Concept explainers
(a)
The magnitude and direction of the electric field just outside surface of nucleus.
Answer to Problem 85QAP
The magnitude of the electric field just outside surface of nucleus is,
Explanation of Solution
Given:
Diameter of atom,
Radius of atom,
Diameter of nucleus,
Radius of nucleus,
Charge on electron,
Mass of electron,
Formula used:
The electric field is given by,
Where,
Calculation:
The electric field is given by,
The electric field is directed outwards from the nucleus because nucleus acts as point source.
(b)
The magnitude and direction of the electric field at the distance of outermost electron.
Answer to Problem 85QAP
The magnitude and direction of the electric field at the distance of outermost electron is,
Explanation of Solution
Given:
Diameter of atom,
Radius of atom,
Diameter of nucleus,
Radius of nucleus,
Charge on electron,
Mass of electron,
Formula used:
The electric field is given by,
Where,
Calculation:
The electric field is given by,
The electric field is directed outwards from the nucleus.
(c)
The magnitude and direction of the acceleration of the outermost electron.
Answer to Problem 85QAP
The magnitude and direction of the acceleration of outermost electron is,
Explanation of Solution
Given:
Diameter of atom,
Radius of atom,
Diameter of nucleus,
Radius of nucleus,
Charge on electron,
Mass of electron,
Electric field,
Formula used:
The force acting on the ball is,
Where,
Calculation:
The force is given by,
But we know that,
From equation (1) and (2)
The acceleration is directed outwards from the nucleus.
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Chapter 16 Solutions
College Physics Volume 2
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