ORGANIC CHEMISTRY-STUDY GDE./SOL.MAN.
ORGANIC CHEMISTRY-STUDY GDE./SOL.MAN.
6th Edition
ISBN: 9780072397475
Author: SMITH
Publisher: MCG
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Chapter 16.6, Problem 14P
Interpretation Introduction

(a)

Interpretation: Whether the given substituent exhibits an electron-withdrawing or an electron-donating inductive effect is to be identified.

Concept introduction: The atoms which are more electronegative than carbon pull charge density away from carbon and exhibit an electron-withdrawing inductive effect. Alkyl groups donate electron density, thus exhibit an electron donation inductive effect.

Interpretation Introduction

(b)

Interpretation: Whether the given substituent exhibits an electron-withdrawing or an electron-donating inductive effect is to be identified.

Concept introduction: The atoms which are more electronegative than carbon pull charge density away from carbon and exhibit an electron-withdrawing inductive effect. Alkyl groups donate electron density, thus exhibit an electron donation inductive effect.

Interpretation Introduction

(c)

Interpretation: Whether the given substituent exhibits an electron-withdrawing or an electron-donating inductive effect is to be identified.

Concept introduction: The atoms which are more electronegative than carbon pull charge density away from carbon and exhibit an electron-withdrawing inductive effect. Alkyl groups donate electron density, thus exhibit an electron donation inductive effect.

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Using the data in Appendix C, determine which of the following bases is strong enough to deprotonate acetonitrile (CH3CN), so that equilibrium favors the products: (a) NaH; (b) Na2CO3; (c) NaOH; (d) NaNH2; (e) NaHCO3.
Complete each acid-base reaction and predict whether the position of equilibrium lies toward the left or toward the right.
Predict the products of the following acid-base reactions. If the equilibrium would not result in the formation of appreciable amounts of products, you should so indicate. In each case label the stronger acid, the stronger base, the weaker acid, and the weaker base: (a) CH3CH=CH2 + NANH2 (d) CH3C=C: + CH;CH2OH → (e) CH3C=C:- + NH¾CI – | (b) CH;C=CH + NaNH2 (c) CH3CH2CH3 + NANH2 → | HAS

Chapter 16 Solutions

ORGANIC CHEMISTRY-STUDY GDE./SOL.MAN.

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