(a)
Calculate
(b)
Calculate
Interpretation:
The standard free energy change and the equilibrium constant, at a constant pressure
Concept introduction:
For a general chemical reaction,
The reaction quotient in terms of partial pressure can be represented as
The general formula for writing equilibrium expression for the reaction is given as follows:
The standard free energy change of the reaction is the difference between the sums of the standard free energy change of the products and the standard free energy change of the reactants.
The relation between free energy change and standard free energy change is as follows:
Here,
Answer to Problem 45QP
Solution:
a)
b)
Explanation of Solution
a) Value of
The given reaction, for which
The standard free energy changes for the formation of
The Gibbs free energy of the reaction is calculated as
The reaction quotient for the above reaction is represented as
The relation between free energy change and standard free energy change is as
The value of
So, the above expression is reduced to the following expression:
Substitute all the values in the above expression
Again, solving further, we get
Thus, the
b) Value of
The given equilibrium reaction is as follows:
The reaction quotient for the above reaction is represented as
The partial pressures of
Substitute all the values of partial pressure in the above expression
The relation between free energy change and standard free energy change is as follows:
Thus, the Gibbs free energy for the given equilibrium reaction at a temperature of
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Chapter 18 Solutions
Package: Chemistry With Aleks 360 Access Card, 2-semester
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