EBK BIOLOGY
4th Edition
ISBN: 8220102797376
Author: BROOKER
Publisher: YUZU
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Chapter 16.1, Problem 5CC
Summary Introduction
To identify: The genotype of the parent purple flowered plant.
Introduction: An allele is defined as a variant of a gene responsible for coding a specific character. There are atleast two different alleles for each
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EXAMPLE PROBLEM A plant with orange, spotted flowers was grown in the greenhouse from a seed collected in the wild. The plant was self-pollinated and gave rise to the following progeny: 88 orange with spots, 34 yellow with spots, 32 orange with no spots, and 8 yellow with no spots. What can you conclude about the dominance relationships of the alleles responsible for the spotted and unspotted phenotypes? What can you conclude about the genotype of the original plant that had orange, spotted flowers?
picture shows the results of a cross between a tall pea plant and a short pea plant.
Q. What phenotypes and proportions will be produced if a tall F1 plant is backcrossed to the short parent?
Give typed explanation
In pea plants, the tall allele (T) is dominant to the dwarf allele (t) and the yellow pea color allele (Y) is dominant to the green pea color allele (y). Cross TtYy with Ttyy.
What would be the genotype and phenotype ratios in their offspring?
(Please include the gametes produced by each parent.)
Chapter 16 Solutions
EBK BIOLOGY
Ch. 16.1 - Prob. 1CCCh. 16.1 - Prob. 2CCCh. 16.1 - Prob. 3CCCh. 16.1 - Prob. 4CCCh. 16.1 - Prob. 5CCCh. 16.1 - Mendels Laws of Inheritance Concept Check: What...Ch. 16.2 - Prob. 1BCCh. 16.2 - Prob. 2BCCh. 16.2 - Prob. 1CCCh. 16.3 - Prob. 1CC
Ch. 16.3 - Prob. 2CCCh. 16.4 - Prob. 1CCCh. 16.4 - Prob. 1EQCh. 16.4 - Prob. 2EQCh. 16.4 - Prob. 3EQCh. 16.5 - Prob. 1CCCh. 16 - Prob. 1TYCh. 16 - During which phase of nuclear division does the...Ch. 16 - Prob. 3TYCh. 16 - Which of Mendels laws cannot be observed in a...Ch. 16 - During a __________blank, an individual with the...Ch. 16 - Prob. 6TYCh. 16 - Prob. 7TYCh. 16 - A hypothetical flowering plant species produces...Ch. 16 - Genes located on a sex chromosome are said to be...Ch. 16 - Prob. 10TYCh. 16 - Prob. 1CQCh. 16 - A cross is made between individuals having the...Ch. 16 - Core Concept: Systems We can view life as a...Ch. 16 - Discuss the principles of the chromosome theory of...Ch. 16 - When examining a human pedigree, what patterns do...
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- SET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b plant color booster vs. non-booster +/lg with ligule vs. without ligule +/v green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg b + lg b v lg + + lg 305 148 58 bv + + + + 62 + v + b + + 152 275 1000 Total Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.arrow_forwardGive only typing answer with explanation and conclusion to all parts Two true-breeding varieties of maize, one 11 cm high and the other 47 cm high were crossed and the resultant F1 hybrids were then crossed to generate the F2 . In the F2 there were a total of 13,923 plants with a continuous variation in heights between the two extremes and with only 3 plants as large as 47 cm high and 5 plants of 11 cm high. a) How many i) genes and ii) how many alleles are involved in determining height in this plant? b) What is the contribution of each dominant allele to the phenotype in cm?arrow_forwardYou have already localized the genes to the same chromosome by deletion mapping, and now decide that the best way to accomplish the mapping is to conduct two simultaneous three-point testcross experiments. The genes you are investigating are as follows: N = round leaves, n = notched leaves; H = smooth stems, h = hairy stems; R = purple flowers, r = red flowers; B = grey seeds, b = black seeds; and Y = green pods, y = yellow pods. Earlier experiments you have done already established that gene B is in the middle of this gene cluster, so you design both three-point test crosses to include that gene. Cross #1 is designed as RrHhBb x rrhhbb while cross #2 is NnBbYy x nnbbyy. The results of both crosses are given in the table below. Based on the information given, determine the arrangement of these five genes including the position of each allele in the heterozygous fly and the distances between each pair of genes. (Hint: treat each experiment separately, knowing that gene B is in the…arrow_forward
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