BIOLOGY W/CONNECT AC 1 YR
BIOLOGY W/CONNECT AC 1 YR
12th Edition
ISBN: 9781260231403
Author: Mader
Publisher: MCG
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Chapter 16, Problem 2TS

You are observing a grouse population in which two feathers phenotypes are present in males. One is relatively dark and blends into shadows well, and the other is relatively bright and more obvious to predators. The females are uniformly dark-feathered. Observing the frequency of mating between females and the two types of males, you have recorded the following:

Matings with dark-feathered males: 13 Matings with bright-feathered males: 32 Propose a hypothesis to explain why females apparently prefer bright-feathered males. What selective advantage might there be in choosing a male with alleles that make it more susceptible to predation? What data would help test your hypothesis?

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What is the average survival rate for the Minotaur when the breeding season starts?   A. 0.42   B. 0.54   C. 0.66   D. 0.76   E. 0.83   Following up on Question 6, assuming random mating, what would be the percentage of long-horned baby Minotaur who are heterozygous at the H locus?   A. 23.5%   B. 25.0%   C. 50.0%   D. 51.5%   E. 68.0%
Based on the data shown in the graph, select the statements that describe what happens whenever one sex becomes rare or common. When one sex becomes rare, parents producing that sex have higher fitness due to a higher probability of mating success in their offspring. The rare sex becomes more common. When one sex becomes common, parents producing that sex have reduced fitness due to a lower probability of mating success in their offspring. The common sex becomes rarer. When one sex becomes rare, the other sex becomes common due to random fluctuations in the production of male and female offspring. The fitness of the parents is not affected. When one sex becomes either more rare or more common, parents produce an equal number of sons and daughters. The sex ratio returns to an equal number of males and females.
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