Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 18.SE, Problem 61GP
Interpretation Introduction
Interpretation:
Given that Grignard reagents react with oxetane to yield primary alcohols, but the reaction is much slower than the corresponding reaction with ethylene oxide. The reason for the difference in reactivity between oxenate and ethylene oxide is to be suggested.
Concept introduction:
The ring size of cyclic compound has a great influence on its reactivity. Normally cyclic compounds with rings made up of 3 or 4 of carbon atoms are less stable and react fast as the strain in the molecule is relieved when the ring opens by reaction.
To suggest:
The reason for the difference in reactivity between oxenate and ethylene oxide when they are treated with Grignard reagents. Oxenate reacts much slower than ethylene oxide.
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Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2 SO4 gives E (C10 H16), which decolorizes two equivalents of Br2 to give F (C10H16 Br4). E undergoes hydrogenation with excess H2 and a Pt catalyst to give isobutylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.
Chapter 18 Solutions
Organic Chemistry
Ch. 18.1 - Name the following ethers:Ch. 18.2 - Why do you suppose only symmetrical ethers are...Ch. 18.2 - How would you prepare the following ethers using a...Ch. 18.2 - Review the mechanism of oxymercuration shown in...Ch. 18.2 - How would you prepare the following ethers? Use...Ch. 18.2 - Prob. 6PCh. 18.3 - Prob. 7PCh. 18.3 - Write the mechanism of the acid-induced cleavage...Ch. 18.3 - Why are HI and HBr more effective than HCl in...Ch. 18.4 - What product would you expect from Claisen...
Ch. 18.5 - Prob. 11PCh. 18.6 - Predict the major product of each of the following...Ch. 18.6 - Prob. 13PCh. 18.6 - Predict the major product of the following...Ch. 18.7 - 15-Crown-5 and 12-crown-4 ethers complex Na+ and...Ch. 18.8 - Prob. 16PCh. 18.8 - 2-Butene-l-thiol is one component of skunk spray....Ch. 18.9 - The 1H NMR spectrum shown is that of a cyclic...Ch. 18.SE - Give IUPAC names for the following compounds...Ch. 18.SE - Show the product, including stereochemistry, that...Ch. 18.SE - Prob. 21VCCh. 18.SE - Treatment of the following alkene with a...Ch. 18.SE - Prob. 23MPCh. 18.SE - Prob. 24MPCh. 18.SE - Predict the product(s) and provide the mechanism...Ch. 18.SE - The alkoxymercuration of alkenes involves the...Ch. 18.SE - Predict the product(s) and provide the mechanism...Ch. 18.SE - Predict the product(s) and provide the mechanism...Ch. 18.SE - Prob. 29MPCh. 18.SE - Ethers undergo an acid-catalyzed cleavage reaction...Ch. 18.SE - Treatment of 1, 1-diphenyl-l, 2-epoxyethane with...Ch. 18.SE - Fluoxetine, a heavily prescribed antidepressant...Ch. 18.SE - When 2-methyl-2, 5-pentanediol is treated with...Ch. 18.SE - Prob. 34MPCh. 18.SE - Prob. 35MPCh. 18.SE - Aldehydes and ketones undergo acid-catalyzed...Ch. 18.SE - Propose a mechanism to account for the following...Ch. 18.SE - Prob. 38APCh. 18.SE - Prob. 39APCh. 18.SE - How would you prepare the following ethers?Ch. 18.SE - Prob. 41APCh. 18.SE - tert-Butyl ethers can be prepared by the reaction...Ch. 18.SE - Treatment of trans-2-chlorocyclohexanol with NaOH...Ch. 18.SE - Predict the products of the following ether...Ch. 18.SE - Prob. 45APCh. 18.SE - Prob. 46APCh. 18.SE - Write the mechanism of the hydrolysis of cis-5,...Ch. 18.SE - Prob. 48APCh. 18.SE - Acid-catalyzed hydrolysis of a 1,...Ch. 18.SE - Prob. 50APCh. 18.SE - Epoxides are reduced by treatment with lithium...Ch. 18.SE - Prob. 52APCh. 18.SE - The red fox (Vulpes vulpes) uses a chemical...Ch. 18.SE - Anethole, C10H12O, a major constituent of the oil...Ch. 18.SE - Propose structures for compounds that have the...Ch. 18.SE - Prob. 56GPCh. 18.SE - How would you synthesize anethole (Problem 18-54)...Ch. 18.SE - How could you prepare benzyl phenyl ether from...Ch. 18.SE - Meerwein's reagent, triethyloxonium...Ch. 18.SE - Prob. 60GPCh. 18.SE - Prob. 61GPCh. 18.SE - The Zeisel method is an old analytical procedure...Ch. 18.SE - Prob. 63GPCh. 18.SE - Prob. 64GPCh. 18.SE - Prob. 65GPCh. 18.SE - Identify the reagents a-e in the following scheme:Ch. 18.SE - Propose structures for compounds that have the...Ch. 18.SE - Prob. 68GPCh. 18.SE - Prob. 69GPCh. 18.SE - Predict the product(s) if the starting materials...
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- The first widely used herbicide for the control of weeds was 2,4-dichlorophenoxyacetic acid (2,4-D). Show how this compound might be synthesized from phenol and chloro-acetic acid by way of the given chlorinated phenol intermediate.arrow_forwardCompound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give F (C10H16Br4). E undergoes hydrogenation with excess H2 and a Pt catalyst to giveisobutylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughoutarrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data?arrow_forward
- Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. What is the isometric pair of A and B that corresponds?arrow_forwardIdentify products A and B from the given 1H NMR data.a. Treatment of CH2 = CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3 H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?b. Treatment of acetone [(CH3)2C = O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1 H) ppm. What is the structure of B?arrow_forwardIdentify products A and B from the given 1H NMR data. a.Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3 H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A? b.Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1 H) ppm. What is the structure of B?arrow_forward
- Compound A of molecular formula C8H14 is reduced by sodium in liquid ammonia to give compound B of molecular formula C8H16. product (Y).Both A and B undergo hydrogenation in the presence of a platinum catalyst to give 2,5-dimethylhexane. Ozonolysis of B with an oxidative workup produces a carboxylic acid of molecular formula C4H8O2. Reaction of B with a peroxyacid gives a chiral C8H14O product, but reaction with bromine gives an achiral C8H14Br2 product. What are the identities of A and B?arrow_forwardTreatment of cis-4-bromocyclohexanol with HO– affords compound A and cyclohex-3-en-1-ol. Treatment of trans-4- bromocyclohexanol under the same conditions forms compound B and cyclohex-3-en-1-ol. A and B contain different functional groups and are not isomers of each other. Propose structures for A and B and offer an explanation for their formation.arrow_forward
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