Chemistry: Atoms First
Chemistry: Atoms First
2nd Edition
ISBN: 9780073511184
Author: Julia Burdge, Jason Overby Professor
Publisher: McGraw-Hill Education
Question
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Chapter 18.4, Problem 18.4WE
Interpretation Introduction

Interpretation:

The standard free energy change of the given reaction should be calculated.

Concept introduction:

  • The substance that easily be reduced in a reaction is represented as an oxidizing agent. For metal cations, a good oxidizing agent can be determined by the standard reduction potential values.
  • Half-cell: In the electrochemical cell, both oxidation and reduction occurs. Oxidation occurs at the anode and reduction occurs at the cathode
  • Standard electrode potential of cell is defined as the difference of reduction potential at cathode to the reduction potential at anode.
  • For the cathode and anode reactions, the values are taken from the standard reduction potential table. The standard cell potential is calculated by taking the difference between the standard reduction potential values of the cathode and anode.

Ecell0=Ecathode0Eanode0

  • ΔG0=nFEcell0ΔG0=Standardfreeenergy changeEcell0=StandardelectrochemicalcellpotentialF=Faradayconstantn=numberofelectronspassedfromanodetocathode

Expert Solution & Answer
Check Mark

Answer to Problem 18.4WE

The standard free energy change is 2.53×103kJ/mol

Explanation of Solution

There are two half-cell reactions involved

At anode,

2Au(s)2Au(aq)3++6eEanode0=1.50V

At cathode,

3Ca(aq)2++6e3Ca(s)Ecathode0=2.87V

ΔG0 is calculated for the above reaction.

Given,

From standard reduction potential table,

Eanode0=EAu3+/Au0=1.50V

Ecathode0=ECa2+/Ca0=2.87V

Ecell0 for equation can be calculated by using the given equation,

Ecell0=Ecathode0Eanode0=ECa2+/Ca0EAu3+/Au0=2.87V1.50V=4.37V

ΔG0 can be calculated by using the given equation,

ΔG0=nFEcell0ΔG0=Standardfreeenergy changeEcell0=StandardelectrochemicalcellpotentialF=Faradayconstantn=numberofelectronspassedfromanodetocathode

