Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 16, Problem 47P
Interpretation Introduction
Interpretation:
If lactate along with CO2 labeled with 14C is allowed to form glucose, then the carbon that would be labeled in the glucose should be determined.
Concept introduction:
Glycolysis is the process that occurs in the cytoplasm of the cell. It is the breakdown of one molecule of glucose into two molecules of pyruvic acid. During this process, energy is released in the form of two moles of ATP. The purpose of glycolysis is to maintain the blood glucose level.
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Tracing carbon atoms 2. If cells synthesizing glucose from lactate are
exposed to CO2CO2 labeled with 14C,“C, what will be the
distribution of label in the newly synthesized glucose?
1. pH Effects
a. In the enzyme mechanism of lysozyme, two acidic amino acid residues, Asp52
and Glu35, are critical for catalytic activity. If we assume normal side chain pKa
values for Asp (pKar = 3.90) and for Glu (pKar = 4.07), what proportion of
enzyme molecules will have both Asp52 and Glu35 in the correct ionization
state at pH 5.0 (the pH optimum for lysozyme)?
b. Are the traditional pKa values likely to be correct within the protein? What pKa
changes might be present within lysozyme?
The allosteric site
1). Draw a representation of an allosteric binding site of an enzyme.
must bind an allosteric modifier that maintains three hydrophobic regions, a polar
charged region and two regions of hydrogen bonding. You choose the order or
organization of the characteristics in the allosteric site - label all regions.
Details
the allosteric site is composed of faces of two separate beta sheets and two
separate alpha helices. You might decide that each beta sheet or each alpha helix
contributes one amino acid R group to the allosteric site or you may decide that one of
the beta sheets or one of the alpha helixes contributes two or more amino acid R groups
to the allosteric organization. Your choice but please show R group structure in the
allosteric site!
Chapter 16 Solutions
Biochemistry
Ch. 16 - Prob. 1PCh. 16 - Prob. 2PCh. 16 - Prob. 3PCh. 16 - Prob. 4PCh. 16 - Prob. 5PCh. 16 - Prob. 6PCh. 16 - Prob. 7PCh. 16 - Prob. 8PCh. 16 - Prob. 9PCh. 16 - Prob. 10P
Ch. 16 - Prob. 11PCh. 16 - Prob. 12PCh. 16 - Prob. 13PCh. 16 - Prob. 14PCh. 16 - Prob. 15PCh. 16 - Prob. 16PCh. 16 - Prob. 17PCh. 16 - Prob. 18PCh. 16 - Prob. 19PCh. 16 - Prob. 20PCh. 16 - Prob. 21PCh. 16 - Prob. 22PCh. 16 - Prob. 23PCh. 16 - Prob. 24PCh. 16 - Prob. 25PCh. 16 - Prob. 26PCh. 16 - Prob. 27PCh. 16 - Prob. 28PCh. 16 - Prob. 29PCh. 16 - Prob. 30PCh. 16 - Prob. 31PCh. 16 - Prob. 32PCh. 16 - Prob. 33PCh. 16 - Prob. 34PCh. 16 - Prob. 35PCh. 16 - Prob. 36PCh. 16 - Prob. 37PCh. 16 - Prob. 38PCh. 16 - Prob. 39PCh. 16 - Prob. 40PCh. 16 - Prob. 41PCh. 16 - Prob. 42PCh. 16 - Prob. 43PCh. 16 - Prob. 44PCh. 16 - Prob. 45PCh. 16 - Prob. 46PCh. 16 - Prob. 47PCh. 16 - Prob. 48PCh. 16 - Prob. 49PCh. 16 - Prob. 50PCh. 16 - Prob. 51PCh. 16 - Prob. 52PCh. 16 - Prob. 53PCh. 16 - Prob. 54PCh. 16 - Prob. 55PCh. 16 - Prob. 56PCh. 16 - Prob. 57PCh. 16 - Prob. 58PCh. 16 - Prob. 59PCh. 16 - Prob. 60PCh. 16 - Prob. 61P
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