a. Explanation Given data: Angle of incident of laser pointer on the aquarium is 45 ° . Refractive index of glass is 1.55. Draw the diagram as shown in Figure 1 to find the angle at which the beam from laser pointer enters the water. By using Snell’s law, n air n glass = sin θ glass sin θ air sin θ air sin θ glass = n glass n air sin θ glass = n air n glass × sin θ air θ glass = sin − 1 ( n air n glass × sin θ air ) Here, n glass is the refractive index of glass, given as 1.55, and n air is the refractive index of air, which has standard value as 1. Substitute 1.55 for n glass , 1 for n air , and 45 ° for θ air , θ glass = sin − 1 ( 1 1.55 × sin 45 ° ) = sin − 1 ( 1 1.55 × 0.707 ) = sin − 1 ( 0.456 ) = 27 b. To determine To check: Whether the angle at which the beam enters the water inside the aquarium depends on the refractive index of the glass or not.

3rd Edition

ISBN: 9780321907233

Author: Field

Publisher: YUZU

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Chapter 18, Problem 47GP

To determine

The angle at which the beam from laser pointer enters the water inside the aquarium.

To determine

To check: Whether the angle at which the beam enters the water inside the aquarium depends on the refractive index of the glass or not.

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Chapter 18, Problem 46GP

Chapter 18, Problem 48GP

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Chapter 18 Solutions

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The angle at which the beam from laser pointer enters the water inside the aquarium.

Solution Summary: The author explains the angle at which the beam from laser pointer enters the water inside the aquarium.

The angle at which the beam from laser pointer enters the water inside the aquarium.

To check: Whether the angle at which the beam enters the water inside the aquarium depends on the refractive index of the glass or not.

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Chapter 18 Solutions