Explanation Given information : An Exponential model for viral load y = 96.398 ⋅ ( 0.819 ) x given by the below graph Concept Involved: In this problem, the exponential function will be of the form A = a ⋅ b x where a is the initial amount, b is the growth factor, and A is the amount after xdays . The Half-life means the time taken for the initial amount to become half the amount. Calculation: Description Steps With the information provided initial amount a = 96.398 R N A c o p i e s / m L , the Half-life means the time taken for the initial amount to become half the amount, so we need to find t, when A = 48.199 48.199 = 96.398 ⋅ ( 0.819 ) x Description Steps Use symmetric property of identity to rewrite the equation 96.398 ⋅ ( 0.819 ) x = 48.199 Dividing by 96.398 on both sides and simplifying the fraction 96

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

1st Edition

ISBN: 9781305779037

Author: James Stewart, Troy Day

Publisher: Cengage Learning

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Chapter 1.4, Problem 33E

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Toestimate : the half-life of the viral load of patient 303.

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Chapter 1.4, Problem 32E

Chapter 1.4, Problem 34E

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Chapter 1 Solutions

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

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Toestimate : the half-life of the viral load of patient 303.

Solution Summary: The author explains that the half-life of the viral load of patient 303 during the first month of treatment is 3.5 days.

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Toestimate : the half-life of the viral load of patient 303.

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Chapter 1 Solutions