Bundle: Physical Chemistry, 2nd + Student Solutions Manual
2nd Edition
ISBN: 9781285257594
Author: David W. Ball
Publisher: Cengage Learning
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Question
Chapter 19, Problem 19.46E
Interpretation Introduction
Interpretation:
The collision frequency, number of collisions per molecule, and the total number of collisions in a sample of ozone is to be calculated.
Concept introduction:
The average collision rate is given by the formula,
Where,
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Students have asked these similar questions
Select from the following which steps are involved in the natural production of ozone in the stratosphere. (You may
select multiple if needed)
O 3 02 (g)
→ 2 03 (g) + photon3 0;(g) –20:(g) + photon
O O2 (g) + O (g) + M
→ O3 (g) + M+heato,g) + O(g) - M→ 0,(g) + M+heat
0 0 (g) + 0 (g)+0 (g)
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D 02 (g) + photon → 2O (g)02(3) + photon →2013)
O 02 (g) + 0 (g) + photon
→ O3 (g)0(g) -O)+ photon
Calculate the collision frequency for (a) a molecule in a sample of oxygen at 1.00 atm pressure and 25°C, and (b) a molecule of hydrogen in a region of interstellar space where the number density is 1.0 × 1010 molecules per cubic meter and the temperature is 30 K. Take the diameter of O2 to be 2.92 × 10-10 m and that of H2 to be 2.34 × 10-10 m.
The degradation of CF3CH2F (an HFC) by OH radicals in the troposphere is first order in each reactant and has a rate constant of k = 1.6 * 108 M-1s-1 at 4 °C. If the tropospheric concentrations of OH and CF3CH2F are 8.1 * 105 and 6.3 * 108 molecules>cm3, respectively, what is the rate of reaction at this temperature in M>s?
Chapter 19 Solutions
Bundle: Physical Chemistry, 2nd + Student Solutions Manual
Ch. 19 - Prob. 19.1ECh. 19 - What is the kinetic energy of a single atom of...Ch. 19 - Prob. 19.3ECh. 19 - One mole of Ne atoms confined to a volume of 10.0L...Ch. 19 - Prob. 19.5ECh. 19 - Prob. 19.6ECh. 19 - Prob. 19.7ECh. 19 - Prob. 19.8ECh. 19 - Prob. 19.9ECh. 19 - Prob. 19.10E
Ch. 19 - Prob. 19.11ECh. 19 - Interstellar space can be considered as having...Ch. 19 - Prob. 19.13ECh. 19 - SF6 is a gas at room temperature, 295K. What is...Ch. 19 - Prob. 19.15ECh. 19 - Prob. 19.16ECh. 19 - If relativistic effects were ignored, what...Ch. 19 - Prob. 19.18ECh. 19 - Prob. 19.19ECh. 19 - Prob. 19.20ECh. 19 - Prob. 19.21ECh. 19 - Prob. 19.22ECh. 19 - Prob. 19.23ECh. 19 - Prob. 19.24ECh. 19 - What is the ratio of vrms/vmostprob for any gas at...Ch. 19 - Prob. 19.26ECh. 19 - Prob. 19.27ECh. 19 - Prob. 19.28ECh. 19 - Prob. 19.29ECh. 19 - Prob. 19.30ECh. 19 - Prob. 19.31ECh. 19 - The previous exercise gives an expression for...Ch. 19 - Prob. 19.33ECh. 19 - Prob. 19.34ECh. 19 - Prob. 19.35ECh. 19 - What must the pressure be if the mean free path of...Ch. 19 - Prob. 19.37ECh. 19 - Prob. 19.38ECh. 19 - Prob. 19.39ECh. 19 - Explain why the molecular diameter for argon, at...Ch. 19 - Prob. 19.41ECh. 19 - Prob. 19.42ECh. 19 - Prob. 19.43ECh. 19 - A 1.00-mol sample of Xe gas is kept at a...Ch. 19 - Prob. 19.45ECh. 19 - Prob. 19.46ECh. 19 - Prob. 19.47ECh. 19 - Prob. 19.48ECh. 19 - Prob. 19.49ECh. 19 - Consider a gas mixture containing equal...Ch. 19 - The inverse of the collision rate, 1/z, is the...Ch. 19 - Prob. 19.52ECh. 19 - Prob. 19.53ECh. 19 - Prob. 19.54ECh. 19 - Prob. 19.55ECh. 19 - Estimate the rate at which Hg effuses out a hole...Ch. 19 - Prob. 19.57ECh. 19 - Knudsen effusion cells are used to determine vapor...Ch. 19 - Prob. 19.59ECh. 19 - Prob. 19.60ECh. 19 - Prob. 19.61ECh. 19 - Prob. 19.62ECh. 19 - Prob. 19.63ECh. 19 - Prob. 19.64ECh. 19 - Prob. 19.65ECh. 19 - Prob. 19.66ECh. 19 - Prob. 19.67ECh. 19 - Prob. 19.68ECh. 19 - Prob. 19.69ECh. 19 - Prob. 19.70ECh. 19 - Prob. 19.71ECh. 19 - Prob. 19.72ECh. 19 - Prob. 19.73E
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