   Chapter 15, Problem 89AE

Chapter
Section
Textbook Problem

# Calculate the value of the equilibrium constant for each of the following reactions in aqueous solution.a. HC 2 H 3 O 2 + OH − ⇌ C 2 H 3 O 2 − + H 2 O b. C 2 H 3 O 2 − + H + ⇌ HC 2 H 3 O 2 c. HCl + NaOH ⇌ NaCl + H 2 O

(a)

Interpretation Introduction

Interpretation:

The value of equilibrium constant for each of the given reactions is to be stated.

Concept introduction:

At equilibrium, the equilibrium constant expression is expressed by the formula,

K=ConcentrationofproductsConcentrationofreactants

Explanation

Explanation

The stated reaction is,

HC2H3O2+OHC2H3O2+H2O

At equilibrium, the equilibrium constant expression is expressed by the formula,

K=ConcentrationofproductsConcentrationofreactants

Where,

• K is the equilibrium constant.

The equilibrium constant expression for the given reaction is,

K=[C2H3O2][HC2H3O2][OH] (1)

The reaction can also be stated as,

HC2H3O2(aq)C2H3O2(aq)+H+(aq)

At equilibrium, the equilibrium constant expression is expressed by the formula,

Ka=ConcentrationofproductsConcentrationofreactants

Where,

• Ka is the acid dissociation constant.

The equilibrium constant expression for the given reaction is,

Ka=[C2H3O2][H+][HC2H3O2] (2)

The Ka value for acetic acid is 1.8×105 .

The dissociation reaction of water is,

H2O(l)H+(aq)+OH(aq)

The ionic product of water is calculated as,

Kw=[H+][OH]=1

(b)

Interpretation Introduction

Interpretation:

The value of equilibrium constant for each of the given reactions is to be stated.

Concept introduction:

At equilibrium, the equilibrium constant expression is expressed by the formula,

K=ConcentrationofproductsConcentrationofreactants

(c)

Interpretation Introduction

Interpretation:

The value of equilibrium constant for each of the given reactions is to be stated.

Concept introduction:

At equilibrium, the equilibrium constant expression is expressed by the formula,

K=ConcentrationofproductsConcentrationofreactants

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