Concept explainers
Cytoplasmic male sterility (CMS) in plants has been exploited to produce hybrid seeds (see Experimental Insight
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Genetic Analysis: An Integrated Approach (2nd Edition)
- Suppose a species of tulip has three alleles for the gene that codes for flower color. The CR allele produces red tulips, the CB allele produces blue tulips, and the CW allele produces white tulips. Both CR and CB are dominant over CW, but CR and CB are incompletely dominant with each other, so CRCB heterozygotes have purple flowers. What is the expected phenotypic ratio in the offspring of the following crosses, in the order red : blue : purple : white? Enter your answers as the most simplified ratio (e.g. 1 : 2 : 1 : 1 instead of 2 : 4 : 2 : 2). Enter 0 if none of the offspring from a cross will be a particular color. CRCB × CBCW _____ red : ______blue : ______purple : ______white CRCB × CRCW - _______red : _____blue : _____purple : _____white CRCW × CBCW - _____red : _____blue : _____purple : _____white CRCB × CRCB - red : blue : purple : whitearrow_forwardIn a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. What is the gene order of these linked genes?arrow_forwardA homozygous strain of corn that produces yellow kernels is crossed with another homozygous strain that produces purple kernels. When the F1 are interbred, 197 of the F2 are yellow and 153 are prurple. Give the genotypes of the yellow and purple F2 and propose a genetic model that explains the inheritance of these kernel colors in corn.arrow_forward
- In the fruit fly, recessive mutations in either of two independently assorting genes, brown and purple, prevent the synthesis of red pigment in the eyes. Thus, homozygotes for either of these mutations have brownish-purple eyes. However, heterozygotes for both of these mutations have dark red, that is, wild-type eyes. If such double heterozygotes are intercrossed, what kinds of progeny will be produced, and in what proportions?arrow_forwardIn mice, the trait for high cholesterol is specified by a dominant allele designated HC, whereas the wild-type allele for normal cholesterol levels is designated hc. Black fur is specified by a recessive allele designated bl, whereas the wild-type allele which gives brown fur is designated BL. The genes for both of these traits are 30cM apart on the same autosome. A brown female (#1) with high cholesterol is mated to a black male (#2) with normal cholesterol. The progeny from this cross include a brown male (#3) with high cholesterol and a black female (#4) with normal cholesterol. What is the probability that the black mouse in the progeny of the first cross will also have high cholesterol?arrow_forwardA cross between fruit files with genotypes Aa Bb × aa bb produces the following progeny: 10 Aa Bb 40 Aa bb 40 aa Bb 10 aa bb Were the parental alleles in the coupling or repulsion configuration? Briefly explainarrow_forward
- The genes for tall vine D and yellow seed G, are dominant over their respective alleles for dwarf d and green g. What phenotypes are expected from each of the following crosses? Include phenotypic and genotypic ratio. Use Punnet square to show the ff. Crosses. a. Heterozygous tall, homozygous yellow X Homozygous Tall, heterozygous yellow. b. Homozygous Dwarf, heterozygous yellow X Heterozygous tall, homozygous greenarrow_forwardIn the pearl-millet plant, color is determined by three alleles at a single locus: Rp1 (red), Rp2 (purple), and rp (green). Red is dominant over purple and green, and purple is dominant over green (Rp1 > Rp2 > rp). Give the expected phenotypes and ratios of offspring produced by the following crosses. a. Rp1/ Rp2 × Rp1/ rp b. Rp1/ rp × Rp2/ rp c. Rp1/ Rp2 × Rp1/ Rp2 d. Rp2/ rp × rp/ rp e. rp/ rp × Rp1/ Rp2arrow_forwardIn Drosophila, a cross was made between a yellow-bodied male with vestigial wings and a wild-type (WT) female(brown body and normal wings). The F1 generation consisted of WT males and WT females. The F1 males and females were crossed, and the F2 progeny consisted of 16 yellow males with vestigial wings, 48 yellow males with WT wings, 15 brown males with vestigial wings, 49 WT males, 31 brown females with vestigial wings, and 97 WT females. Based on these results, explain the inheritance of the two genes (i.e. autosomal or sex-linked, dominant or recessive).arrow_forward
- Given the following pathway on the image: G and H are dominant alleles of the two independently assorting genes that produce an enzyme that catalyzes the conversion of one pigment to another, and g and h are recessive alleles that are non-functional. A true-breeding blue plant is crossed with a white plant of genotype ggHH. The F1s are allowed to self-mate. 1. What proportions would you expect in the F2 progeny? 2. Which is the epistatic allele?arrow_forwardOne particularly useful feature of the Hardy-Weinberg equation is that it allows us to estimate the frequency of heterozygotes for recessive genetic diseases, assuming that Hardy-Weinberg equilibrium exists. As an example, let’s consider cystic fibrosis, which is a human genetic disease involving a gene that encodes a chloride transporter. Persons with this disorder have an irregularity in salt and water balance. One of the symptoms is thick mucus in the lungs that can contribute to repeated lung infections. In populations of Northern European descent, the frequency of affected individuals is approximately 1 in 2500. Because this is a recessive disorder, affected individuals are homozygotes. Assuming that the population is in Hardy-Weinberg equilibrium, what is the frequency of individuals who are heterozygous carriers?arrow_forwardPhenotypically wild-type F1 female Drosophila, whose mothers had light eyes (lt) and fathers had straw (stw) bristles, produced the following offspring when crossed to homozygous light eyed, straw bristled males: Phenotype Number light-straw 140 wild-type 160 light 360 straw 340 Total 1000 Compute the map distance between the light and straw loci. Group of answer choices 70 map units 3 map units 7 map units 0.03 map units 30 map unitsarrow_forward
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