Chapter 1.7, Problem 10CYU

(a)

To determine

To find:The domain and range of the relation

Explanation of Solution

The number of pictures $x$ must be a whole number, the domain is all the whole number.

  $y=0.13x$

So, the range is the multiples of $0.13$ that are greater than or equal to zero.

The relation is a function since each value of $x$ corresponds to only one value of $y$ .

(b)

To determine

To write:The equation in function notation.

Explanation of Solution

Replace $y$ with $f\left(x\right)$ to write the equation in function notation.

  $f\left(x\right)=0.13x$ .

The function is interpreted as each picture costs $\$0.13$ to print since the cost goes of $\$0.13$ for every addition picture that printed.

Therefore, the equation in function notation is $f\left(x\right)=0.13x$ .

(c)

To determine

To find:The value of $f\left(5\right)$ and $f\left(12\right)$ .

Explanation of Solution

The value of $f\left(5\right)$ is calculated as,

  $\begin{array}{c}f\left(5\right)=0.13\left(5\right)\\ =0.65\end{array}$

This means the cost of printing $5$ pictures is $\$0.65$ .

The value of $f\left(12\right)$ is calculated as,

  $\begin{array}{c}f\left(12\right)=0.13\left(12\right)\\ =1.56\end{array}$

This means the cost of printing $12$ pictures is $\$1.56$ .