Chapter 19, Problem 19.74SP

Interpretation Introduction

Interpretation:

Product formed in the reaction” should be identified

Conceptual Introduction:

Boron has atomic no. = $5$

There are two isotopes of boron

• Boron $10$ (no. of neutrons = $5$)
• Boron $11$ ( no. of neutrons = $6$)

The no. of protons in both are $5$.

Lithium has atomic no. = $3$

There are two main isotopes of lithium which are present in abundance

• Lithium 6
• Lithium 7 ( no. of neutron =4)

Both have no. of proton $3$

Solutions:
  ${}_{\text{5}}{\text{B}}^{\text{10}}{\text{ + }}_{\text{0}}{\text{n}}^{\text{1 }}\to {}_{\text{3}}{\text{Li}}^{\text{7 }}{\text{ + }}_{\text{2}}{\text{He}}^{\text{4}}$

To determine:

Balance equation

  ${}_{\text{5}}{\text{B}}^{\text{10}}{\text{ + }}_{\text{0}}{\text{n}}^{\text{1 }}\to$