Chapter 15.6, Problem 1LTS

a)

Interpretation Introduction

Interpretation:

For the given compounds, the highlighted bonds should be arranged in order of their increasing wavenumber.

Concept introduction

Reciprocal of wavelength is called wavenumber or Number of waves in one centimeter is called wavenumber.

Unit of wave number is reciprocal of Centimeter.

According to Hooke’s law the factors affecting wave numbers are

1. Bond strength

2. Mass of bond shared pair of atoms

$\begin{array}{l}\overline{\text{ν}}\text{=}\left(\frac{\text{1}}{\text{2πc}}\right){\left(\frac{\text{f}}{{\text{m}}_{\text{red}}}\right)}^{\text{1/2}}\\ \text{f}\text{=}\text{force}\text{constant}\left(\text{bond}\text{strength}\right)\\ {\text{m}}_{\text{red}}\text{=}\text{reduced}\text{mass}\\ \text{=}\frac{{\text{m}}_{\text{1}}{\text{m}}_{\text{2}}}{{\text{m}}_{\text{1}}{\text{+m}}_{\text{2}}}\end{array}$

b)

Interpretation Introduction

Interpretation:

For the given compounds, the highlighted bonds should be arranged in order of their increasing wavenumber.

Concept introduction

Reciprocal of wavelength is called wavenumber or Number of waves in one centimeter is called wavenumber

Unit of wave number is reciprocal of Centimeter.

According to Hooke’s law the factors affecting wave numbers are

1. Bond strength

2. Mass of bond shared pair of atoms

$\begin{array}{l}\overline{\text{ν}}\text{=}\left(\frac{\text{1}}{\text{2πc}}\right){\left(\frac{\text{f}}{{\text{m}}_{\text{red}}}\right)}^{\text{1/2}}\\ \text{f}\text{=}\text{force}\text{constant}\left(\text{bond}\text{strength}\right)\\ {\text{m}}_{\text{red}}\text{=}\text{reduced}\text{mass}\\ \text{=}\frac{{\text{m}}_{\text{1}}{\text{m}}_{\text{2}}}{{\text{m}}_{\text{1}}{\text{+m}}_{\text{2}}}\end{array}$