Bundle: Physical Chemistry, 2nd + Student Solutions Manual
Bundle: Physical Chemistry, 2nd + Student Solutions Manual
2nd Edition
ISBN: 9781285257594
Author: David W. Ball
Publisher: Cengage Learning
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Chapter 19, Problem 19.37E
Interpretation Introduction

Interpretation:

The value of T/p that is necessary for He to have a mean free path of 130pm is to be calculated. The reason as to how it would be feasible to attain the corresponding ratio is to be stated.

Concept introduction:

The mean distance traveled by the same particle between two consecutive collisions is termed as a mean free path. The value of the mean free path of a gas depends on the pressure and temperature of the system. The mean free path of gas is represented as,

λ=kT2πd2p

Where,

T represents the temperature.

d collision diameter of a gas.

p represents the pressure.

k represents the Boltzmann constant with value 1.381×1023J/K.

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Chapter 19 Solutions

Bundle: Physical Chemistry, 2nd + Student Solutions Manual

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