Concept explainers
(a)
Interpretation:
Whether the following reaction will takes place spontaneously or not should be predicted.
Concept Introduction:
A redox reaction is meant to take place when the oxidation states of the atoms present in a chemical species are changed.
Electrical energy can be generated through spontaneous
When these half cells containing the strip of the metal and the metal ion solution are placed in separate beakers, flow of electrons takes place from one half cell to other and these two half cells are connected by a salt bridge. The strip of the metal in each of these half cells is known as electrode and this strip is in contact with the metal ion solution.
Oxidation takes place at the electrode known as anode whereas reduction reaction takes place at cathode. Oxidation means loss of electrons while reduction means gain of electrons. Direction of a spontaneous redox reaction is determined with the help of activity series in which the metals which lose electrons easily are placed at the top and the metals that are unable to lose electrons easily are placed at bottom of the series.
(b)
Interpretation:
Whether the following reaction will takes place spontaneously or not should be predicted.
Concept Introduction:
A redox reaction is meant to take place when the oxidation states of the atoms present in a chemical species are changed.
Electrical energy can be generated through spontaneous oxidation-reduction reaction by making use of apparatus known as voltaic cell. It contains two half cells, at one of the half cell oxidation takes place and at other half cell reduction takes place.
When these half cells containing the strip of the metal and the metal ion solution are placed in separate beakers, flow of electrons takes place from one half cell to other and these two half cells are connected by a salt bridge. The strip of the metal in each of these half cells is known as electrode and this strip is in contact with the metal ion solution.
Oxidation takes place at the electrode known as anode whereas reduction reaction takes place at cathode. Oxidation means loss of electrons while reduction means gain of electrons. Direction of a spontaneous redox reaction is determined with the help of activity series in which the metals which lose electrons easily are placed at the top and the metals that are unable to lose electrons easily are placed at bottom of the series.
(c)
Interpretation:
Whether the following reaction will takes place spontaneously or not should be predicted.
Concept Introduction:
A redox reaction is meant to take place when the oxidation states of the atoms present in a chemical species are changed.
Electrical energy can be generated through spontaneous oxidation-reduction reaction by making use of apparatus known as voltaic cell. It contains two half cells, at one of the half cell oxidation takes place and at other half cell reduction takes place.
When these half cells containing the strip of the metal and the metal ion solution are placed in separate beakers, flow of electrons takes place from one half cell to other and these two half cells are connected by a salt bridge. The strip of the metal in each of these half cells is known as electrode and this strip is in contact with the metal ion solution.
Oxidation takes place at the electrode known as anode whereas reduction reaction takes place at cathode. Oxidation means loss of electrons while reduction means gain of electrons. Direction of a spontaneous redox reaction is determined with the help of activity series in which the metals which lose electrons easily are placed at the top and the metals that are unable to lose electrons easily are placed at bottom of the series.
