Organic Chemistry (9th Edition)
9th Edition
ISBN: 9780321971371
Author: Leroy G. Wade, Jan W. Simek
Publisher: PEARSON
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Textbook Question
Chapter 16.12, Problem 16.22P
Ciprofloxacin is a member of the fluoroquinolone class of antibiotics.
- a. Which of its rings are aromatic?
- b. Which nitrogen atoms are basic?
- c. Which protons would you expect to appear between δ6 and δ8 in the proton NMR spectrum?
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4. HCl is known to give addition reactions to carbon-carbon double bonds. Why is this behavior not observed in this reaction?
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Chapter 16 Solutions
Organic Chemistry (9th Edition)
Ch. 16.2 - Prob. 16.1PCh. 16.2 - Prob. 16.2PCh. 16.2 - a. Draw the resonance forms of benzene,...Ch. 16.2 - Show the product of the Diels-Alder dimerization...Ch. 16.4 - Prob. 16.5PCh. 16.6 - Make a model of cyclooctatetraene in the tub...Ch. 16.6 - Prob. 16.7PCh. 16.6 - Prob. 16.8PCh. 16.7 - Prob. 16.9PCh. 16.8A - a. Draw the molecular orbitals for the...
Ch. 16.8A - Repeat Problem16-10 for the cyclopentadienyl ions....Ch. 16.8C - Explain why each compound or ion should be...Ch. 16.8C - The following hydrocarbon has an unusually large...Ch. 16.8C - Prob. 16.14PCh. 16.8C - Prob. 16.15PCh. 16.9B - Prob. 16.16PCh. 16.9C - Show which of the nitrogen atoms in purine are...Ch. 16.9C - The proton NMR spectrum of 2-pyridone gives the...Ch. 16.9D - Prob. 16.19PCh. 16.9D - Prob. 16.20PCh. 16.10 - Prob. 16.21PCh. 16.12 - Ciprofloxacin is a member of the fluoroquinolone...Ch. 16.13 - Draw and name all the chlorinated benzenes having...Ch. 16.13 - Name the following compounds:Ch. 16.15 - The UV spectrum of 1-phenylprop-2-en-1-ol shows an...Ch. 16 - Prob. 16.26SPCh. 16 - Name the following compounds:Ch. 16 - Draw and name all the methyl, dimethyl, and...Ch. 16 - Four pairs of compounds are shown. In each pair,...Ch. 16 - One of the following hydrocarbons is much more...Ch. 16 - In Kekuls time cyclohexane was unknown, and there...Ch. 16 - Prob. 16.32SPCh. 16 - Azulene is a deep-blue hydrocarbon with resonance...Ch. 16 - Prob. 16.34SPCh. 16 - Prob. 16.35SPCh. 16 - Prob. 16.36SPCh. 16 - Prob. 16.37SPCh. 16 - Prob. 16.38SPCh. 16 - Prob. 16.39SPCh. 16 - Biphenyl has the following structure. a. Is...Ch. 16 - Anions of hydrocarbons are rare, and dianions of...Ch. 16 - How would you convert the following compounds to...Ch. 16 - Prob. 16.43SPCh. 16 - Prob. 16.44SPCh. 16 - A student found an old bottle labeled thymol on...Ch. 16 - Prob. 16.46SPCh. 16 - Prob. 16.47SPCh. 16 - Prob. 16.48SPCh. 16 - The proton NMR chemical shifts of the hydrogens in...Ch. 16 - Prob. 16.50SPCh. 16 - NMR has been used to probe many molecular...
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- Use the observed 1H NMR data to decide whether C and its dianion are aromatic, antiaromatic, or not aromatic. C shows NMR signals at –4.25 (6 H) and 8.14–8.67 (10 H) ppm. The dianion of C shows NMR signals at –3 (10 H) and 21 (6 H) ppm. Why are the signals shifted upfield (or downfield) to such a large extent?arrow_forwardUse the observed 1H NMR data to decide whether C and its dianion are aromatic, antiaromatic, or not aromatic. C shows NMR signals at –4.25 (6 H) and 8.14–8.67 (10 H) ppm. The dianion of C shows NMR signals at –3 (10 H) and 21 (6 H) ppm. Why are the signals shifted upeld (or downeld) to such a large extent?arrow_forwardUse the four compounds shown below to answer the following questions: a. Why are the ortho-halo-substituted benzoic acids stronger acids than benzoic acid? b. Why is o-fluorobenzoic acid the weakest of the ortho-halo-substituted benzoic acids? c. Why do o-chlorobenzoic acid and o-bromobenzoic acid have similar pKa values?arrow_forward
- Use the four compounds shown below to answer the following questions: a. Why are the ortho-halo-substituted benzoic acids stronger acids than benzoic acid?b. Why is o-fluorobenzoic acid the weakest of the ortho-halo-substituted benzoic acids?c. Why do o-chlorobenzoic acid and o-bromobenzoic acid have similar pKa values?arrow_forwardStanozolol is an anabolic steroid that promotes muscle growth. Although stanozolol has been used by athletes and body builders, many physical and psychological problems result from prolonged use and it is banned in competitive sports. a. Explain why the nitrogen heterocycle—a pyrazole ring—is aromatic. b. In what type of orbital is the lone pair on each N atom contained? c. Draw all reasonable resonance structures for stanozolol. d. Explain why the pKa of the N – H bond in the pyrazole ring is comparable to the pKa of the O–H bond, making it considerably more acidic than amines such as CH3NH2 (pKa = 40).arrow_forwardStanozolol is an anabolic steroid that promotes muscle growth. Although stanozolol has been used by athletes and body builders, many physical and psychological problems result from prolonged use and it is banned in competitive sports. a.Explain why the nitrogen heterocycle—a pyrazole ring—is aromatic. b.In what type of orbital is the lone pair on each N atom contained? c. Draw all reasonable resonance structures for stanozolol. d.Explain why the pKa of the N—H bond in the pyrazole ring is comparable to the pKa of the O—H bond, making it considerably more acidic than amines such as CH3NH2 (pKa = 40).arrow_forward
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- Assume a compound with the formula C4H8O. a) How many double bonds and/or rings does your compound contain? b) If your compound shows an infrared absorption peak at 1715 cm-1, what functional group does it have? c) If your compound shows a single 1H NMR absorption peak at 2.1 δ, what is its structure?arrow_forward1. Predict the maximum total number of possible peaks in the 1H NMR spectrum of sesamin a. Indicate the number of non-aromatic peaks in the 1H NMR of sesamin b. Indicate the number of aromatic peaks in the 1H NMR of sesaminarrow_forwardArrange the compounds in each set in order of increasing acid strength. consult Table 4.1 for pKa values of each acid.arrow_forward
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NMR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=SBir5wUS3Bo;License: Standard YouTube License, CC-BY