Chemistry: An Atoms-Focused Approach
1st Edition
ISBN: 9780393124200
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
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When a strong base is added to a solution of CuSO4, which is pale blue, a precipitate forms and the
solution above the precipitate is colorless. What is the net chemical equation that describes this reaction?
Include the phases of all species in the chemical equation.
When ammonia is then added, the precipitate dissolves and the solution turns a deep navy blue. What is the
net chemical equation that describes this event? Include the phases of all species in the chemical equation.
Cu(OH)₂(s) + 4NH₂(aq) → [Cu(NH₂)]²+ (aq) + 2OH¯(aq)
Tip: Plus signs (+) can be typed from the keyboard. Reaction arrows can be found in the Tools
menu of the answer module. Include phases in the balanced chemical equation. Click on the
(aq) button in the tools to select the phase to add. Phases should not be subscripted.
17.) Which combination results in precipitate formation? A. aqueous silver nitrate is added to aqueous ammonium acetateB. aqueous copper(II) sulfate is added to aqueous potassium perchlorateC. aqueous chromium(III) chloride is added to aqueous sodium hydroxideD. aqueous sodium carbonate is added to aqueous hydrobromic acid
Explain why.
nitrous acid is estimated,
c) What is the pH of the groundwater sample in which dichromate is oxidized to chromic ion by
ethanol, which is simultaneously transformed to dissolved carbon dioxide? Modeling studies show
that equilibrium is 1.75 x 107 M, dichromate ion is 7.3 x 10-2 M, chromic ion is 8.2 x 10°, ethanol is
6.8 x 102, and carbon dioxide is 6.4 x 10%.
dr for the state of South Carolina, describe
Chapter 16 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 16 - Prob. 16.2VPCh. 16 - Prob. 16.3VPCh. 16 - Prob. 16.4VPCh. 16 - Prob. 16.5VPCh. 16 - Prob. 16.6VPCh. 16 - Prob. 16.7VPCh. 16 - Prob. 16.8VPCh. 16 - Prob. 16.9VPCh. 16 - Prob. 16.10VPCh. 16 - Prob. 16.11QA
Ch. 16 - Prob. 16.12QACh. 16 - Prob. 16.13QACh. 16 - Prob. 16.14QACh. 16 - Prob. 16.16QACh. 16 - Prob. 16.17QACh. 16 - Prob. 16.18QACh. 16 - Prob. 16.19QACh. 16 - Prob. 16.20QACh. 16 - Prob. 16.21QACh. 16 - Prob. 16.22QACh. 16 - Prob. 16.23QACh. 16 - Prob. 16.24QACh. 16 - Prob. 16.25QACh. 16 - Prob. 16.26QACh. 16 - Prob. 16.27QACh. 16 - Prob. 16.28QACh. 16 - Prob. 16.29QACh. 16 - Prob. 16.30QACh. 16 - Prob. 16.31QACh. 16 - Prob. 16.32QACh. 16 - Prob. 16.33QACh. 16 - Prob. 16.34QACh. 16 - Prob. 16.35QACh. 16 - Prob. 16.36QACh. 16 - Prob. 16.37QACh. 16 - Prob. 16.38QACh. 16 - Prob. 16.39QACh. 16 - Prob. 16.40QACh. 16 - Prob. 16.41QACh. 16 - Prob. 16.42QACh. 16 - Prob. 16.43QACh. 16 - Prob. 16.44QACh. 16 - Prob. 16.45QACh. 16 - Prob. 16.46QACh. 16 - Prob. 16.47QACh. 16 - Prob. 16.48QACh. 16 - Prob. 16.49QACh. 16 - Prob. 16.50QACh. 16 - Prob. 16.51QACh. 16 - Prob. 16.52QACh. 16 - Prob. 16.53QACh. 16 - Prob. 16.54QACh. 16 - Prob. 16.55QACh. 16 - Prob. 16.56QACh. 16 - Prob. 16.57QACh. 16 - Prob. 16.58QACh. 16 - Prob. 16.59QACh. 16 - Prob. 16.60QACh. 16 - Prob. 16.61QACh. 16 - Prob. 16.62QACh. 16 - Prob. 16.63QACh. 16 - Prob. 16.64QACh. 16 - Prob. 16.65QACh. 16 - Prob. 16.66QACh. 16 - Prob. 16.67QACh. 16 - Prob. 16.68QACh. 16 - Prob. 16.69QACh. 16 - Prob. 16.70QACh. 16 - Prob. 16.71QACh. 16 - Prob. 16.72QACh. 16 - Prob. 16.73QACh. 16 - Prob. 16.74QACh. 16 - Prob. 16.75QACh. 16 - Prob. 16.76QACh. 16 - Prob. 16.77QACh. 16 - Prob. 16.78QACh. 16 - Prob. 16.79QACh. 16 - Prob. 16.80QACh. 16 - Prob. 16.81QACh. 16 - Prob. 16.82QACh. 16 - Prob. 16.83QACh. 16 - Prob. 16.84QACh. 16 - Prob. 16.85QACh. 16 - Prob. 16.86QACh. 16 - Prob. 16.87QACh. 16 - Prob. 16.88QACh. 16 - Prob. 16.89QACh. 16 - Prob. 16.90QACh. 16 - Prob. 16.91QACh. 16 - Prob. 16.92QACh. 16 - Prob. 16.93QACh. 16 - Prob. 16.94QACh. 16 - Prob. 16.95QACh. 16 - Prob. 16.96QACh. 16 - Prob. 16.97QACh. 16 - Prob. 16.98QACh. 16 - Prob. 16.99QA
