The reason corresponding to the fact that by using one or two equivalents of NaH results in different products in the given reactions is to be explained. Concept introduction: Sodium hydride is a strong base. It abstracts a proton and forms carbanion. The carbanion acts as a nucleophile and attacks on the electrophilic centre of alkyl halide .

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Answer 1

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Chapter 19, Problem 19.70P

Interpretation Introduction

Interpretation: The reason corresponding to the fact that by using one or two equivalents of NaH results in different products in the given reactions is to be explained.

Concept introduction: Sodium hydride is a strong base. It abstracts a proton and forms carbanion. The carbanion acts as a nucleophile and attacks on the electrophilic centre of alkyl halide.

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Explain why using one or two equivalents of NaH results in different products in the following reactions.

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Answer 2

Question

Chapter 19, Problem 19.70P

Interpretation Introduction

Interpretation: The reason corresponding to the fact that by using one or two equivalents of NaH results in different products in the given reactions is to be explained.

Concept introduction: Sodium hydride is a strong base. It abstracts a proton and forms carbanion. The carbanion acts as a nucleophile and attacks on the electrophilic centre of alkyl halide.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 19, Problem 19.70P

Interpretation Introduction

Interpretation: The reason corresponding to the fact that by using one or two equivalents of NaH results in different products in the given reactions is to be explained.

Concept introduction: Sodium hydride is a strong base. It abstracts a proton and forms carbanion. The carbanion acts as a nucleophile and attacks on the electrophilic centre of alkyl halide.

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Answer 4

Question

Chapter 19, Problem 19.70P

Interpretation Introduction

Interpretation: The reason corresponding to the fact that by using one or two equivalents of NaH results in different products in the given reactions is to be explained.

Concept introduction: Sodium hydride is a strong base. It abstracts a proton and forms carbanion. The carbanion acts as a nucleophile and attacks on the electrophilic centre of alkyl halide.

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Answer 5

Chapter 19, Problem 19.70P

Interpretation Introduction

Interpretation: The reason corresponding to the fact that by using one or two equivalents of NaH results in different products in the given reactions is to be explained.

Concept introduction: Sodium hydride is a strong base. It abstracts a proton and forms carbanion. The carbanion acts as a nucleophile and attacks on the electrophilic centre of alkyl halide.

Answer 6

Chapter 19, Problem 19.70P

Interpretation Introduction

Interpretation: The reason corresponding to the fact that by using one or two equivalents of NaH results in different products in the given reactions is to be explained.

Concept introduction: Sodium hydride is a strong base. It abstracts a proton and forms carbanion. The carbanion acts as a nucleophile and attacks on the electrophilic centre of alkyl halide.

Answer 7

Chapter 19, Problem 19.70P

Interpretation Introduction

Interpretation: The reason corresponding to the fact that by using one or two equivalents of NaH results in different products in the given reactions is to be explained.

Concept introduction: Sodium hydride is a strong base. It abstracts a proton and forms carbanion. The carbanion acts as a nucleophile and attacks on the electrophilic centre of alkyl halide.

Answer 8

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Answer 11

Ch. 19 - Give the IUPAC name for each compound.Ch. 19 - Problem 19.2 Give the structure corresponding to...Ch. 19 - Problem 19.3 Draw the structure corresponding to...Ch. 19 - Prob. 19.4P Ch. 19 - Prob. 19.5P Ch. 19 - Rank the following compounds in order of...Ch. 19 - Explain how you could use IR spectroscopy to...Ch. 19 - Identify the structure of a compound of molecular...Ch. 19 - Problem 19.9 How many tetrahedral stereogenic...Ch. 19 - What alcohol can be oxidized to each carboxylic...

Solution Summary: The author explains that using one or two equivalents of NaH results in different products in the given reactions.

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