Therefore,

ΔG0=(6mole)×(96500J/Vmole)×(4.37V)=2.53×106J/mol=2.53×103kJ/mol

The standard free energy change is 2.53×103kJ/mol

Conclusion

The standard free energy change was calculated as 2.53×103kJ/mol

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Chapter 18 Solutions

Chemistry: Atoms First

Ch. 18.3 - Prob. 18.3WECh. 18.3 - Prob. 3PPACh. 18.3 - Prob. 3PPBCh. 18.3 - Prob. 3PPCCh. 18.3 - Prob. 18.3.1SRCh. 18.3 - Prob. 18.3.2SRCh. 18.3 - Prob. 18.3.3SRCh. 18.3 - Prob. 18.3.4SRCh. 18.4 - Prob. 18.4WECh. 18.4 - Prob. 4PPACh. 18.4 - Prob. 4PPBCh. 18.4 - Prob. 4PPCCh. 18.4 - Prob. 18.5WECh. 18.4 - Prob. 5PPACh. 18.4 - Prob. 5PPBCh. 18.4 - Prob. 5PPCCh. 18.4 - Prob. 18.4.1SRCh. 18.4 - Prob. 18.4.2SRCh. 18.5 - Prob. 18.6WECh. 18.5 - Prob. 6PPACh. 18.5 - Prob. 6PPBCh. 18.5 - Prob. 6PPCCh. 18.5 - Prob. 18.7WECh. 18.5 - Prob. 7PPACh. 18.5 - Prob. 7PPBCh. 18.5 - Prob. 7PPCCh. 18.5 - Prob. 18.5.1SRCh. 18.5 - Prob. 18.5.2SRCh. 18.5 - Prob. 18.5.3SRCh. 18.5 - Prob. 18.5.4SRCh. 18.7 - Prob. 18.8WECh. 18.7 - Prob. 8PPACh. 18.7 - Prob. 8PPBCh. 18.7 - Prob. 8PPCCh. 18.7 - Prob. 18.7.1SRCh. 18.7 - Prob. 18.7.2SRCh. 18.7 - Prob. 18.7.3SRCh. 18 - Balance the following redox equations by the...Ch. 18 - Balance the following redox equations by the...Ch. 18 - In the first scene of the animation, when a zinc...Ch. 18 - What causes the change in the potential of the...Ch. 18 - Why does the color of the blue solution in the...Ch. 18 - Prob. 18.4VCCh. 18 - Define the following terms: anode, cathode, cell...Ch. 18 - Prob. 18.4QPCh. 18 - Prob. 18.5QPCh. 18 - What is a cell diagram? Write the cell diagram for...Ch. 18 - What is the difference between the half-reactions...Ch. 18 - Discuss the spontaneity of an electrochemical...Ch. 18 - Prob. 18.9QPCh. 18 - Prob. 18.10QPCh. 18 - Calculate the standard emf of a cell that uses...Ch. 18 - Prob. 18.12QPCh. 18 - Prob. 18.13QPCh. 18 - Consider the following half-reactions....Ch. 18 - Predict whether NO3 ions will oxidize Mn2+ to MnO4...Ch. 18 - Prob. 18.16QPCh. 18 - Prob. 18.17QPCh. 18 - Prob. 18.18QPCh. 18 - Prob. 18.19QPCh. 18 - Use the information m Table 2.1, and calculate the...Ch. 18 - Prob. 18.21QPCh. 18 - Prob. 18.22QPCh. 18 - Use the standard reduction potentials to find the...Ch. 18 - Calculate G and Kc for the following reactions at...Ch. 18 - Under standard state conditions, what spontaneous...Ch. 18 - Prob. 18.26QPCh. 18 - Balance (in acidic medium) the equation for the...Ch. 18 - Prob. 18.28QPCh. 18 - Prob. 18.29QPCh. 18 - Write the Nernst equation for the following...Ch. 18 - What is the potential of a cell made up of Zn/Zn2+...Ch. 18 - Calculate E, E, and G for the following cell...Ch. 18 - Calculate the standard potential of the cell...Ch. 18 - What is the emf of a cell consisting of a Pb2+/Pb...Ch. 18 - Prob. 18.35QPCh. 18 - Calculate the emf of the following concentration...Ch. 18 - What is a battery? Describe several types of...Ch. 18 - Explain the differences between a primary galvanic...Ch. 18 - Discuss the advantages and disadvantages of fuel...Ch. 18 - The hydrogen-oxygen fuel cell is described in...Ch. 18 - Calculate the standard emf of the propane fuel...Ch. 18 - What is the difference between a galvanic cell...Ch. 18 - Prob. 18.43QPCh. 18 - Calculate the number of grams of copper metal that...Ch. 18 - Prob. 18.45QPCh. 18 - Consider the electrolysis of molten barium...Ch. 18 - Prob. 18.47QPCh. 18 - Prob. 18.48QPCh. 18 - Prob. 18.49QPCh. 18 - How many faradays of electricity are required to...Ch. 18 - Calculate the amounts of Cu and Br2 produced in...Ch. 18 - Prob. 18.52QPCh. 18 - Prob. 18.53QPCh. 18 - A constant electric current flows for 3.75 h...Ch. 18 - What is the hourly production rate of chlorine gas...Ch. 18 - Chromium plating is applied by electrolysis to...Ch. 18 - The passage of a current of 0.750 A for 25.0 min...Ch. 18 - A quantity of 0.300 g of copper was deposited from...Ch. 18 - In a certain electrolysis experiment, 1.44 g of Ag...Ch. 18 - Prob. 18.60QPCh. 18 - Prob. 18.61QPCh. 18 - Prob. 18.62QPCh. 18 - Tarnished silver contains Ag2S. The tarnish can be...Ch. 18 - Prob. 18.64QPCh. 18 - For each of the following redox reactions, (i)...Ch. 18 - Prob. 18.66QPCh. 18 - Prob. 18.67QPCh. 18 - Prob. 18.68QPCh. 18 - Prob. 18.69QPCh. 18 - Prob. 18.70QPCh. 18 - Prob. 18.71QPCh. 18 - Prob. 18.72QPCh. 18 - Prob. 18.73QPCh. 18 - Prob. 18.74QPCh. 18 - A galvanic cell consists of a silver electrode in...Ch. 18 - Explain why chlorine gas can be prepared by...Ch. 18 - Prob. 18.77QPCh. 18 - Prob. 18.78QPCh. 18 - Prob. 18.79QPCh. 18 - Prob. 18.80QPCh. 18 - Prob. 18.81QPCh. 18 - Prob. 18.82QPCh. 18 - An acidified solution was electrolyzed using...Ch. 18 - Prob. 18.84QPCh. 18 - Consider the oxidation of ammonia....Ch. 18 - Prob. 18.86QPCh. 18 - Prob. 18.87QPCh. 18 - Prob. 18.88QPCh. 18 - Prob. 18.89QPCh. 18 - Prob. 18.90QPCh. 18 - Prob. 18.91QPCh. 18 - Prob. 18.92QPCh. 18 - An aqueous solution of a platinum salt is...Ch. 18 - Prob. 18.94QPCh. 18 - Prob. 18.95QPCh. 18 - Prob. 18.96QPCh. 18 - Prob. 18.97QPCh. 18 - A silver rod and a SHE are dipped into a saturated...Ch. 18 - Prob. 18.99QPCh. 18 - Prob. 18.100QPCh. 18 - The magnitudes (but not the signs) of the standard...Ch. 18 - Prob. 18.102QPCh. 18 - Given the standard reduction potential for Au3+ in...Ch. 18 - Prob. 18.104QPCh. 18 - Prob. 18.105QPCh. 18 - Prob. 18.106QPCh. 18 - Prob. 18.107QPCh. 18 - Prob. 18.108QPCh. 18 - Prob. 18.109QPCh. 18 - Prob. 18.110QPCh. 18 - Prob. 18.111QPCh. 18 - In recent years there has been much interest in...Ch. 18 - Prob. 18.113QPCh. 18 - Prob. 18.114QPCh. 18 - Prob. 18.115QPCh. 18 - Prob. 18.116QPCh. 18 - Prob. 18.117QPCh. 18 - A galvanic cell using Mg/Mg2+ and Cu/Cu2+...Ch. 18 - Prob. 18.119QPCh. 18 - Prob. 18.120QPCh. 18 - Lead storage batteries arc rated by ampere-hours,...Ch. 18 - Use Equations 14.10 and 18.3 to calculate the emf...Ch. 18 - Prob. 18.123QPCh. 18 - A 9.00 102 mL amount of 0.200 M MgI2 solution was...Ch. 18 - Prob. 18.125QPCh. 18 - Which of the components of dental amalgam...Ch. 18 - Calculate the equilibrium constant for the...Ch. 18 - Prob. 18.128QPCh. 18 - Prob. 18.129QPCh. 18 - Prob. 18.130QPCh. 18 - Prob. 18.131QPCh. 18 - Prob. 18.1KSPCh. 18 - Prob. 18.2KSPCh. 18 - Prob. 18.3KSPCh. 18 - Prob. 18.4KSP
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