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- The active ingredient of Pepto-Bismol is the compound bismuth subsalicylate, which undergoes the following dissociation when added to water: C7H5BiO4(s)+H2O(l)C7H4O32(aq)+Bi3+(aq)+OH(aq)K=? If the maximum amount of bismuth subsalicylate that reacts by this reaction is 3.2 1019 mol/L, calculate the equilibrium constant for the preceding reaction.arrow_forwardThe concentration of Mg2+ in seawater is 0.052 M. At what pH will 99% of the Mg2+ be precipitated as the hydroxide salt? [Ksp for Mg(OH)2 = 8.9 1012.]arrow_forwardThe average normal concentration of Ca2+ in urine is 5.33 g/L. Calculate the concentration of oxalate needed to precipitate calcium oxalate to initiate formation of a kidney stone. Ksp of calcium oxalate = 2.3 × 10−9. Calculate the minimum phosphate concentration that would precipitate a calcium phosphate kidney stone. Ksp of calcium phosphate = 2.0 × 10−29.arrow_forward
- You have a solution that has a lead(II) ion concentration of 0.0012 M. If enough soluble chloride-containing salt is added so that the Cl concentration is 0.010 M, will PbCl2 precipitate?arrow_forwardScott prepares a solution which contains a large excess of iron and a small amount of thiocyanate. He notices a faint orange color appear in the solution once mixed. He repeats this process with a higher concentration of thiocyanate and notices a deepening of the orange color in the solution once mixed. Explain what has happened to the equilibrium in this case. Has the value of Keq changed? Explain.arrow_forwardTo 200 ml of a solution containing 0.002 mol of aluminium chloride and 0.001 mol of calcium chloride is slowly added solid sodium phosphate (assuming no change in volume). How many grams of sodium phosphate must be added to precipitate as much of one ion as possible, while the other ion just doesn't precipitate? What percentage of the ion that will precipitate first is left in the solution at that moment?arrow_forward
- Consider a pale blue solution of CuSO4. Include phases in the balanced chemical equations. When a strong base is added to the pale blue solution of CuSO4, a precipitate forms and the solution above the precipitate is colorless(1) What is the net ionic equation that describes this irreversbile reaction? Ammonia is then added to the above heterogenous mixture. The precipitate dissolves, and then the entire solution turns a deep navy blue. However adding OH- to the deep navy blue solution results in the precipiate reforming.(2) What is the net ionic equation that describes this reversible event?arrow_forwardExplain why the solubility of a sparingly soluble salt represents an equilibrium system.arrow_forward(a) In the determination of chloride by the Mohr method, what will be the equilibrium concentration of silver ions in mg/L., on the basis of the solubility product principle, when the chloride concentration has been reduced to 0.2 mg/L? (b) If the concentration of chromate indicator used is 5 x 10 M, how much excess silver ion in mg/L. must be present before the formation of a red precipitate will begin?arrow_forward
- .030 moles of a weak acid, HA, was dissolved in 2.0L of water to form a solution. At equilibrium the concentration of HA was found to be .013 M. Determine the value of Ka for the weak acid.arrow_forwardAn equilibrium reaction between chromate ions, CrO4 2- (yellow), and H+ ions is established to produce dichromate, Cr₂072- (orange). Note the colours. A student adds NaOH to a test tube containing an orange mixture of the above reagents. What is observed? 01. The solution turns from orange to yellow O 2.A precipitate forms 3. The solution tuimns from orange to colourless O4. The solution remains orangearrow_forwardA sample can contain any ion from groups I to IV. Adding 6M HCl does not produce precipitates.The H + concentrations are adjusted to 0.3M and the solution is saturated with H2S, no precipitate forms.However, when [ H+] is reduced to 10-9M and saturated again with H2S, precipitate appears. Subsequently, it is found that this precipitate is a group III hydroxide.In group IV analysis, a precipitate is formed by adding (NH4) 2CO3. What ions must be present from groups a) I, b) II, c) III d) IV ?arrow_forward
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