Chapter 16, Problem 5P

Lactic acid (CH3 - CH(OH) - COOH) is a weak acid and therefore a weak electrolyte.found in "cut milk". The freezing point of an aqueous solution 0.01 m of lactic acid is 0.0206 ºC. Knowing that in aqueous solution the following equilibrium occurs:CH3 -CH(OH) -COOH(ac)  = CH3 -CH(OH) -COO(-)(ac) + H(+)(ac)and that, therefore, there are three species (solutes) in solution, calculate their percentage of ionization.

Lactic acid (CH3 - CH(OH) - COOH) is a weak acid and therefore a weak electrolyte. found in "cut milk". The freezing point of an aqueous solution 0.01 m of lactic acid is 0.0206 ºC. Knowing that in aqueous solution the following equilibrium occurs: CH3 -CH(OH) -COOH(ac) = CH3 -CH(OH) -COO(-)(ac) + H(+)(ac) and that, therefore, there are three species (solutes) in solution, calculate their percentage of ionization.

The molar solubility in mol/L of Mg(OH)2 (Ksp=1.8x10-11) is   4.2x10-6M   1.8x10-11M   2.6x10-4M   1.7x10-4M

If ΔHsoln < 0, will the conditions for solubility always be met?

The molas solubility of silver phosphate is 1.6x10-5 mol/L. What is the ksp for silver phosphate?

At 25 ∘C, the osmotic pressure of a solution of the salt XY is 39.9 torr . What is the solubility product of XY at 25 ∘C?