   # The mass defect for a lithium-6 nucleus is −0.03434 g/mol. Calculate the atomic mass of 6 Li. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 18, Problem 47E
Textbook Problem
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## The mass defect for a lithium-6 nucleus is −0.03434 g/mol. Calculate the atomic mass of 6Li.

Interpretation Introduction

Interpretation: The mass defect of 6Li is given. The atomic mass of 6Li is to be calculated.

Concept introduction: The sum of masses of the component nucleons and the actual mass of a nucleus is known as the mass defect and it can be used to calculate the nuclear binding energy.

To determine: The atomic mass of 6Li .

### Explanation of Solution

Explanation

The mass defect (Δm) is 0.03434g/mol .

The atomic mass of 11H=1.0078amu

The mass of a neutron is 1.0087amu .

The mass of 36Li is assumed to be x .

Number of protons in 36Li=3

Number of neutrons in 36Li=3

The atomic mass is calculated by the formula,

Δm=Mass of 12Li[(Numberofprotons×massof11H)Numberofneutrons×massofneutron] (1)

The conversion of g to amu is,

1.66×1024g=1amu1g=11.66×1024amu

Therefore, the conversion of 0.03434g to amu is,

0

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