Principles of Biology
2nd Edition
ISBN: 9781259875120
Author: Robert Brooker, Eric P. Widmaier Dr., Linda Graham Dr. Ph.D., Peter Stiling Dr. Ph.D.
Publisher: McGraw-Hill Education
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Chapter 16, Problem 3TY
Summary Introduction
Introduction:
In genetics, an organism's
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A male mouse with genotype Igf2 Igf2m is crossed with a female who is Igf2 Igf2. What would be the expected outcome of this cross?
All offspring would be normal because the paternal allele is expressed
1/2 the offspring would be normal; 1/2 would be dwarf
All offspring would be dwarf because the maternal allele is silenced
3/4 of the offspring would be normal; 1/4 would be dwarf
All offspring would be dwarf because the paternal allele is silenced
An ebony strain of flies was discovered to be sensitive to carbon dioxide. Crossing a female sensitive strain with male resistant strain gave all sensitive offspring. The offspring of an F1 female crossed with a resistant male were all sensitive.
Using the following key to your illustrations using shapes, make a reciprocal cross up to the F2 generation. Put your illustrations in the space provided below. Label the phenotypes of all individuals in the reciprocal cross. Adjust spacing, if necessary. Make sure that the complete cross(es) can fit the same page.
Big blue circle - male cytoplasm
Big pink circle - female cytoplasm
Small half-blue-half-pink circle - F1 nucleus
Small blue circle - male nucleus
Small pink circle - female nucleus
give a diagram please
An ebony strain of flies was discovered to be sensitive to carbon dioxide. Crossing a female sensitive strain with male resistant strain gave all sensitive offspring. The offspring of an F1 female crossed with a resistant male were all sensitive.
Using the following key to your illustrations using shapes, make a reciprocal cross up to the F2 generation. Put your illustrations in the space provided below. Label the phenotypes of all individuals in the reciprocal cross. Adjust spacing, if necessary. Make sure that the complete cross(es) can fit the same page.
Big blue circle - male cytoplasm
Big pink circle - female cytoplasm
Small half-blue-half-pink circle - F1 nucleus
Small blue circle - male nucleus
Small pink circle - female nucleus
Chapter 16 Solutions
Principles of Biology
Ch. 16.1 - Which of the following is an epigenetic change...Ch. 16.2 - If you crossed an Igf 2 Igf 2- male mouse to an...Ch. 16.2 - Prob. 1TYKCh. 16.2 - Prob. 2TYKCh. 16.3 - Prob. 1CCCh. 16.3 - Prob. 1TYKCh. 16.3 - Which of the following statements regarding...Ch. 16.4 - Prob. 1TYKCh. 16.4 - Prob. 2TYKCh. 16.5 - Prob. 1BC
Ch. 16.5 - Prob. 1CCCh. 16.5 - Prob. 1TYKCh. 16.5 - Prob. 2TYKCh. 16.6 - Prob. 1CCCh. 16.6 - Prob. 1BCCh. 16.6 - Prob. 1TYKCh. 16.6 - Genes that are linked do not conform to Mendels...Ch. 16 - Which of the following is an example of an...Ch. 16 - In mice, the allele of the Igf2 gene that is...Ch. 16 - Prob. 3TYCh. 16 - The marking process for genomic imprinting...Ch. 16 - According to Mary Lyons hypothesis, the patchwork...Ch. 16 - Prob. 6TYCh. 16 - Prob. 7TYCh. 16 - Prob. 8TYCh. 16 - Prob. 9TYCh. 16 - Prob. 10TYCh. 16 - Prob. 1CCQCh. 16 - Prob. 2CCQCh. 16 - Prob. 3CCQCh. 16 - Prob. 1CBQCh. 16 - Prob. 2CBQ
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- An Agouti with Himalayan gene female rabbit was mated by an albino male. If there is an Agouti in the filial generation, its genotype isarrow_forwardThe A & B antigens in humans may be found in water-soluble forms in secretions, including saliva of individuals with the genotypes E/E& E/e, but not individuals with the genotype e/e. Thus, the population contains ‘secretors’ & ‘nonsecretors’. A cross was performed between 2 heterozygous secretors, one with type O blood and the second with type AB blood. What phenotypic ratios are expected in their offspring? A) 1/4 type A : 1/4 type B : 1/2 non-secretor B) 3/8 type A : 3/8 type B : 2/8 non-secretor C) 1/2 type A : 1/2 type B D) 3/4 type AB : 1/4 non-secretorarrow_forwardA parental cross between homozygous wild-type red eyed females (X+ X+) were crossed with white eyed males (XwY). The F1 generation consisted of phenotypic X+Xw females and X+Y males. The F2 generation was produced by crossing the F1 generation and consisted of a ratio of 2 red eyed females (X+ X+ and X+ Xw) : 1 red eyed male (X+Y) : 1 white eyed male (XwY). Attached is a picture of a chi square analysis based on the results from the F2 generation. Please discus what conclusions can be made based on the data/findings. What inheritance pattern is this?arrow_forward
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