Organic Chemistry -Study Guide / Solution Manual (Custom)
Organic Chemistry -Study Guide / Solution Manual (Custom)
4th Edition
ISBN: 9781259141072
Author: SMITH
Publisher: MCG
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Chapter 19, Problem 19.37P

Which compound in each pair has the lower p K a ? Which compound in each pair has the stronger conjugate base?

a. Chapter 19, Problem 19.37P, Which compound in each pair has the lower pKa? Which compound in each pair has the stronger , example  1 c. Chapter 19, Problem 19.37P, Which compound in each pair has the lower pKa? Which compound in each pair has the stronger , example  2

b. ClCH 2 COOH or FCH 2 COOH d. CNCH 2 COOH or CH 3 COOH

Expert Solution
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Interpretation Introduction

(a)

Interpretation: The compound in the given pair that has lower pKa is to be predicted. The compound in the given pair that has the stronger conjugate base is to be stated.

Concept introduction: An acid is the substance that has the ability to donate a proton in the chemical reaction and base is a substance that accepts a proton. The species that do not possess hydrogen ions and formed from an acid are known as the conjugate base. The major factors that contribute to the acidic strength are inductive effect and polarity.

Answer to Problem 19.37P

The compound benzoic acid has lower pKa value and cyclohexylmethanol forms a strong conjugate base.

Explanation of Solution

The given compounds are,

Organic Chemistry -Study Guide / Solution Manual (Custom), Chapter 19, Problem 19.37P , additional homework tip  1

Figure.1

The strength of an acid depends upon the stability of conjugate base. Stable is the conjugate base, higher is the acidity of acid. The anion formed in benzoic acid is resonance stabilized and the negative charge is delocalized on two highly electronegative oxygen atom. Thus, the conjugate base formed by the benzoic acid is more stable than that formed by cyclohexyl methanol. The compounds which have lower pKa value and the compound which is a strong conjugate base are shown below.

Organic Chemistry -Study Guide / Solution Manual (Custom), Chapter 19, Problem 19.37P , additional homework tip  2

Figure 2

The resonance stabilization of benzoic acid is shown below.

Organic Chemistry -Study Guide / Solution Manual (Custom), Chapter 19, Problem 19.37P , additional homework tip  3

Figure 3

Therefore, the compound benzoic acid has lower pKa value and cyclohexylmethanol forms a strong conjugate base.

Conclusion

The compound benzoic acid has lower pKa value and cyclohexylmethanol forms a strong conjugate base.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation: The compound in the given pair that has lower pKa is to be predicted. The compound in the given pair that has the stronger conjugate base is to be stated.

Concept introduction: An acid is the substance that has the ability to donate a proton in the chemical reaction and base is a substance that accepts a proton. The species that do not possess hydrogen ions and formed from an acid are known as the conjugate base. The major factors that contribute to the acidic strength are inductive effect and polarity.

Answer to Problem 19.37P

The compound 2- fluoroacetic acid has lower pKa value and 2- chloroacetic acid forms a strong conjugate base.

Explanation of Solution

The given compounds are ClCH2COOH and FCH2COOH.

The electron withdrawing groups increase the acidic strength of the compound. Fluorine is more electronegative than chlorine. Due to this, the acidic strength of 2- fluoroacetic acid is higher as compared to the acidic strength of 2- chloroacetic acid.

The pKa value is inversely related to the acidic strength of the compound. The strong acids produce weak conjugate bases. The compounds which have lower pKa value and the compound which is a strong conjugate base are shown below.

Organic Chemistry -Study Guide / Solution Manual (Custom), Chapter 19, Problem 19.37P , additional homework tip  4

Figure 4

Therefore, the compound 2- fluoroacetic acid has lower pKa value and 2- chloroacetic acid forms a strong conjugate base.

Conclusion

The compound 2- fluoroacetic acid has lower pKa value and 2- chloroacetic acid forms a strong conjugate base.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation: The compound in the given pair that has lower pKa is to be predicted. The compound in the given pair that has the stronger conjugate base is to be stated.

Concept introduction: An acid is the substance that has the ability to donate a proton in the chemical reaction and base is a substance that accepts a proton. The species that do not possess hydrogen ions and formed from an acid are known as the conjugate base. The major factors that contribute to the acidic strength are inductive effect and polarity.

Answer to Problem 19.37P

The compound 4- chlorobenzoic acid has lower pKa value and 4- methylbenzoic acid forms a strong conjugate base.

Explanation of Solution

The given compounds are shown below.

Organic Chemistry -Study Guide / Solution Manual (Custom), Chapter 19, Problem 19.37P , additional homework tip  5

Figure 5

The electron withdrawing groups increase the acidic strength of the compound. Chlorine is electron withdrawing group, whereas methyl is electron donating group. Due to this, the acidic strength of 4- chlorobenzoic acid is higher as compared to the acidic strength of 4- methylbenzoic acid.

The pKa value is inversely related to the acidic strength of the compound. The strong acids produce weak conjugate bases. The compounds which have lower pKa value and the compound which is a strong conjugate base are shown below.

Organic Chemistry -Study Guide / Solution Manual (Custom), Chapter 19, Problem 19.37P , additional homework tip  6

Figure 6

Therefore, the compound 4- chlorobenzoic acid has lower pKa value and 4- methylbenzoic acid forms a strong conjugate base.

