Concept explainers
Knowing that at the instant shown the angular velocity of rod BE is 4 rad/s counterclockwise, determine (a) the angular velocity of rod AD. (b) the velocity of collar D. (c) the velocity of point A.
Fig. 15.84
(a)
The angular velocity of the rod
Answer to Problem 15.84P
The angular velocity of the rod
Explanation of Solution
Given information:
At the instant shown, the angular velocity of rob
Concept used:
The angular velocity (
Calculation:
At the instant shown, the angular velocity of rob
Therefore the velocity at point
be downward directed. (The point
Thus, the instantaneous center can be found by drawing the lines perpendicular to
Point
Consider the motion of the rod
The velocity at point
Then, consider the motion of the point
The angular velocity the rod
Thus, the angular velocity of the rod
Conclusion:
The angular velocity of the rod
(b)
The velocity of collar
Answer to Problem 15.84P
The velocity of collar
Explanation of Solution
Given information:
At the instant shown, the angular velocity of rob
Concept used:
The angular velocity (
Calculation:
Point
Consider the motion of point
From part (a),
The velocity of point
Thus, the velocity of collar
Conclusion:
The velocity of collar
(c)
The velocity of point
Answer to Problem 15.84P
The velocity of point
Explanation of Solution
Given information:
At the instant shown, the angular velocity of rob
Concept used:
The angular velocity (
Calculation:
Point
Consider the motion of point
From part (a),
The velocity of point
Thus, the velocity of point
Conclusion:
The velocity of point
Want to see more full solutions like this?
Chapter 15 Solutions
Vector Mechanics For Engineers
- In order to uncoil electrical wire from a spool fixed to a truck, a worker drives to the left with a speed of vA = 4 m/s. At the same time, a second worker holds the cable as he walks to the right. Knowing that at the instant shown the thickness of wire on the spool is 50 mm and that the 0.6-m-radius spool has an angular velocity of 8 rad/s, determine (a) the instantaneous center of rotation of the spool, (b) the velocity of point D on the spool, (c) the speed of the second worker B.arrow_forwardRod BDE is partially guided by a roller at D that moves in a vertical track. Knowing that atthe instant shown the angular velocity of crank AB is 5 rad/s clockwise and that β = 25°, determine (a) the angular velocity of the rod, (b) the velocity of point E.arrow_forwardA painter is half way up a 10-m ladder when the bottom starts sliding out from under him. Knowing that point A has a velocity vA = 2 m/s directed to the left when 0= 60°, determine (a) the angular velocity of the ladder, (b) the velocity of the painter.arrow_forward
- Knowing that at the instant shown the angular velocity of rod AB is 15 rad/s clockwise, write down the equation of velocity of point B relative to point D. Equation should be in vectorial form. Value of postion vector should be inserted.arrow_forwardKnowing that the angular velocity of rod DE is a constant 20 rad/s clockwise, determine in the position shown (a) the angular velocity of rod BD, (b) the velocity of the midpoint of rod BD. Solve using instantaneous center. The answer for WBD should be -5 rad/s and for Vc is 1.63 m/s. ] Please show every step on a piece of paper, if typed sometimes it gets cut off.arrow_forwardKnowing that at the instant shown the angular velocity of rod DEis 2.4 rad/s clockwise, determine (a) the velocity of collar A, (b) the velocity of point B.arrow_forward
- In a four bar mechanism, the dimensions of the links are given as AB = 50 mm, BC = 66 mm, CD = 56 mm and AD = 100 mm. At a given instant when <DAB=600 . The angular velocity of link AB is 10.5r/s in CCW direction. Determine, (i) velocity of point C, (ii) velocity of point E on link BC when BE = 40 mm, (iii) the angular velocity of link BC and CD; (iv) the velocity of an offset point F on link BC, if BF = 45 mm, CF = 30 mm and BCF is read clockwise. (v) the velocity of an offset point G on link CD, if CG = 24 mm, DG = 44 mm and DCG is read clockwise (arrow_forwardIn a four bar mechanism, the dimensions of the links are as given below:AB = 50 mm, BC = 66 mmCD = 56 mm and AD = 100 mmAt a given instant when | DAB=60°the angular velocity of link AB is 10.5rad/sec in CCW direction.Determine,i) Velocity of point Cii) Velocity of point E on link BC when BE = 40 mmiii) The angular velocity of link BC and CDiv) The velocity of an offset point F on link BC, if BF = 45 mm,CF = 30 mm and BCF is read clockwise.v) The velocity of an offset point G on link CD, if CG = 24mm, DG = 44 mm and DCG is read clockwise.vi) The velocity of rubbing of pins A, B, C and D. The ratios ofthe pins are 30 mm, 40 mm, 25 mm and 35 mmrespectively.arrow_forwardProblem 1: In a four bar mechanism, the dimensions of the links are as given below: AB = 50 mm, BC = 66 mm CD = 56 mm and AD = 100 mm At a given instant when |DAB 60o the angular velocity of link AB is 10.5 r/s in CCW direction. Determine, i) Velocity of point C ii) Velocity of point E on link BC when BE = 40 mm iii) The angular velocity of link BC and CD iv) The velocity of an offset point F on link BC, if BF = 45 mm, CF = 30 mm and BCF is read clockwise. v) The velocity of an offset point G on link CD, if CG = 24 mm, DG = 44 mm and DCG is read clockwise. vi) The velocity of rubbing of pins A, B, C and D. The ratio of the pins are 30 mm, 40 mm, 25 mm and 35 mm respectively.arrow_forward
- Knowing that at the instant shown the angular velocity of rod AB is 15 rad/s clockwise, write down the equation of velocity of point B relative to point A. Equation should be in vectorial form. Values of angular velocity and postion vector should be inserted.arrow_forwardAt the instant shown, the velocity of collar A is 0.4 m/s to the right and the velocity of collar B is 1 m/s to the left. Determine (a) the angular velocity of bar AD, (b) the angular velocity of bar BD, (c) the velocity of point D.arrow_forwardKnowing that at the instant shown the angular velocity of rod AB is 15 rad/s clockwise, write down the equation of velocity of point B relative to point A. -V_Bi=(-15k)x(-0.2j) +V_Bj=V_Ai-(15k) x (0.6i+0.25j) -V_Bi=V_A+(-15k)x(0.2j) +V_Bj=V_Ai-(omega_BDk) x (-0.6i-0.25j)arrow_forward
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY