Chapter 18, Problem 18.122SP

Interpretation Introduction

(a)

Interpretation:

The equilibrium pressure of ${\text{CO}}_{\text{2}}$ when temperature of container is $25°\text{C}$ is to be calculated.

Concept introduction:

The relationship between standard free energy change and equilibrium pressure is as follows:

$\Delta G^{\text{o}}=-RT\ln K_{\text{p}}$

Where,

• $\Delta G^{\text{o}}$ is standard free energy change.
• $R$ is universal gas constant.
• $T$ is absolute temperature.
• $K_{\text{p}}$ is equilibrium pressure.

Interpretation Introduction

(b)

Interpretation:

The equilibrium pressure of ${\text{CO}}_{\text{2}}$ when $\text{15}\text{g}{\text{MgCO}}_3$ and $\text{1}\text{g}\text{MgO}$ are mixed at $280°\text{C}$ is to be determined.

Concept introduction:

The relationship between standard free energy change and equilibrium pressure is as follows:

$\Delta G^{\text{o}}=-RT\ln K_{\text{p}}$

Where,

• $\Delta G^{\text{o}}$ is standard free energy change.
• $R$ is universal gas constant.
• $T$ is absolute temperature.
• $K_{\text{p}}$ is equilibrium pressure.

Interpretation Introduction

(c)

Interpretation:

The equilibrium pressure of ${\text{CO}}_{\text{2}}$ when $\text{30}\text{g}{\text{MgCO}}_3$ and $\text{1}\text{g}\text{MgO}$ are mixed at $280°\text{C}$ is to be determined.

Concept introduction:

The relationship between standard free energy change and equilibrium pressure is as follows:

$\Delta G^{\text{o}}=-RT\ln K_{\text{p}}$

Where,

• $\Delta G^{\text{o}}$ is standard free energy change.
• $R$ is universal gas constant.
• $T$ is absolute temperature.
• $K_{\text{p}}$ is equilibrium pressure.