Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
9th Edition
ISBN: 9781305266292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 15, Problem 89CP
A light, cubical container of volume a3 is initially filled with a liquid of mass density ρ as shown in Figure P15.5la. The cube is initially supported by a light string to form a simple pendulum of length Li, measured from the center of mass of the filled container, where Li>> a. The liquid is allowed to flow from the bottom of the container at a constant rate (dM/dt). At any time t, the level of the liquid in the container is h and the length of the pendulum is L. (measured relative to the instantaneous center of mass) as shown in Figure P15.51b. (a) Find the period of the pendulum as a function of time. (b) What is the period of the pendulum after the liquid completely runs out of the container?
Figure P15.51
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Chapter 15 Solutions
Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
Ch. 15.1 - A block on the end of a spring is pulled to...Ch. 15.2 - Consider a graphical representation (Fig. 15.3) of...Ch. 15.2 - shows two curves representing particles undergoing...Ch. 15.2 - An object of mass m is hung from a spring and set...Ch. 15.4 - The ball in Figure 15.13 moves in a circle of...Ch. 15.5 - The grandfather clock in the opening storyline...Ch. 15 - Prob. 1OQCh. 15 - Prob. 2OQCh. 15 - Prob. 3OQCh. 15 - Prob. 4OQ
Ch. 15 - Prob. 5OQCh. 15 - Prob. 6OQCh. 15 - Prob. 7OQCh. 15 - Prob. 8OQCh. 15 - Prob. 9OQCh. 15 - Prob. 10OQCh. 15 - Prob. 11OQCh. 15 - Prob. 12OQCh. 15 - Prob. 13OQCh. 15 - Prob. 14OQCh. 15 - Prob. 15OQCh. 15 - Prob. 16OQCh. 15 - Prob. 17OQCh. 15 - Prob. 1CQCh. 15 - Prob. 2CQCh. 15 - Prob. 3CQCh. 15 - Prob. 4CQCh. 15 - Prob. 5CQCh. 15 - Prob. 6CQCh. 15 - Prob. 7CQCh. 15 - Prob. 8CQCh. 15 - Prob. 9CQCh. 15 - Prob. 10CQCh. 15 - Prob. 11CQCh. 15 - Prob. 12CQCh. 15 - Prob. 13CQCh. 15 - A 0.60-kg block attached to a spring with force...Ch. 15 - Prob. 2PCh. 15 - Prob. 3PCh. 15 - Prob. 4PCh. 15 - The position of a particle is given by the...Ch. 15 - A piston in a gasoline engine is in simple...Ch. 15 - Prob. 7PCh. 15 - Prob. 8PCh. 15 - Prob. 9PCh. 15 - Prob. 10PCh. 15 - Prob. 11PCh. 15 - Prob. 12PCh. 15 - Review. A particle moves along the x axis. It is...Ch. 15 - Prob. 14PCh. 15 - A particle moving along the x axis in simple...Ch. 15 - The initial position, velocity, and acceleration...Ch. 15 - Prob. 17PCh. 15 - Prob. 18PCh. 15 - Prob. 19PCh. 15 - You attach an object to the bottom end of a...Ch. 15 - Prob. 21PCh. 15 - Prob. 22PCh. 15 - Prob. 23PCh. 15 - Prob. 24PCh. 15 - Prob. 25PCh. 15 - Prob. 26PCh. 15 - Prob. 27PCh. 15 - Prob. 28PCh. 15 - A simple harmonic oscillator of amplitude A has a...Ch. 15 - Review. A 65.0-kg bungee jumper steps off a bridge...Ch. 15 - Review. A 0.250-kg block resting on a...Ch. 15 - Prob. 32PCh. 15 - Prob. 33PCh. 15 - A seconds pendulum is one that moves through its...Ch. 15 - A simple pendulum makes 120 complete oscillations...Ch. 15 - A particle of mass m slides without friction...Ch. 15 - A physical pendulum in the form of a planar object...Ch. 15 - Prob. 38PCh. 15 - Prob. 39PCh. 15 - Consider the physical pendulum of Figure 15.16....Ch. 15 - Prob. 41PCh. 15 - Prob. 42PCh. 15 - Prob. 43PCh. 15 - Prob. 44PCh. 15 - A watch balance wheel (Fig. P15.25) has a period...Ch. 15 - Prob. 46PCh. 15 - Prob. 47PCh. 15 - Show that the time rate of change of mechanical...Ch. 15 - Show that Equation 15.32 is a solution of Equation...Ch. 15 - Prob. 50PCh. 15 - Prob. 51PCh. 15 - Prob. 52PCh. 15 - Prob. 53PCh. 15 - Considering an undamped, forced oscillator (b =...Ch. 15 - Prob. 55PCh. 15 - Prob. 56APCh. 15 - An object of mass m moves in simple harmonic...Ch. 15 - Prob. 58APCh. 15 - Prob. 59APCh. 15 - Prob. 60APCh. 15 - Four people, each with a mass of 72.4 kg, are in a...Ch. 15 - Prob. 62APCh. 15 - Prob. 63APCh. 15 - An object attached to a spring vibrates with...Ch. 15 - Prob. 65APCh. 15 - Prob. 66APCh. 15 - A pendulum of length L and mass M has a spring of...Ch. 15 - A block of mass m is connected to two springs of...Ch. 15 - Prob. 69APCh. 15 - Prob. 70APCh. 15 - Review. A particle of mass 4.00 kg is attached to...Ch. 15 - Prob. 72APCh. 15 - Prob. 73APCh. 15 - Prob. 74APCh. 15 - Prob. 75APCh. 15 - Review. A light balloon filled with helium of...Ch. 15 - Prob. 78APCh. 15 - A particle with a mass of 0.500 kg is attached to...Ch. 15 - Prob. 80APCh. 15 - Review. A lobstermans buoy is a solid wooden...Ch. 15 - Prob. 82APCh. 15 - Prob. 83APCh. 15 - A smaller disk of radius r and mass m is attached...Ch. 15 - Prob. 85CPCh. 15 - Prob. 86CPCh. 15 - Prob. 87CPCh. 15 - Prob. 88CPCh. 15 - A light, cubical container of volume a3 is...
