Principles of Modern Chemistry
8th Edition
ISBN: 9781305079113
Author: David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher: Cengage Learning
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Chapter 15, Problem 88AP
Interpretation Introduction
Interpretation:
The solution is prepared from 0.23 mol of HF and 0.57 mol of HClO which is dissolved in 3.60 L of water. The pH of stronger acid and equilibrium concentration of HF, F-, HCO and ClO- should be determined.
Concept Introduction:
pH is used to determine the concentration of solution.
The ratio of mole to the volume of solution is known as concentration.
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Chapter 15 Solutions
Principles of Modern Chemistry
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- Acids You make a solution by dissolving 0.0010 mol of HCl in enough water to make 1.0 L of solution. a Write the chemical equation for the reaction of HCl(aq) and water. b Without performing calculations, give a rough estimate of the pH of the HCl solution. Justify your answer. c Calculate the H3O+ concentration and the pH of the solution. d Is there any concentration of the base OH present in this solution of HCl(aq)? If so, where did it come from? e If you increase the OH concentration of the solution by adding NaOH, does the H3O+ concentration change? If you think it does, explain why this change occurs and whether the H3O+ concentration increases or decreases. f If you were to measure the pH of 10 drops of the original HCl solution, would you expect it to be different from the pH of the entire sample? Explain. g Explain how two different volumes of your original HCl solution can have the same pH yet contain different moles of H3O+. h If 1.0 L of pure water were added to the HCl solution, would this have any impact on the pH? Explain.arrow_forwardCalculate the pH of a 0.10 molar solution of sodium formatearrow_forwardThe Kb of pyridine, C5H5N, is 1.7 x 10−9. Calculate the pH of a 0.124 M solution of pyridinium bromide, C5H5NH+Br−.arrow_forward
- calculate the pH of a 0.10 M perchloric ,HCIO4, solution.arrow_forwardDetermine the pH of each solution and classify it as acidic,basic, or neutral.(a) pOH = 8.5(b) pOH = 4.2(c) pOH = 1.7(d) pOH = 7.0arrow_forwardBacteria in the human mouth release enzymes to break up sucrose, and thenpolymerize glucose to form a bacterial plaque. When this glucose is digested, it formslactic acid, which causes tooth decay. Tooth enamel is made of calcium phosphate.Lactic acid has a Ka 1.38x10 -4 and ionizes into lactate and H3O+ ions. Assuming aninitial lactic acid concentration of 0.10 mol/L on your tooth, determine the pH(assume a 1:1:1 mole ratio) and the percent ionization. Should people be concernedwith plaque buildup? Justify your answer.arrow_forward
- Suppose that, instead of using NaOH, a base such as Ba(OH)2 had been used. What changes in the calculations would then have to be made to determine the molar concentrations of the base?arrow_forwardCalculate the pH of a 0.25 mol/L solution of magnesium hydroxidearrow_forwardCalculate the pH of a solution in which [OH−]=7.1×10−3M.arrow_forward
- Define pH in words. The strong acid HClaq has a pH value of 1, use the following equation for a strong acid: HClaq à H+aq + Cl-aq and convert the following expression to deduce the hydrogen ion concentration: pH = -log10 [H+] (ii) Use the above expression to deduce the pH of HCl (aq) given the concentration of the acid to be 4.5 mol/dm3arrow_forwardCalculate the pH of the weak acid, lactic acid (HC3H5O3), if the concentration is 0.10 mol/L and the Ka value is 1.4 x 10-4arrow_forwardCalculate the pH of 0.10 M (COOH)2 (aq), oxalic acid. Ka1 = 5.9 × 10–2 ; Ka2 = 6.4 × 10–5.arrow_forward
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