Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Question
Chapter 18, Problem 27P
To determine
The mass of the air in bedroom.
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Chapter 18 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 18.1 - Prob. 18.1QQCh. 18.3 - Consider the following pairs of materials. Which...Ch. 18.4 - If you are asked to make a very sensitive glass...Ch. 18.4 - Prob. 18.4QQCh. 18.5 - A common material for cushioning objects in...Ch. 18.5 - On a winter day, you turn on your furnace and the...Ch. 18 - Prob. 1PCh. 18 - Prob. 2PCh. 18 - Prob. 3PCh. 18 - Liquid nitrogen has a boiling point of 195.81C at...
Ch. 18 - Prob. 5PCh. 18 - Prob. 6PCh. 18 - A copper telephone wire has essentially no sag...Ch. 18 - Prob. 8PCh. 18 - The Trans-Alaska pipeline is 1 300 km long,...Ch. 18 - Prob. 10PCh. 18 - Prob. 11PCh. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - Why is the following situation impossible? A thin...Ch. 18 - A volumetric flask made of Pyrex is calibrated at...Ch. 18 - Review. On a day that the temperature is 20.0C, a...Ch. 18 - Prob. 17PCh. 18 - Prob. 18PCh. 18 - An auditorium has dimensions 10.0 m 20.0 m 30.0...Ch. 18 - Prob. 20PCh. 18 - Prob. 21PCh. 18 - Prob. 22PCh. 18 - In state-of-the-art vacuum systems, pressures as...Ch. 18 - Prob. 24PCh. 18 - Prob. 25PCh. 18 - Prob. 26PCh. 18 - Prob. 27PCh. 18 - Prob. 28PCh. 18 - The pressure gauge on a cylinder of gas registers...Ch. 18 - Prob. 30APCh. 18 - Prob. 31APCh. 18 - Why is the following situation impossible? An...Ch. 18 - A student measures the length of a brass rod with...Ch. 18 - Prob. 34APCh. 18 - A liquid has a density . (a) Show that the...Ch. 18 - Prob. 36APCh. 18 - Prob. 37APCh. 18 - A bimetallic strip of length L is made of two...Ch. 18 - Prob. 39APCh. 18 - A vertical cylinder of cross-sectional area A is...Ch. 18 - Prob. 41APCh. 18 - Prob. 42APCh. 18 - Prob. 43APCh. 18 - Prob. 44CPCh. 18 - A 1.00-km steel railroad rail is fastened securely...Ch. 18 - Prob. 46CP
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- A deepsea diver should breathe a gas mixture that has the same oxygen partial pressure as at sea level, where dry air contains 20.9% oxygen and has a total pressure of 1.01105N/m2. (a) What is me partial pressure of oxygen at sea level? (b) If the diver breathes a gas mixture at a pressure of 2.00106N/m2, what percent oxygen should it be to have the same oxygen partial pressure as at sea level?arrow_forwardA liquid with a coefficient of volume expansion just fills a spherical shell of volume V(Fig. P19.51). The shell and the open capillary of area A projecting from the top of the sphere are made of a material with an average coefficient of linear expansion . The liquid is free to expand into the capillary. Assuming the temperature increases by T find the distance h the liquid rises in the capillary.arrow_forwardThere are two important isotopes of uranium 235U and 238U ; these isotopes are nearly identical chemically but have different atomic masses. Only 235U is very useful in nuclear reactors. One of the techniques for separating them (gas diffusion) is based on the different average velocities vrms of uranium hexafluoride gas. UF6. (a) The molecular masses for 235UUF6 and 238UUF6 are 349.0g/mol and 352.0g/mol, respectively. What is the ratio of their average velocities? (b) At what temperature would their average velocities differ by 1.00m/s ? (c) Do your answers in this problem imply that this technique may be difficult?arrow_forward
- (a) Show that the density of an ideal gas occupying a volume V is given by = PM/KT, where M is the molar mass. (b) Determine the density of oxygen gas at atmospheric pressure and 20.0C.arrow_forwardAtmospheric pressure amp Mt. Everest is 3.30104N/m2. (a) What is the partial pressure of oxygen there if it is 20.9% at me air? (b) What percent oxygen should a mountain climber breathe so that its partial pressure is the same as at sea level, where atmospheric pressure is 1.01105N/m2 ? (c) One of the most severe problems for those climbing very high mountains is the extreme drying of breathing passages. Why does this drying occur?arrow_forwardA gas is in a container of volume V0 at pressure P0. It is being pumped out of the container by a piston pump. Each stroke of the piston removes a volume Vs through valve A and then pushes the air out through valve B as shown in Figure P19.74. Derive an expression that relates the pressure Pn of the remaining gas to the number of strokes n that have been applied to the container. FIGURE P19.74arrow_forward
- Figure P20.45 shows a phase diagram of carbon dioxide in terms of pressure and temperature, a. Use the phase diagram to explain why dry ice (solid carbon dioxide) sublimates into vapor at atmospheric pressure rather than melting into a liquid. At what temperature does the dry ice sublimate when at atmospheric pressure? b. Estimate what pressure would be needed to liquefy carbon dioxide at room temperature.arrow_forwardA sealed cubical container 20.0 cm on a side contains a gas with three times Avogadros number of neon atoms at a temperature of 20.0C. (a) Find the internal energy of the gas. (b) Find the total translational kinetic energy of the gas. (c) Calculate the average kinetic energy per atom, (d) Use Equation 10.13 to calculate the gas pressure. (e) Calculate the gas pressure using the ideal gas law (Eq. 10.8).arrow_forwardThe pressure gauge on a cylinder of gas registers the gauge pressure, which is the difference between the interior pressure and the exterior pressure P0. Lets call the gauge pressure Pg. When the cylinder is full, the mass of the gas in it is mi at a gauge pressure of Pgi. Assuming the temperature of the cylinder remains constant, show that the mass of the gas remaining in the cylinder when the pressure reading is Pgf is given by mf=mi(Pgf+P0Pgi+P0)arrow_forward
- (a) Find the average time required for an oxygen molecule to diffuse through a 0.200-mm-thick tear layer on the cornea. (b) How much time is required to diffuse 0.500 cm3 of oxygen to the cornea if its surface area is 1.00 cm2?arrow_forwardIn the chapter on fluid mechanics, Bernoulli's equation for the flow of incompressible fluids was explained in terms of changes affecting a small volume dV of fluid. Such volumes are a fundamental idea in the study of the flow of compressible fluids such as gases as well. For the equations of hydrodynamics to apply, the mean free path must be much less than the linear size of such a volume, adV1/3 . For air in the stratosphere at a temperature of 220 K and a pressure of 5.8 kPa, how big should a be for it to be 100 times the mean free path? Take the effective radius of air molecules to be 1.881011 m, which is roughly correct for N2.arrow_forwardConsider again the box and particles with the speed distribution described in Problem 56. a. What is the average pressure exerted by the particles on the walls of the box? b. What is the average kinetic energy per particle in this box?arrow_forward
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