - Prob. 1P Ch. 1.5 - Prob. 2P Ch. 1.5 - Prob. 3P Ch. 1.5 - Prob. 4P Ch. 1.5 - Prob. 5P Ch. 1.6 - Prob. 1E Ch. 1.6 - Prob. 2E Ch. 1.6 - Prob. 3E Ch. 1.6 - Prob. 4E Ch. 1.6 - Prob. 5E Ch. 1.6 - Prob. 6E Ch. 1.6 - Prob. 7E Ch. 1.6 - Prob. 8E Ch. 1.6 - Prob. 9E Ch. 1.6 - Prob. 10E Ch. 1.6 - Prob. 11E Ch. 1.6 - Prob. 12E Ch. 1.6 - Prob. 13E Ch. 1.6 - Prob. 14E Ch. 1.6 - Prob. 15E Ch. 1.6 - Prob. 16E Ch. 1.6 - Prob. 17E Ch. 1.6 - Prob. 18E Ch. 1.6 - Prob. 19E Ch. 1.6 - Prob. 20E Ch. 1.6 - Prob. 21E Ch. 1.6 - Prob. 22E Ch. 1.6 - Prob. 23E Ch. 1.6 - Prob. 24E Ch. 1.6 - Prob. 25E Ch. 1.6 - Prob. 26E Ch. 1.6 - Prob. 27E Ch. 1.6 - Prob. 28E Ch. 1.6 - Prob. 29E Ch. 1.6 - Prob. 30E Ch. 1.6 - Prob. 31E Ch. 1.6 - Prob. 32E Ch. 1.6 - Prob. 33E Ch. 1.6 - Prob. 34E Ch. 1.6 - Prob. 35E Ch. 1.6 - Prob. 36E Ch. 1.6 - Prob. 37E Ch. 1.6 - Prob. 38E Ch. 1.6 - Prob. 39E Ch. 1.6 - Prob. 40E Ch. 1.6 - Prob. 1P Ch. 1.6 - Prob. 2P Ch. 1.6 - Prob. 3P Ch. 1.6 - Prob. 4P Ch. 1 - Prob. 1CC Ch. 1 - Prob. 2CC Ch. 1 - Prob. 3CC Ch. 1 - Prob. 4CC Ch. 1 - Prob. 5CC Ch. 1 - Prob. 6CC Ch. 1 - Prob. 7CC Ch. 1 - Prob. 8CC Ch. 1 - Prob. 9CC Ch. 1 - Prob. 10CC Ch. 1 - Prob. 11CC Ch. 1 - Prob. 12CC Ch. 1 - Prob. 13CC Ch. 1 - Prob. 14CC Ch. 1 - Prob. 15CC Ch. 1 - Prob. 16CC Ch. 1 - Prob. 1TFQ Ch. 1 - Prob. 2TFQ Ch. 1 - Prob. 3TFQ Ch. 1 - Prob. 4TFQ Ch. 1 - Prob. 5TFQ Ch. 1 - Prob. 6TFQ Ch. 1 - Prob. 7TFQ Ch. 1 - Prob. 8TFQ Ch. 1 - Prob. 9TFQ Ch. 1 - Prob. 10TFQ Ch. 1 - Prob. 11TFQ Ch. 1 - Prob. 12TFQ Ch. 1 - Prob. 1E Ch. 1 - Prob. 2E Ch. 1 - Prob. 3E Ch. 1 - Prob. 4E Ch. 1 - Prob. 5E Ch. 1 - Prob. 6E Ch. 1 - Prob. 7E Ch. 1 - Prob. 8E Ch. 1 - Prob. 9E Ch. 1 - Prob. 10E Ch. 1 - Prob. 11E Ch. 1 - Prob. 12E Ch. 1 - Prob. 13E Ch. 1 - Prob. 14E Ch. 1 - Prob. 15E Ch. 1 - Prob. 16E Ch. 1 - Prob. 17E Ch. 1 - Prob. 18E Ch. 1 - Prob. 19E Ch. 1 - Prob. 20E Ch. 1 - Prob. 21E Ch. 1 - Prob. 22E Ch. 1 - Prob. 23E Ch. 1 - Prob. 24E Ch. 1 - Prob. 25E Ch. 1 - Prob. 26E Ch. 1 - Prob. 27E Ch. 1 - Prob. 28E Ch. 1 - Prob. 29E Ch. 1 - Prob. 30E Ch. 1 - Prob. 31E Ch. 1 - Prob. 32E Ch. 1 - Prob. 33E Ch. 1 - Prob. 34E Ch. 1 - Prob. 35E Ch. 1 - Prob. 36E Ch. 1 - Prob. 37E Ch. 1 - Prob. 38E Ch. 1 - Prob. 39E Ch. 1 - Prob. 40E Ch. 1 - Prob. 1CS Ch. 1 - Prob. 2CS Ch. 1 - Prob. 3CS Ch. 1 - Prob. 4CS Ch. 1 - Prob. 5CS Ch. 1 - Prob. 6CS Ch. 1 - Prob. 7CS Ch. 1 - Prob. 8CS Ch. 1 - Prob. 9CS

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To express the given quantity in single logarithm 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ]

Solution Summary: The author explains how to express the given quantity in single logarithm.

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To express the given quantity in single logarithm

13ln(x+2)3+12[lnx−ln( x 2+3x+2)2]

Chapter 1 Solutions

To express the given quantity in single logarithm 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ]

Solution Summary: The author explains how to express the given quantity in single logarithm.

Videos

To express the given quantity in single logarithm 13ln(x+2)3+12[lnx−ln( x 2+3x+2)2]

Chapter 1 Solutions

To express the given quantity in single logarithm

13ln(x+2)3+12[lnx−ln( x 2+3x+2)2]