Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 16, Problem 54GP
To determine

To Find: Amount of electric field (E) to suspend a proton at rest in electric field under action of gravity

Expert Solution & Answer
Check Mark

Answer to Problem 54GP

  1.02×107N/C,upwards

Explanation of Solution

Given:

Mass of proton: 1.67×1027kg

Electron is suspended in (E) against the action of gravity.

Formula used:

  E=mgq

  Where,m= mass of proton

  g= acceleration due to gravity

  q= charge on electron

Calculation:

Mass of Proton (m)=1.67×1027kg

  g=9.8m/s2

Charge on proton (e)=1.6×1019C

The electric field E=Fe=mge

  =(1.67×1027)(9.8)(1.6×1019)N/CE=1.02×107N/C

Conclusion:

Amount of electric field required to suspend a proton at rest against action of gravity is 1.02×107N/C (in upward direction)

Chapter 16 Solutions

Physics: Principles with Applications

Ch. 16 - Prob. 11QCh. 16 - Prob. 12QCh. 16 - Prob. 13QCh. 16 - Prob. 14QCh. 16 - Prob. 15QCh. 16 - Prob. 16QCh. 16 - Prob. 17QCh. 16 - Assume that the two opposite charges in Fig....Ch. 16 - Consider the electric field at the three points...Ch. 16 - Why can electric field lines never cross?Ch. 16 - Show, using the three rules for field lines given...Ch. 16 - Given two point charges, Q and 2Q, a distance l...Ch. 16 - Consider a small positive test charge located on...Ch. 16 - A point charge is surrounded by a spherical...Ch. 16 - Prob. 1PCh. 16 - Prob. 2PCh. 16 - Prob. 3PCh. 16 - Prob. 4PCh. 16 - Prob. 5PCh. 16 - Prob. 6PCh. 16 - Prob. 7PCh. 16 - Prob. 8PCh. 16 - Prob. 9PCh. 16 - Prob. 10PCh. 16 - Prob. 11PCh. 16 - Prob. 12PCh. 16 - Prob. 13PCh. 16 - Prob. 14PCh. 16 - Prob. 15PCh. 16 - Prob. 16PCh. 16 - Prob. 17PCh. 16 - Prob. 18PCh. 16 - Prob. 19PCh. 16 - Prob. 20PCh. 16 - Prob. 21PCh. 16 - Prob. 22PCh. 16 - Prob. 23PCh. 16 - Prob. 24PCh. 16 - Prob. 25PCh. 16 - Prob. 26PCh. 16 - Prob. 27PCh. 16 - Prob. 28PCh. 16 - Prob. 29PCh. 16 - Prob. 30PCh. 16 - Prob. 31PCh. 16 - Prob. 32PCh. 16 - Prob. 33PCh. 16 - Prob. 34PCh. 16 - Prob. 35PCh. 16 - Prob. 36PCh. 16 - Prob. 37PCh. 16 - Prob. 38PCh. 16 - Prob. 39PCh. 16 - Prob. 40PCh. 16 - Prob. 41PCh. 16 - Prob. 42PCh. 16 - Prob. 43PCh. 16 - Prob. 44PCh. 16 - Prob. 45PCh. 16 - Prob. 46PCh. 16 - Prob. 47PCh. 16 - Prob. 48PCh. 16 - Prob. 49PCh. 16 - Prob. 50PCh. 16 - Prob. 51PCh. 16 - Prob. 52GPCh. 16 - Prob. 53GPCh. 16 - Prob. 54GPCh. 16 - Prob. 55GPCh. 16 - Prob. 56GPCh. 16 - Prob. 57GPCh. 16 - Prob. 58GPCh. 16 - Prob. 59GPCh. 16 - Prob. 60GPCh. 16 - Prob. 61GPCh. 16 - Prob. 62GPCh. 16 - Prob. 63GPCh. 16 - Prob. 64GPCh. 16 - Prob. 65GPCh. 16 - Prob. 66GPCh. 16 - Prob. 67GPCh. 16 - Prob. 68GPCh. 16 - Prob. 69GPCh. 16 - Prob. 70GPCh. 16 - Prob. 71GPCh. 16 - Prob. 72GPCh. 16 - Prob. 73GP
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