EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Question
Chapter 16, Problem 16.8P
Interpretation Introduction
Interpretation:
The structure of the compound having formula
Concept Introduction:
The
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Compound 1 has molecular formula C7H15Cl. It shows two signals in the 1H-NMR spectrum, one at 1.08 ppm and one at 1.59 ppm. The relative integrals of these two signals are 3 and 2, respectively.
Propose structures for compound 1, explaining how you reach your conclusion.
The 1H NMR spectrum of CH3OH recorded on a 500 MHz NMR spectrometer consists of two signals, one due to the CH3 protons at 1715 Hz and one due to the OH proton at 1830 Hz, both measured downeld from TMS. (a) Calculate the chemical shift of each absorption. (b) Do the CH3 protons absorb upeld or downeld from the OH proton?
Predict the 13C-NMR spectrum of methyl orange in DMSO-d6. How many signals will beobserved and in which range?
Chapter 16 Solutions
EBK ORGANIC CHEMISTRY
Ch. 16 - Prob. 16.1PCh. 16 - Prob. 16.2PCh. 16 - Prob. 16.3PCh. 16 - Prob. 16.4PCh. 16 - Prob. 16.5PCh. 16 - Prob. 16.6PCh. 16 - Prob. 16.7PCh. 16 - Prob. 16.8PCh. 16 - Prob. 16.9PCh. 16 - Prob. 16.10P
Ch. 16 - Prob. 16.11PCh. 16 - Prob. 16.12PCh. 16 - Prob. 16.13PCh. 16 - Prob. 16.14PCh. 16 - Prob. 16.15PCh. 16 - Prob. 16.16PCh. 16 - Prob. 16.17PCh. 16 - Prob. 16.18PCh. 16 - Prob. 16.19PCh. 16 - Prob. 16.20PCh. 16 - Prob. 16.21PCh. 16 - Prob. 16.22PCh. 16 - Prob. 16.23PCh. 16 - Prob. 16.24PCh. 16 - Prob. 16.25PCh. 16 - Prob. 16.26PCh. 16 - Prob. 16.27PCh. 16 - Prob. 16.28PCh. 16 - Prob. 16.29PCh. 16 - Prob. 16.30PCh. 16 - Prob. 16.31PCh. 16 - Prob. 16.32PCh. 16 - Prob. 16.33PCh. 16 - Prob. 16.34PCh. 16 - Prob. 16.35APCh. 16 - Prob. 16.36APCh. 16 - Prob. 16.37APCh. 16 - Prob. 16.38APCh. 16 - Prob. 16.39APCh. 16 - Prob. 16.40APCh. 16 - Prob. 16.41APCh. 16 - Prob. 16.42APCh. 16 - Prob. 16.43APCh. 16 - Prob. 16.44APCh. 16 - Prob. 16.45APCh. 16 - Prob. 16.46APCh. 16 - Prob. 16.47APCh. 16 - Prob. 16.48APCh. 16 - Prob. 16.49APCh. 16 - Prob. 16.50APCh. 16 - Prob. 16.51APCh. 16 - Prob. 16.52APCh. 16 - Prob. 16.53APCh. 16 - Prob. 16.54APCh. 16 - Prob. 16.55APCh. 16 - Prob. 16.56APCh. 16 - Prob. 16.57APCh. 16 - Prob. 16.58APCh. 16 - Prob. 16.59APCh. 16 - Prob. 16.60APCh. 16 - Prob. 16.61APCh. 16 - Prob. 16.62APCh. 16 - Prob. 16.63APCh. 16 - Prob. 16.64APCh. 16 - Prob. 16.65APCh. 16 - Prob. 16.66APCh. 16 - Prob. 16.67APCh. 16 - Prob. 16.68AP
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- Following is the 1H-NMR spectrum of compound O, molecular formula C7H12. Compound O reacts with bromine in carbon tetrachloride to give a compound with the molecular formula C7H12Br2. The 13C-NMR spectrum of compound O shows signals at d 150.12, 106.43, 35.44, 28.36, and 26.36. Deduce the structural formula of compound O.arrow_forwardExplain why 2-chloropropene shows signals for three kinds of protons in its 1H NMRspectrum? Draw the structure and predict the approximate values for 1H-NMR spectra.arrow_forwardIndicate two basic differences that exist between the spectra of 1H y 13C in NMR.arrow_forward
- The 1H NMR spectrum of CH3OH recorded on a 500 MHz NMR spectrometer consists of two signals, one due to the CH3 protons at 1715 Hz and one due to the OH proton at 1830 Hz, both measured downfield from TMS. (a) Calculate the chemical shift of each absorption. (b) Do the CH3 protons absorb upfield or downfield from the OH proton?arrow_forwardWhich one of these four compounds would give a 13C NMR spectrum with only these three peaks, one at 210, one at 40 and one at 20? H3C OB OD 13C NMR delta (8) values C=O of ketones, aldehydes C=O of acids, esters, amides C=C and C=N C-X (where X = halogen, O) base position, alkyl C OC A OA CH3 H3C B CH3 H3C1 220-200 160-180 100-150 40-70 0 - 40 CH3 H₂C D CH3arrow_forwardThe 1H-NMR spectrum of compound B,C7H14O , consists of the following signals: δ 0.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t, 4H). Draw the structural formula of compound B.arrow_forward
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