INTRO CHEM + MASTERING W/ETEXT
INTRO CHEM + MASTERING W/ETEXT
8th Edition
ISBN: 9781323688113
Author: CORWIN
Publisher: PEARSON
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Chapter 19, Problem 36E
Interpretation Introduction

(a)

Interpretation:

A balanced equation for the reaction CHCCH3+O2 is to be stated.

Concept introduction:

The reaction of hydrocarbon in the presence of oxygen to give carbon dioxide and water is known as combustion reaction. Complete combustion of any hydrocarbons always gives oxide of carbon and hydrogen. The reason for this is that hydrocarbons consist of hydrogen and carbon.

Expert Solution
Check Mark

Answer to Problem 36E

A balanced equation for reaction CHCCH3+O2 is shown below.

CHCCH3+4O23CO2+2H2O

Explanation of Solution

The given reaction is a combustion reaction. Complete combustion of any hydrocarbons always gives carbon dioxide and water as final product. The alkenes react with oxygen forms carbon dioxide and water. The corresponding reaction is shown below.

CHCCH3+O2CO2+H2O

In the above reaction, the number of carbon atoms on the reactant side is three and on the product side is one. The number of hydrogen atoms on the reactant side is four and on the product side are two. Therefore, the number of carbon and hydrogen atoms is balanced as shown below.

CHCCH3+O23CO2+2H2O

Now, the number of oxygen atoms on the reactant side is two and on the product side are eight. Therefore, the number of oxygen is balanced as shown below.

CHCCH3+4O23CO2+2H2O

Therefore, the balanced equation for the reaction CHCCH3+O2 is shown below.

CHCCH3+4O23CO2+2H2O

Conclusion

A balanced equation for the reaction CHCCH3+O2 is shown below.

CHCCH3+4O23CO2+2H2O

Interpretation Introduction

(b)

Interpretation:

A balanced equation for the reaction CH3CCH+2H2 is to be stated.

Concept introduction:

The reaction of hydrocarbon in the presence of oxygen to give carbon dioxide and water is known as combustion reaction. Complete combustion of any hydrocarbons always gives oxide of carbon and hydrogen. The reason for this is that hydrocarbons consist of hydrogen and carbon.

Expert Solution
Check Mark

Answer to Problem 36E

A balanced equation for the reaction CH3CCH+2H2 is shown below.

CH3CCH+2H2CH3CH2CH3

Explanation of Solution

The reaction of alkenes with hydrogen gives alkanes as the final product. This reaction is known as reduction reaction. The reaction of propyne with hydrogen is shown below.

CH3CCH+2H2CH3CH2CH3

In the above reaction, the number of carbon and hydrogen atoms is same on the both sides. Therefore, the above reaction is balanced. The balanced equation for the reaction CH3CCH+2H2 is shown below.

CH3CH=CH2+H2CH3CH2CH3

Conclusion

A balanced equation for the reaction CH3CCH+2H2 is shown below.

CH3CCH+2H2CH3CH2CH3

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Chapter 19 Solutions

INTRO CHEM + MASTERING W/ETEXT

Ch. 19 - Prob. 4KTCh. 19 - Prob. 5KTCh. 19 - Prob. 6KTCh. 19 - Prob. 7KTCh. 19 - Prob. 8KTCh. 19 - Prob. 9KTCh. 19 - Prob. 10KTCh. 19 - Prob. 11KTCh. 19 - Prob. 12KTCh. 19 - Prob. 13KTCh. 19 - Prob. 14KTCh. 19 - Prob. 15KTCh. 19 - Prob. 16KTCh. 19 - Prob. 17KTCh. 19 - Prob. 18KTCh. 19 - Prob. 19KTCh. 19 - Prob. 20KTCh. 19 - Prob. 21KTCh. 19 - Prob. 22KTCh. 19 - Prob. 23KTCh. 19 - Prob. 24KTCh. 19 - Prob. 1ECh. 19 - Prob. 2ECh. 19 - Prob. 3ECh. 19 - Prob. 4ECh. 19 - Prob. 5ECh. 19 - Prob. 6ECh. 19 - Prob. 7ECh. 19 - Prob. 8ECh. 19 - Prob. 9ECh. 19 - Prob. 10ECh. 19 - Prob. 11ECh. 19 - Prob. 12ECh. 19 - Prob. 13ECh. 19 - Prob. 14ECh. 19 - Prob. 15ECh. 19 - Prob. 16ECh. 19 - Prob. 17ECh. 19 - Prob. 18ECh. 19 - Prob. 19ECh. 19 - Prob. 20ECh. 19 - Prob. 21ECh. 19 - Prob. 22ECh. 19 - Prob. 23ECh. 19 - Prob. 24ECh. 19 - Prob. 25ECh. 19 - Prob. 26ECh. 19 - Prob. 27ECh. 19 - Prob. 28ECh. 19 - Prob. 29ECh. 19 - Prob. 30ECh. 19 - Prob. 31ECh. 19 - Prob. 32ECh. 19 - Prob. 33ECh. 19 - Prob. 34ECh. 19 - Prob. 35ECh. 19 - Prob. 36ECh. 19 - Prob. 37ECh. 19 - Prob. 38ECh. 19 - Prob. 39ECh. 19 - Prob. 40ECh. 19 - Prob. 41ECh. 19 - Prob. 42ECh. 19 - Prob. 43ECh. 19 - Prob. 44ECh. 19 - Prob. 45ECh. 19 - Prob. 46ECh. 19 - Prob. 47ECh. 19 - Prob. 48ECh. 19 - Prob. 49ECh. 19 - Prob. 50ECh. 19 - Prob. 51ECh. 19 - Prob. 52ECh. 19 - Prob. 53ECh. 19 - Prob. 54ECh. 19 - Prob. 55ECh. 19 - Prob. 56ECh. 19 - Prob. 57ECh. 19 - Prob. 58ECh. 19 - Prob. 59ECh. 19 - Prob. 60ECh. 19 - Prob. 61ECh. 19 - Prob. 62ECh. 19 - Prob. 63ECh. 19 - Prob. 64ECh. 19 - Prob. 65ECh. 19 - Prob. 66ECh. 19 - Prob. 67ECh. 19 - Prob. 68ECh. 19 - Prob. 69ECh. 19 - Prob. 70ECh. 19 - Prob. 71ECh. 19 - Prob. 72ECh. 19 - Prob. 73ECh. 19 - Prob. 74ECh. 19 - Prob. 75ECh. 19 - Prob. 76ECh. 19 - Prob. 77ECh. 19 - Prob. 78ECh. 19 - Prob. 79ECh. 19 - Prob. 80ECh. 19 - Prob. 81ECh. 19 - Prob. 82ECh. 19 - Prob. 83ECh. 19 - Prob. 84ECh. 19 - Prob. 85ECh. 19 - Prob. 86ECh. 19 - Prob. 1STCh. 19 - Prob. 2STCh. 19 - Prob. 3STCh. 19 - Prob. 4STCh. 19 - Prob. 5STCh. 19 - Prob. 6STCh. 19 - Prob. 7STCh. 19 - Prob. 8STCh. 19 - Prob. 9STCh. 19 - Prob. 10STCh. 19 - Prob. 11STCh. 19 - Prob. 12STCh. 19 - Prob. 13STCh. 19 - Prob. 14STCh. 19 - Prob. 15STCh. 19 - Prob. 16STCh. 19 - Prob. 17STCh. 19 - Prob. 18ST
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