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- 11.arrow_forward(7.11) A voltaic cell is constructed that uses the following reaction and operates at 298 K: Zn(s) + Cd+2, Cd*2(aq) ® + (S)uZ Zn*2(aq) + Cd(s) a) What is the emf of the cell under standard conditions? Zn*2 (ag) + 2e¯ ® Zn(s) E°cell = -0.76 V cd*2 (aq) + 2e¯ ® Cd(s) E°cell = -0.40 V Answer: The emf of the cell is V. Refer to the Table of Standard Reduction Potential below to solve Question (a). STANDARD REDUCTION POTENTIAL AT 25 °c E() Hall Reaction +0.N0 2 H,O) + ze Hg) + 2OH (a) Hal-Reaction Hall-Reaction E(V) Ag"(ng) +e- Ag(s) --0.83 Aglir(s) +e- Ag(s) + Br (ag) AgCKs) +e- Ag(s) + a"(a) Ag(CN), "(a) +e Ag(s)+ 2CN (a) Ag:Cro(s) + 2e 2 Ag(s) + Cro (ag) +0.10 HO, (a) + H,O) + 2e 3OH (ay) +0.22 H,O(ng) + 2H"(ag) + 2e 2 H;O() -0.31 Hg/ (a) + 2e 2 Hg() +0.45 2g"(ay) + 2e 1Hg (a) -0.15 Hg" (a) + 2e - Hg() +0.01 s) + 2e 21(a) +1.78 +0.79 +0.92 Agl(s) +e- Ag(s) +I(ay) +0.85 Ag(S0,) (ay) +e Ag(s) + 2 S,0 (ap) +0.54 A (ay) + 3e Al(s) HAso,(a) + 2H'(ay) + 2e - HAsOdany) + HO() Ba"(ag) + 2e -…arrow_forward(7.1b) Complete and balance the following by ion-electron method. Reactions are taking place in acidic solution. b) Mn*2(aq) + BiO3 (aq) Bi* (aq) + Mn04 (aq) Analysis: Oxidation-Half reation: Balancing atoms & charges: Mn*2(aq) Mn04 (aq) H20 - + H* + e Reduction-Half reation: Balancing atoms and charges: BiO3 (aq) H* + Bi* (aq) e H20 Balancing electrons lost & gained Multiply oxidation-half reaction by e's Multiply reduction-half reaction by es Final balanced equation: Continue nextarrow_forward
- (27) What is the value of the equilibrium constant (Keq) when the following redox reaction takes place at 727°C? Mn (s) + Sn¹+ (aq) → Mn²+ (aq) + Sn²+ (aq) (A) 2.55 x 10¹3 (B) 2.76 x 10¹8 (C) 7.62 x 1036 (D) 5.23 x 10-15 (E) 3.62 x 10-1⁹ The most convenient form of the equation for this one might not be on your note sheet. I suggest using: RT ECELL -In K nF (28) An archaeologist claims that a bone in her collection is from a saber-toothed tiger that is believed to have the carbon-1arrow_forward(7.7) A voltaic cell based on the half- reactions: In (aq) – In*3(ag) + 2e™ (aq) Br2() +2e¯→ 2Br¯(ag) The standard emf for this cell is +1.46 V. Using the data below, calculate, E'red for the reduction of In*3 to In*1. Br2() + 2e¯ → 2B1¯(ag) (cathode) E red(cathode) = E %3D Br(aq) = +1.06 V (See Table below) Choices: (A) +0.40 V (B) -0.40 V (C) + 2.50 V (D) -2.50 V Answer: E'red for the reduction of In+3 = to In*1 (in volts) STANDARD REDUCTION POTENTIALS at 25°C; Reduction Half Reaction F: (g) + 2e → 2F (aq) HO, (aq) + 2H" (aq) + 2e 2H;0 PbO(3) +4H" (ag) + So (ag) + 2e PbSO(s) + HO MnO. (aq) + 8H" (aq)+ Se+ Ma" (ag) + 4H,o Au" (aq) + 3e Au (s) Ch (g) + 2e 2C (ag) CrO (aq) + 14H" (aq) + 6e →2Cr" (aq) + TH:O MnO: (3) i 4H" (aq) 2e Ma (aq) 2H:0 O: (g) + 4H" (aq) + 4e + 2H:0 Br: () +2e + 2Br (ag) NO, (aq) + 4I" (aq) + 3e + NO (g) + 2H:0 2Hg (aq) + 2e Hg" (aq) Hgr" (aq) + 2e→ 2Hg () Ag (aq) +e Ag (s) Fe (aq) + e Fe (aq) O: (g) - 21 (aq) + 2e HO: (ag) E MnO" (aq) + 2H0 + 3e MnO: (3) + 40H…arrow_forward(7.2b) Complete and balance the following by ion-electron method. Reactions are taking place in alkaline solution. b) Cr(OH)a) + CIO (aq) - Cro, (aq) + Clug Analysis: Balancing under acidic condition first (adding H30 & H*) Oxidation-Half reation: Balancing atoms & charges: Cr(OH)) * H20 - Cro, ug) + Reduction-Half reation: Balancing atoms and charges: e Clap H20 Balancing electrons lost & galned Multiply oxidation-half reaction by e's Multiply reduction-half reaction by e's Final balanced equation: Continue next page.arrow_forward
- Solve question 6arrow_forward(5.9: Similar to For Practice 5.15) Identify the oxidizing agent in the reaction below. Mg(s) + 2HCl(aq) --> MgCl2(aq) + H2(g) O Mg O H₂ OHCI This is not a redox reaction. < Previousarrow_forward(7.1a) Complete and balance the following by ion-electron method. Reactions are taking place in acidic solution. a) Cu(s) + NO3 (aq) - Cu*2(aq) + NO2(g) + NO29) Analysis: Oxidation-Half reation: Balancing atoms & charges: Cu(s) Cu*2, (aq) e Reduction-Half reation: Balancing O & H and charges: H* + NO3 (aq) e NO2(g) + 1 H20 Balancing electrons lost & gained and balancing the equation: Cu(s) NO3 (aq) + H* - Cu*(aq) NO2(g) H20arrow_forward
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