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- A hollow copper (Cu = 8.92 103 kg/m3) spherical shell of mass m = 0.950 kg floats on water with its entire volume below the surface. a. What is the radius of the sphere? b. What is the thickness of the shell wall?arrow_forwardWater is flowing through a pipe that has a constriction opening into a region with a wider cross-sectional area. If the pipe regions are cylindrical with radii of 0.10 m and 0.35 m, respectively, and the water is moving with a speed of 1.50 m/s in the wider section, what is the speed of the water in the constricted section?arrow_forwardA manometer is shown in Figure P15.36. Rank the pressures at the five locations indicated from highest to lowest. Indicate equal pressures, if any. FIGURE P15.36arrow_forward
- In about 1657. Otto von Guericke, inventor of the air pump, evacuated a sphere made of two brass hemispheres (Fig. P9.89). Two teams of eight horses each could pull the hemispheres apart only on some trials and then with greatest difficulty, with the resulting sound likened to a cannon firing. Find the force F required to pull the thin-walled evacuated hemispheres apart in terms of R, the radius of the hemispheres, P the pressure inside the hemispheres, and atmospheric pressure P0. Figure P9.89arrow_forward(a) How high will water rise in a glass capillary tube with a 0.500-mm radius? (b) How much gravitational potential energy does the water gain? (c) Discuss possible sources of this energy.arrow_forward(a) A water hose 2.00 cm in diameter is used to fill a 20.0-L bucket. If it takes 1.00 min to fill the bucket, what is the speed v at which water moves through the hose? (Note: 1 L = 1 000 cm3.) (b) The hose has a nozzle 1.00 cm in diameter. Find the speed of the water at the nozzle.arrow_forward
- Review. In a water pistol, a piston drives water through a large tube of area A1 into a smaller tube of area A2 as shown in Figure P14.46. The radius of the large tube is 1.00 cm and that of the small tube is 1.00 mm. The smaller tube is 3.00 cm above the larger tube. (a) If the pistol is fired horizontally at a height of 1.50 m, determine the time interval required for the water to travel from the nozzle to the ground. Neglect air resistance and assume atmospheric pressure is 1.00 atm. (b) If the desired range of the stream is 8.00 m, with what speed v2 must the stream leave the nozzle? (c) At what speed v1 must the plunger be moved to achieve the desired range? (d) What is the pressure at the nozzle? (e) Find the pressure needed in the larger tube. (f) Calculate the force that must be exerted on the trigger to achieve the desired range. (The force that must be exerted is due to pressure over and above atmospheric pressure.) Figure P14.46arrow_forwardA fluid flows through a horizontal pipe that widens, making a 45 angle with the y axis (Fig. P15.48). The thin part of the pipe has radius R, and the fluids speed in the thin part of the pipe is v0. The origin of the coordinate system is at the point where the pipe begins to widen. The pipes cross section is circular. a. Find an expression for the speed v(x) of the fluid as a function of position for x 0 b. Plot your result: v(x) versus x. FIGURE P15.48 (a) The continuity equation (Eq. 15.21) relates the cross-sectional area to the speed of the fluid traveling through the pipe. A0v0 = A(x)v(x) v(x)=A0v0A(x) The cross sectional area is the area of a circle whose radius is y(x). The widening pan of the pipe is a straight line with slope of 1 and intercept y(0) = R. y(x) = mx + b = x + R A(x) = [y(x)]2 = (x + R)2 Plug this into the formula for the velocity. Plug this into the formula for the velocity. v(x)=A0v0(x+R)2arrow_forward
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