Conclusion

The compound 4- chlorobenzoic acid has lower pKa value and 4- methylbenzoic acid forms a strong conjugate base.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation: The compound in the given pair that has lower pKa is to be predicted. The compound in the given pair that has the stronger conjugate base is to be stated.

Concept introduction: An acid is the substance that has the ability to donate a proton in the chemical reaction and base is a substance that accepts a proton. The species that do not possess hydrogen ions and formed from an acid are known as conjugate base. The major factors that contribute to the acidic strength are pKa value, inductive effect and polarity.

Answer to Problem 19.37P

The compound 2- cyanoacetic acid has lower pKa value and acetic acid generates a strong conjugate base.

Explanation of Solution

The given compounds are shown below.

Organic Chemistry -Study Guide / Solution Manual (Custom), Chapter 19, Problem 19.37P , additional homework tip  7

Figure 7

The electron withdrawing groups increase the acidic strength of the compound. Cyano is an electron withdrawing group. Due to this, the acidic strength of 2- cyanoacetic acid is higher as compared to the acidic strength of acetic acid.

The pKa value is inversely related to the acidic strength of the compound. The strong acids produce weak conjugate bases. The compounds which have lower pKa value and the compound which is the strong conjugate base are shown below.

Organic Chemistry -Study Guide / Solution Manual (Custom), Chapter 19, Problem 19.37P , additional homework tip  8

Figure 8

Therefore, the compound 2- cyanoacetic acid has lower pKa value and acetic acid generates strong conjugate base.

Conclusion

The compound 2- cyanoacetic acid has lower pKa value and acetic acid produces strong conjugate base.

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Chapter 19 Solutions

Organic Chemistry -Study Guide / Solution Manual (Custom)

Ch. 19 - Prob. 19.11PCh. 19 - Draw the products of each acid-base reaction.Ch. 19 - Problem 19.14 Given the values in Appendix A,...Ch. 19 - Problem 19.15 Rank the labeled protons in...Ch. 19 - Problem 19.16 Match each of the following values ...Ch. 19 - Rank the compounds in each group in order of...Ch. 19 - Rank the compounds in each group in order of...Ch. 19 - Prob. 19.18PCh. 19 - Which of the following pairs of compounds can be...Ch. 19 - Problem 19.21 Two other commonly used sulfonic...Ch. 19 - Problem 19.22 Draw both enantiomers of each amino...Ch. 19 - Problem 19.23 Explain why amino acids, unlike most...Ch. 19 - Problem 19.24 Draw the positively charged,...Ch. 19 - Prob. 19.24PCh. 19 - Problem 19.26 Explain why the of the group of...Ch. 19 - Answer each question for A and B depicted in the...Ch. 19 - Prob. 19.27PCh. 19 - Give the IUPAC name for each compound. a....Ch. 19 - Prob. 19.29PCh. 19 - Draw the structures and give the IUPAC names for...Ch. 19 - Prob. 19.31PCh. 19 - Rank the compounds in each group in order of...Ch. 19 - 19.33 Draw the organic products formed in each...Ch. 19 - 19.34 Identify the lettered compounds in each...Ch. 19 - 19.35 Using the table in Appendix A, determine...Ch. 19 - Draw the products of each acid-base reaction, and...Ch. 19 - Which compound in each pair has the lower pKa?...Ch. 19 - 19.38 Rank the compounds in each group in order of...Ch. 19 - Rank the compounds in each group in order of...Ch. 19 - 19.40 Match the values to the appropriate...Ch. 19 - Prob. 19.41PCh. 19 - 19.42 Which carboxylic acid has the lower ,...Ch. 19 - Prob. 19.43PCh. 19 - 19.44 Explain the following statement. Although...Ch. 19 - Prob. 19.45PCh. 19 - 19.46 Explain why the of compound A is lower than...Ch. 19 - 19.47 Rank the following compounds in order of...Ch. 19 - Explain the following result. Acetic acid...Ch. 19 - 19.50 Draw all resonance structures of the...Ch. 19 - As we will see in Chapter 23, CH bonds are...Ch. 19 - Prob. 19.51PCh. 19 - The pKa of acetamide (CH3CONH2) is 16. Draw the...Ch. 19 - 19.54 Write out the steps needed to separate...Ch. 19 - Prob. 19.54PCh. 19 - Can octane and octan -1- ol be separated using an...Ch. 19 - 19.57 Identify each compound from its spectral...Ch. 19 - 19.58 Use the NMR and IR spectra given below to...Ch. 19 - 19.59 An unknown compound (molecular formula )...Ch. 19 - 19.60 Propose a structure for (molecular formula...Ch. 19 - Prob. 19.60PCh. 19 - 19.61 Match the data to the appropriate...Ch. 19 - Prob. 19.62PCh. 19 - Prob. 19.63PCh. 19 - Prob. 19.64PCh. 19 - 19.65 For each amino acid ,draw its neutral,...Ch. 19 - Calculate the isoelectric point for each amino...Ch. 19 - 19.67 Lysine and tryptophan are two amino acids...Ch. 19 - Prob. 19.68PCh. 19 - Prob. 19.69PCh. 19 - Prob. 19.70PCh. 19 - Prob. 19.71PCh. 19 - 19.71 Hydroxy butanedioic acid occurs naturally in...Ch. 19 - 19.72 Although it was initially sold as a rat...
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