Concept explainers
(a)
Interpretation:
The normality of a
Concept introduction:
Solution is a homogeneous mixture of two or more components. A sample taken from any part of the solution will have the same composition as the rest of the solution. The normality of a solution is defined as the number of equivalents per liter of the solution. One equivalent of an acid is the quantity that gives
Answer to Problem 78E
The normality of a
Explanation of Solution
The formula to calculate normality is given below.
The molarity of the solution is
The relation between
The probable conversion factors are given below.
The conversion factor to determine
Therefore,
The reaction is given below.
In this reaction,
Substitute the number of equivalents and the molarity of
The relation between
The probable conversion factors are given below.
The conversion factor to determine
Therefore,
Therefore, the normality of a
The normality of a
(b)
Interpretation:
The volume of the solution that would contain
Concept introduction:
Solution is a homogeneous mixture of two or more components. A sample taken from any part of the solution will have the same composition as the rest of the solution. The normality of a solution is defined as the number of equivalents per liter of the solution. One equivalent of an acid is the quantity that gives
Answer to Problem 78E
The volume of the solution that would contain
Explanation of Solution
The formula to calculate the volume is given below.
The normality of the solution is
The relation between
The probable conversion factors are given below.
The conversion factor to determine
Therefore,
The equivalents of solute is
Substitute the value of normality and equivalents of solute in equation (2).
Therefore, the volume of the solution that would contain
The volume of the solution that would contain
Want to see more full solutions like this?
Chapter 16 Solutions
Bundle: Introductory Chemistry: An Active Learning Approach, 6th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
- You want to prepare a 1.0 mol/kg solution of ethyleneglycol, C2H4(OH)2, in water. Calculate the mass of ethylene glycol you would need to mix with 950. g water.arrow_forwardDescribe in words how you would prepare pure crystalline AgCl and NaNO3 from solid AgNO3 and solid NaCl.arrow_forwardUse the appropriate tables to calculate H for (a) the reaction between MgC03(s) and a strong acid to give Mg2+(aq), CO2(g), and water. (b) the precipitation of iron(III) hydroxide from the reaction between iron(III) and hydroxide ions.arrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningPrinciples of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning